tìm số tự nhiên x biết
1+2+2 mũ 3 +2 mũ 4+....+2 mũ x+1 =1023
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NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
7 tháng 8
Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
7 tháng 8
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
20 tháng 9 2020
+) \(x^3=x^2\Leftrightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
+) \((7x-11)^3=2^5.5^2+200\)
\((7x-11)^3=2^3.2^2.5^2+2^3.5^2\)
\((7x-11)^3=2^3.5^2.(2^2+1)\)
\((7x-11)^3=2^3.5^2.5\)
\((7x-11)^3=2^3.5^3\)
\((7x-11)^3=10^3\)
\(\Rightarrow7x-11=10\)
\(7x=21\)
\(x=3\)
+) \(3+2^{x-1}=24-[4^2-(2^2-1)]\)
\(3+2^{x-1}=11\)
\(2^{x-1}=8\)
\(2^{x-1}=2^3\)
\(\Rightarrow x-1=3\)
\(x=4\)
5 tháng 8 2023
Bài 9,
62x73+36x33=36x73+36x27=36(73+27)=36x100=3600.
197-\([\)6x(5-1)2+20220\(]\):5=197-\([\)6x16+1\(]\):5=197-97:5=197-97/5=888/5.
Bài 10,
21-4x=13
=>4x=21-13=8
=>x=8:4=2.
30:(x-3)+1=45:43=42=16
=>30:(x-3)=16-1=15
=>x-3=30:15=2
=>x=2+3=5.
(x-1)3+5x6=38
=>(x-1)3+30=38
=>(x-1)3=38-30=8=23
=>x-1=2
=>x=3.
H9
HT.Phong (9A5)
CTVHS
20 tháng 7 2023
a) \(5\left(x+7\right)-10=2^3\cdot5\)
\(\Rightarrow5\left(x+7\right)-10=40\)
\(\Rightarrow5\left(x+7\right)=40+10\)
\(\Rightarrow x+7=\dfrac{50}{5}\)
\(\Rightarrow x+7=10\)
\(\Rightarrow x=10-7\)
\(\Rightarrow x=3\)
b) \(9x-2\cdot3^2=3^4\)
\(\Rightarrow9x-18=81\)
\(\Rightarrow9x=81+18\)
\(\Rightarrow9x=99\)
\(\Rightarrow x=\dfrac{99}{9}\)
\(\Rightarrow x=11\)
c) \(5^{25}\cdot5^{x-1}=5^{25}\)
\(\Rightarrow5^{x-1}=5^{25}:5^{25}\)
\(\Rightarrow5^{x-1}=1\)
\(\Rightarrow5^{x-1}=5^0\)
\(\Rightarrow x-1=0\)
\(\Rightarrow x=1\)
14 tháng 10 2018
Bo may la binh day k di hieu ashdbfgbgygygggydfsghuyfhdguuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu3
LM
1
H9
HT.Phong (9A5)
CTVHS
31 tháng 10 2023
\(A=3+3^2+....+3^{99}\)
\(3A=3^2+3^3+...+3^{100}\)
\(3A-A=3^2+3^3+...+3^{100}-3-3^2-...-3^{99}\)
\(2A=3^{100}-3\)
\(A=\dfrac{3^{100}-3}{2}\)
\(\Rightarrow2A+3=9^{2x+6}\)
\(\Rightarrow2\cdot\dfrac{3^{100}-3}{2}+3=\left(3^2\right)^{2x+6}\)
\(\Rightarrow3^{100}-3+3=3^{2\left(2x+6\right)}\)
\(\Rightarrow3^{100}=3^{4x+12}\)
\(\Rightarrow4x+12=100\)
\(\Rightarrow4x=88\)
\(\Rightarrow x=22\)
LM
0
30 tháng 9 2021
a: \(2^x=2^3\)
nên x=3
c: \(11^x=1331\)
nên x=3
d: \(2^x+4=12\)
nên \(2^x=8\)
hay x=3
Lời giải:
$1+2+2^3+2^4+2^5+...+2^{x+1}=1023$
$2^3+2^4+2^5+...+2^{x+1}=1020(1)$
$2^4+2^5+2^6+...+2^{x+2}=2040(2)$
Lấy (2) trừ (1) theo vế suy ra:
$2^{x+2}-2^3=2040-1020=1020$
$2^{x+2}=1028$
Với giá trị này sẽ không tồn tại số tự nhiên x. Bạn xem lại đề.