4/25+x/13= 0,76
15. x +15 . 2,7= 105
giúp add cộng k
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24% + 3/4 + 0,76 + 25% + 10% x 15 + 1/10 x 85
0,24 + 0,75 + 0,76 + 0,25 + 0,1 x 15 + 0,1 x 85
= (0,24 + 0,76) + (0,75 + 0,25) + 0,1 x (15 + 85)
= 1 + 1 + 0,1 x 100
= 1 + 1 + 10
= 2 + 10
= 12
24% + \(\dfrac{3}{4}\) + 0,76 + 25% + 10% x 15 + \(\dfrac{1}{10}\) x 85
0,24 + 0,75 + 0,76 + 0,25 + 0,1 x 15 + 8,5
= (0,24 + 0,76) + (0,75 + 0,25) + (0,1 x 15 + 8,5)
= 1 + 1 + (1,5 + 8,5)
= 2 + 10
= 12
Tìm x
a,\(\frac{5}{4}x=\frac{2}{3}-1,5=\frac{2}{3}-\frac{3}{2}=\frac{4}{6}-\frac{9}{6}=\frac{-5}{6}\)
\(x=\frac{-5}{6}:\frac{5}{4}=\frac{-5}{6}.\frac{4}{5}=\frac{5.\left(-1\right).2.2}{2.3.5}=\frac{-2}{3}\)
b, \(\frac{2}{7}x-\frac{3}{2}x=\frac{-21}{4}.\frac{2}{7}=\frac{-3}{2}\)
\(x.\left(\frac{2}{7}-\frac{3}{2}\right)=\frac{-3}{2}\)
\(x.\frac{-17}{14}=\frac{-3}{2}\)
\(x=\frac{-3}{2}:\frac{-17}{14}=\frac{-3}{2}.\frac{14}{-17}=\frac{21}{17}\)
a) \(25-\left(25-x\right)=12+\left(42-65\right)\)
\(25-\left(25-x\right)=12+\left(-23\right)\)
\(25-\left(25-x\right)=-11\)
\(25-x=25-\left(-11\right)\)
\(25-x=36\)
\(x=25-36\)
\(x=-11\)
Làm 2 câu dài cho bạn nhá! Mấy câu ngắn tương tự!
a, \(25-\left(25-x\right)=12+\left(42-65\right)\)
\(\Rightarrow25-25+x=12+42-65\)
\(\Rightarrow x=-11\)
b, \(215+\left(-38\right)-54+90-\left(-48+x\right)=0\)
\(\Rightarrow215-38-54+90+48-x=0\)
\(\Rightarrow x=261\)
m, \(\left|x\right|-5=12\)
\(\Rightarrow\left|x\right|=17\Rightarrow\left\{{}\begin{matrix}x=-17\\x=17\end{matrix}\right.\)
Chúc bạn học tốt!!!
y \(\times\) \(\dfrac{16}{64}\) + y \(\times\) \(\dfrac{25}{100}\) + y \(\times\) \(\dfrac{1}{4}\) + y \(\times\) \(\dfrac{15}{60}\) - \(\dfrac{13}{15}\) = \(\dfrac{17}{15}\)
y \(\times\) ( \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\)+ \(\dfrac{1}{4}\)) - \(\dfrac{13}{15}\) = \(\dfrac{17}{15}\)
y = \(\dfrac{17}{15}\) + \(\dfrac{13}{15}\)
y = \(\dfrac{30}{15}\)
y = 2
Cái này bằng rủ em chơi oẳn tù tì ,em ra lá còn anh ra hôn má em
\(\left(x-4\right)^{15}=25\cdot\left(x-4\right)^{13}\\ \Leftrightarrow\left(x-4\right)^{13}\left[\left(x-4\right)^2-25\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}x=4\\\left(x-4\right)^2=25\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=9\\x=-1\end{matrix}\right.\)
a) Đặt f(x)=0
\(\Leftrightarrow-5x-4=0\)
\(\Leftrightarrow-5x=4\)
hay \(x=-\frac{4}{5}\)
Vậy: \(S=\left\{-\frac{4}{5}\right\}\)
b) Đặt F(x)=0
\(\Leftrightarrow13-3x=0\)
\(\Leftrightarrow3x=13\)
hay \(x=\frac{13}{3}\)
Vậy: \(S=\left\{\frac{13}{3}\right\}\)
c) Đặt h(x)=0
\(\Leftrightarrow-15+5x=0\)
\(\Leftrightarrow5x=15\)
hay x=3
Vậy: S={3}
d) Đặt k(x)=0
\(\Leftrightarrow\frac{4}{5}x+\frac{16}{25}=0\)
\(\Leftrightarrow\frac{4}{5}x=-\frac{16}{25}\)
hay \(x=-\frac{16}{25}:\frac{4}{5}=\frac{-16}{25}\cdot\frac{5}{4}=-\frac{80}{100}=-\frac{4}{5}\)
Vậy: \(S=\left\{-\frac{4}{5}\right\}\)
`Answer:`
a. \(x+12=3\Leftrightarrow x=3-12\Leftrightarrow x=-9\)
b. \(2x-15=21\Leftrightarrow2x=21+15\Leftrightarrow2x=36\Leftrightarrow x=36:2\Leftrightarrow x=18\)
c. \(13-3x=4\Leftrightarrow-3x=4-13\Leftrightarrow-3x=-9\Leftrightarrow x=-9:-3\Leftrightarrow x=3\)
d. \(2\left(x-2\right)+4=12\Leftrightarrow2x-4+4=12\Leftrightarrow2x=12\Leftrightarrow x=12:2\Leftrightarrow x=6\)
e. \(15-3\left(x-2\right)=21\Leftrightarrow15-3x+6=21\Leftrightarrow-3x=21-15-6\Leftrightarrow-3x=0\Leftrightarrow x=0\)
g. \(25+4\left(3-x\right)=1\Leftrightarrow25+12-4x=1\Leftrightarrow37-4x=1\Leftrightarrow-4x=-36\Leftrightarrow x=9\)
h. \(3x+12=2x-4\Leftrightarrow3x-2x=-4-12\Leftrightarrow x=-16\)
i. \(14-3x=\left(-x\right)+4\Leftrightarrow-3x+x=4-14\Leftrightarrow-2x=10\Leftrightarrow x=5\)
k. \(2\left(x-2\right)+7=x-25\Leftrightarrow2x-4+7=x-25\Leftrightarrow2x-x=-25-3\Leftrightarrow x=-28\)
4/25 + x/13 =0,76
=> x/13 = 0,76 -4/25
=> x/13 = 0,6
=> x = 0,6 x 13
=> x = 7,8
\(\frac{4}{25}+\frac{x}{13}=0,76\Leftrightarrow\frac{x}{13}=\frac{19}{25}-\frac{4}{25}=\frac{3}{5}\Leftrightarrow x=\frac{3.13}{5}=\frac{39}{5}\)
\(15.x+15.2,7=105\Leftrightarrow15.\left(x+2,7\right)=105\Leftrightarrow x+2,7=7\Leftrightarrow x=7-2,7=4,3\)