tính:
2400- (60-2x) (40-2x)
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\(\frac{1}{2x^2+10x+12}+\frac{1}{2x^2+14x+24}+\frac{1}{2x^2+18x+40}+\frac{1}{2x^2+22x+60}=\frac{1}{8}\)
<=> \(\frac{1}{2x^2+6x+4x+12}+\frac{1}{2x^2+6x+8x+24}+\frac{1}{2x^2+8x+10x+40}+\frac{1}{2x^2+12x+10x+60}=\frac{1}{8}\)
<=> \(\frac{1}{2x\left(x+3\right)+4\left(x+3\right)}+\frac{1}{2x\left(x+3\right)+8\left(x+3\right)}+\frac{1}{2x\left(x+4\right)+10\left(x+4\right)}+\frac{1}{2x\left(x+6\right)+10\left(x+6\right)}=\frac{1}{8}\)
<=> \(\frac{1}{\left(x+3\right)\left(2x+4\right)}+\frac{1}{\left(x+3\right)\left(2x+8\right)}+\frac{1}{\left(x+4\right)\left(2x+10\right)}+\frac{1}{\left(x+6\right)\left(2x+10\right)}=\frac{1}{8}\)
<=> \(\frac{1}{2\left(x+2\right)\left(x+3\right)}+\frac{1}{2\left(x+3\right)\left(x+4\right)}+\frac{1}{2\left(x+4\right)\left(x+5\right)}+\frac{1}{2\left(x+5\right)\left(x+6\right)}=\frac{1}{8}\)
<=> \(\frac{1}{2}.\left[\frac{1}{\left(x+2\right)\left(x+3\right)}+\frac{1}{\left(x+3\right)\left(x+4\right)}+\frac{1}{\left(x+4\right)\left(x+5\right)}+\frac{1}{\left(x+5\right)\left(x+6\right)}\right]=\frac{1}{8}\)
<=> \(\frac{1}{x+2}-\frac{1}{x+3}+\frac{1}{x+3}-\frac{1}{x+4}+\frac{1}{x+4}-\frac{1}{x+5}+\frac{1}{x+5}-\frac{1}{x+6}=\frac{1}{8}:\frac{1}{2}\)
<=> \(\frac{1}{x+2}-\frac{1}{x+6}=\frac{1}{4}\)
<=> \(\frac{4\left(x+6\right)-4\left(x+2\right)}{4\left(x+2\right)\left(x+6\right)}=\frac{\left(x+2\right)\left(x+6\right)}{4\left(x+2\right)\left(x+6\right)}\)
<=> \(4\left(x+6\right)-4\left(x+2\right)=\left(x+2\right)\left(x+6\right)\)
<=> \(4\left(x+6-x-2\right)=x^2+8x+12\)
<=> \(4.4=x^2+8x+12\)
<=> \(x^2+8x-4=0\)
<=> ...
Đến đây bạn tự giải tiếp. Mình bấm máy 570ES PLUS II thì ra nghiệm \(x\approx0,47\).
-2x-40=(5-x)-(-15+60)
=> -2x - 40 = 5 - x + 15 +60
=> -2x - 40 = 80 - x
=> -2x + x = 80 + 40
=> -x = 120
-2x-40=(5-x)-(-15+60)
-2x - 40 = 5 - x - 45
-2x - 40 = -x - 40
-2x + x = -40 + 40
-1x = 0
x = 0
\(-2x-40=\left(5-x\right)-\left(-15+60\right)\)
\(-2x-40=5-x+15-60\)
\(-2x-40=-40-x\)
\(-2x+x=-40+40\)
\(-x=0\)
\(x=0\)
-2x-40=(5-x)-(-15+60)
-2x-40=5-x+15-60
-2x+x=5+15-60+40
-x=0
=> x=0
các bạn cho mk vài li-ke cho tròn 230 với
<=> -2x - 40 = 5-x +15-60
<=> -2x + x = 5+15-60+40
<=> -x=0
=> x=0
-2x-40=(5-x)-(-15+60)
-2x-40=5-x+15-60
-2x-40=5+15-60-x
-2x-40=-40-x
-2x=x
TH1:x=0 thì -2x0=0(chọn)
TH2:x>0 thì -2x<0 mà x>0(loại)
TH3:x<0 thì -2x>0 mà x<0(loại)
Vậy x=0
-2x-40=(5-x)-(-15+60)
=>-2x-40=5-x+15-60
=>-2x+x=5+15-60+40
=>-x=20-60+40=0
=>x=0
\(-2x-40=5-x-45\)
\(\Leftrightarrow-x=0\)
\(\Leftrightarrow x=0\)
\(-2x-40=\left(5-x\right)-\left(-15+60\right)\)
\(-2x-40=5-x+15-60\)
\(-2x+x=5+15-60+40\)
\(-x=0\Rightarrow x=0\)
-2x - 40 = (5 - x) - (-15 + 60)
-2x - 40 = (5 - x) - 45
-2x - 40 = -40 - x
-2x - x = 40 - 40
-3x = 0
x = 0
2(x - 4) - 3(x + 7) = 14
2x - 8 - 3x - 21 = 14
-x - 29 = 14
-x = 14 + 29
-x = 43
x = -43
-7(5 - x) - 2(x - 10) = 15
-35 + 7x - 2x + 20 = 15
-15 + 5x = 15
5x = 15 + 15
5x = 30
x = 6
2400 - (60 - 2x)(40 - 2x)
= 2400 - 2400 + 120x + 80x - 4x²
= -4x² + 200x