y+ 1/2 nhân 1/3= 3/4
giúp mình nha các bạn ui
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a = |2x-1/3|-7/4
Do |2x-1/3| \(\ge\) 0
|2x-1/3|-7/4 \(\ge\) 7/4
Dấu = xảy ra <=> 2x-1/3=0. =>. x= 1/6
b 1/3|x-2|+2|3-1/2 y|+4
Do |x-2| \(\ge\) 0
|3-1/2y| \(\ge\) 0
=> 1/3|x-2|+2|3-1/2 y|+4 \(\ge\) 4
Dấu = xảy ra <=>\(\left\{{}\begin{matrix}x-2=0\\3-\dfrac{1}{2}y=0\end{matrix}\right.\)
<=>\(\left\{{}\begin{matrix}x=2\\y=6\end{matrix}\right.\)
a: Ta có: \(\left|2x-\dfrac{1}{3}\right|\ge0\forall x\)
\(\Leftrightarrow\left|2x-\dfrac{1}{3}\right|-\dfrac{7}{4}\ge-\dfrac{7}{4}\forall x\)
Dấu '=' xảy ra khi \(x=\dfrac{1}{6}\)
b: Ta có: \(\dfrac{1}{3}\left|x-2\right|\ge0\forall x\)
\(2\left|3-\dfrac{1}{2}y\right|\ge0\forall y\)
Do đó: \(\dfrac{1}{3}\left|x-2\right|+2\left|3-\dfrac{1}{2}y\right|\ge0\forall x,y\)
\(\Leftrightarrow\left|x-2\right|\cdot\dfrac{1}{3}+\left|3-\dfrac{1}{2}y\right|\cdot2+4\ge4\forall x,y\)
Dấu '=' xảy ra khi x=2 và y=6
(y - 2/5) x 1/2 =1
y - 2/5 =1:1/2
y-2/5 = 1x2/1
y-2/5 =2
y =2+2/5
y =2/1 +2/5
y =10/5+2/5
y = 12/5
\(\dfrac{3}{4}:\left(2\dfrac{4}{9}\right)-\left|-3x+2\dfrac{2}{3}\right|=\dfrac{3}{4}\)
\(\Leftrightarrow\left|-3x+\dfrac{8}{3}\right|=\dfrac{3}{4}-\dfrac{3}{4}\cdot\dfrac{9}{22}\)
\(\Leftrightarrow\left|3x-\dfrac{8}{3}\right|=\dfrac{3}{4}-\dfrac{27}{88}=\dfrac{39}{88}\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-\dfrac{8}{3}=\dfrac{39}{88}\\3x-\dfrac{8}{3}=-\dfrac{39}{88}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{821}{792}\\x=\dfrac{587}{792}\end{matrix}\right.\)
a) ( 1/2-1/3-1/6).(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10
0.(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10
0+3/4.x = 9/10
3/4.x = 9/10
x = 9/10: 3/4
x = 6/5
b) x + ( 3/1.3+3/3.5+...+3/13.15) = 11/5
x + 3/2. ( 1-1/3 + 1/3 - 1/5 + ...+ 1/13 - 1/15) = 11/5
x + 3/2. ( 1-1/15) = 11/5
x + 3/2.14/15 = 11/5
x + 7/5 = 11/5
x = 11/5 - 7/5
x = 4/5
Ta có: A = 1.2.3 + 2.3.4 + 3.4.5 + ... + 18.19.20
=> 4A = 4(1.2.3 + 2.3.4 + 3.4.5 + ... + 18.19.20)
=> 4A = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 +...... +18.19.20.4
=> 4A = 1.2.3.4 + 2.3.4(5 - 1) + 3.4.5.(6 - 2) +..... +18.19.20.(21 - 17)
=> 4A = 1.2.3.4 + 2.3.4.5 - 2.3.4 + 3.4.5.6 - 2.3.4.5 + ..... + 17.18.19.20 - 17.18.19.20
=> 4A =18.19.20
=> 4A = 6840
=> A = 1710
Đặt A=1.2.3+2.3.4+3.4.5+4.5.6+...+18.19.20
4A=(1.2.3+2.3.4+3.4.5+4.5.6+...+18.19.20)4
4A=1.2.3(4-0)+2.3.4(5-1)+3.4.5(6-2)+4.5.6(7-3)+...+18.19.20.(21-17)
4A=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+4.5.6.7-3.4.5.6+...+ 18.19.20.21-17.18.19.20
=>A =18.19.20.21
=>A+18.19.20.21/4
=> A=35910
\(y+\frac{1}{2}\cdot\frac{1}{3}=\frac{3}{4}\)
\(y+\frac{1}{6}=\frac{3}{4}\)
\(y=\frac{3}{4}-\frac{1}{6}\)
\(y=\frac{7}{12}\)
\(y\)\(+\)\(\frac{1}{2}\)X \(\frac{1}{3}\)\(=\)\(\frac{3}{4}\)
\(y\)\(+\)\(\frac{1}{6}\) \(=\)\(\frac{3}{4}\)
\(y\) \(=\)\(\frac{7}{12}\)