tính bằng cách hợp lí nhất
giúp t vs
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a) (-125) . 4
= -500
b) (-2017) . (-2016) . 0
= 0
c) (-12) . (-11)
= 132
d) (-4) . (-8) . (-25) . (-125)
= [(-4).(-25)].[(-8).(-125)]
= 100.1000
= 100000
e) (-2).(-5).(-7)
= [(-2).(-5)].(-7)
= 10.(-7)
= -70
a: \(\left(-125\right)\cdot4=-\left(125\cdot4\right)=-500\)
b: \(\left(-2017\right)\cdot\left(-2016\right)\cdot0=0\cdot2016\cdot2017=0\)
c: \(\left(-12\right)\cdot\left(-11\right)=12\cdot11=12\cdot10+12=120+12=132\)
d: \(\left(-4\right)\cdot\left(-8\right)\cdot\left(-25\right)\cdot\left(-125\right)\)
\(=4\cdot8\cdot25\cdot125\)
\(=4\cdot25\cdot8\cdot125\)
\(=100\cdot1000=100000\)
e: \(\left(-2\right)\cdot\left(-5\right)\cdot\left(-7\right)\)
\(=-7\cdot2\cdot5\)
\(=-7\cdot10=-70\)
\(\dfrac{5}{7}\).\(\dfrac{-3}{11}\)-\(\dfrac{5}{7}\).\(\dfrac{8}{11}\)+1\(\dfrac{5}{7}\)
= \(\dfrac{5}{7}\).(\(\dfrac{-3}{11}\) - \(\dfrac{8}{11}\)) + 1\(\dfrac{5}{7}\)
= \(\dfrac{5}{7}\). -1 + 1\(\dfrac{5}{7}\)
= \(\dfrac{-5}{7}\) +1\(\dfrac{5}{7}\)
= -1
\(12,25+\left(-21,37\right)-\left(14,67-21,75\right)\)
\(=12,25-21,37-14,67+21,75\)
\(=12,25+21,75-21,37-14,63-0,04\)
\(=34-36-0,04\)
= -2-0,04=-2,04
120:{54-[50:2.(3^2-2.4)]}
= 120:{ 54-[25.(9-8)]}
= 120:{54-[25.1]}
= 120:{54-25}
= 120:29
=\(\dfrac{120}{29}\)
e: \(=\dfrac{2^{10}\cdot3^9-2^9\cdot3^8}{2^{10}\cdot3^8}=\dfrac{2^9\cdot3^8\left(2\cdot3-1\right)}{2^{10}\cdot3^8}=\dfrac{5}{2}\)
g: \(=125+\dfrac{3}{5}-97-\dfrac{2}{3}+97+\dfrac{2}{5}-125-\dfrac{1}{3}=0\)
\(\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{35}+...+\dfrac{1}{323}\\ =\dfrac{1}{2}\times\left(\dfrac{2}{1\times3}+\dfrac{2}{3\times5}+\dfrac{2}{5\times7}+...+\dfrac{2}{17\times19}\right)\\=\dfrac{1}{2}\times\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{17}-\dfrac{1}{19}\right)\\ =\dfrac{1}{2}\times\left(\dfrac{1}{1}-\dfrac{1}{19}\right)\\ =\dfrac{1}{2}\times\dfrac{18}{19}=\dfrac{9}{19}\)
đề bài đây:
\(\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{35}+...+\dfrac{1}{323}\)
h: \(\left[\left(-4\right)\cdot\left(-9\right)-6\right]\left[\left(-12\right)-\left(-7\right)\right]\)
\(=\left(36-6\right)\left(-12+7\right)\)
\(=-5\cdot30=-150\)
k: \(125\cdot\left(-24\right)+24\cdot225\)
\(=24\cdot\left(-125\right)+24\cdot225\)
\(=24\left(225-125\right)\)
\(=24\cdot100=2400\)
m: \(\left(-4\right)\cdot13\cdot\left(-250\right)\)
\(=13\cdot4\cdot250\)
\(=13\cdot1000=13000\)
o: \(-43\left(1-296\right)-296\cdot43\)
\(=-43\cdot1+43\cdot296-43\cdot296\)
\(=-43\cdot1=-43\)