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X + 8 = 10
X = 10 − 8
X = 2
X + 5 = 20
X = 20 − 5
X = 15
40 + x = 68
X = 68 − 40
X = 28
\(a,\left(2\times x-40\right):10=-55\)
\(2\times x-40=-55\times10\)
\(2\times x-40=-550\)
\(2\times x=-550+40\)
\(2\times x=-510\)
\(x=-510:2\)
\(\Rightarrow x=-255\)
\(b,\left(2\times x+15\right):5=-40\)
\(2\times x+15=-40\times5\)
\(2\times x+15=-200\)
\(2\times x=-200-15\)
\(2\times x=-215\)
\(x=-215:2\)
\(\Rightarrow x=-\dfrac{215}{2}\)
\(c,\left(2\times x-72\right):8=25\)
\(2\times x-72=25\times8\)
\(2\times x-72=200\)
\(2\times x=200+72\)
\(2\times x=272\)
\(x=272:2\)
\(\Rightarrow x=136\)
tìm nghiệm của đa thức một biến:
a, x(x-5)-(x-5)*(3x+2)
b,2*(0,3x-0,5x)-0,5(3-x)
c,(x-1)-(x-2)=(-x-40-8
a. \(x\left(x-5\right)-\left(x-5\right)\left(3x+2\right)=0\)
\(\Rightarrow\left(x-5\right)\left[x-\left(3x+2\right)\right]=0\)
\(\Rightarrow\left(x-5\right)\left(x-3x-2\right)=0\)
\(\Rightarrow\left(x-5\right)\left(-2x-2\right)=0\)
\(\Rightarrow-2\left(x-5\right)\left(x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}-2\ne0\\x-5=0\\x+1=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}-2\ne0\\x=5\\x=-1\end{matrix}\right.\)
b. \(2\left(0,3x-0,5x\right)-0,5\left(3-x\right)=0\)
\(\Rightarrow-0,4x-1,5+0,5x=0\)
\(\Rightarrow0,1x-1,5=0\)
\(\Rightarrow0,1x=1,5\)
\(\Rightarrow x=\dfrac{1,5}{0,1}=15\)
c. \(\left(x-1\right)-\left(x-2\right)=\left(-x-40\right)-8\)
\(\Rightarrow x-1-x+2=-x-40-8\)
\(\Rightarrow1=-x-48\)
\(\Rightarrow1+48=-x\)
\(\Rightarrow x=-49\)
\(a.\dfrac{12+x}{42}=\dfrac{35}{42}\Leftrightarrow12+x=35\Leftrightarrow x=23\)
\(b.\dfrac{25-x}{40}=\dfrac{3}{8}\Leftrightarrow\dfrac{25-x}{40}=\dfrac{15}{40}\Leftrightarrow25-x=15\Leftrightarrow x=10\)
\(c.\dfrac{13+x}{20}=\dfrac{3}{4}\Leftrightarrow\dfrac{13+x}{20}=\dfrac{15}{20}\Leftrightarrow13+x=15\Leftrightarrow x=2\)
\(d.\dfrac{23-x}{25}=\dfrac{20}{25}\Leftrightarrow23-x=20\Leftrightarrow x=3\)
\(\dfrac{-1}{5}\le\dfrac{x}{40}\le\dfrac{-1}{8}\)
\(\Leftrightarrow\dfrac{-8}{40}\le\dfrac{x}{40}\le\dfrac{-5}{40}\)
\(\Leftrightarrow-8\le x\le-5\)
Mà x\(\in Z\)
\(\Rightarrow x\in\left\{-8;-7;-6;-5\right\}\)
Vậy ...
6 x 4 = 24 4 x 6 = 24 24 : 6 = 4 24 : 4 = 6 | 8 x 5 = 40 5 x 8 = 40 40 : 8 = 5 40 : 5 = 8 | 7 x 8 = 56 8 x 7 = 56 56 : 7 = 8 56 : 8 = 7 |
`@` `\text {Ans}`
`\downarrow`
`a,`
`(x-1954) \times 5=50`
`x-1954 = 50 \div 5`
`x-1954 = 10`
`x=10 + 1954`
`x= 1964`
`B.`
`48 - 40 \times x=8`
`40 \times x=48-8`
`40 \times x = 40`
` x=40 \div 40`
`x=1`
`C.`
`2+70 \div x = 3`
`70 \div x = 3-2`
`70 \div x = 1`
`x=70 \div 1`
`x=70`
`D. [3 \times (x+2) \div 7] \times 4=120`
`3 \times (x+2) \div 7 = 120 \div 4`
`3 \times (x+2) \div 7 =30`
`3 \times (x+2) = 30 \times 7`
`3 \times (x+2)=210`
`x+2=210 \div 3`
`x+2=70`
`x=70-2`
`x=68`
`E.`
`7,2 \div [ (0,6 \times x+8) \div 20 + 59] = 0,12?` Thiếu ngoặc bạn nhé._.
\(a,\left(x-1954\right)\times5=50\\ x-1954=50:5\\ x-1954=10\\ x=1954+10\\ x=1964\\b.48-40\times x=8\\40\times x=48-8\\40\times x=40\\ x=40:40\\ x=1 \\ c.2+70:X=3\\ 70:x=3-2\\ 70:x=1\\ x=70:1\\ x=70\\ d,\left[3\times\left(x+2\right):7\right]\times4=120\\ 3\times\left(x+2\right):7-120:4\\ 3\times\left(x+2\right):7=30\\ \left(x+2\right):7=30:3\\ \left(x+2\right):7=10\\ x+2=10\times7\\ x+2=70\\ x=70-2\\ x=68\)
a) x - 120: 30 = 40
x -40 =40
x =40+40
x =80
b) (x + 120) : 20 = 8
(x+ 120) = 8x20
x+120 =160
x = 160-120
x = 40
c) (x + 5). 3 = 300
x+5=300:3
x+5=100
x=100-5
x=95
d) x.2 + 21 : 3= 27
x.2 +7=27
x.2 = 27-7
x.2= 20
x=20:2
x=10
Bài 1:
a: \(\Leftrightarrow\dfrac{6}{7}\left(\dfrac{7}{12}x-\dfrac{14}{3}\right)=\dfrac{5}{9}-\dfrac{9}{8}=\dfrac{-41}{72}\)
\(\Leftrightarrow x\cdot\dfrac{7}{12}-\dfrac{14}{3}=-\dfrac{287}{432}\)
\(\Leftrightarrow x\cdot\dfrac{7}{12}=\dfrac{1729}{432}\)
hay \(x=\dfrac{247}{36}\)
b: \(\Leftrightarrow\dfrac{1}{5}:x=\dfrac{1}{5}+\dfrac{3}{14}-\dfrac{8}{7}=\dfrac{-51}{70}\)
hay \(x=-\dfrac{14}{51}\)
c: đề sai rồi bạn
40/-x=-8/5
\(\Rightarrow\)40/x=8/5
\(\Rightarrow\)40.5=8x
\(\Rightarrow\)200=8x
\(\Rightarrow\)8x=200
\(\Rightarrow\)x=25
Vậy x = 25
\(\frac{40}{-x}=\frac{-8}{5}\)
\(\Leftrightarrow\left(-8\right)\left(-x\right)=40.5\)
\(8x=200\)
\(x=200:8\)
\(x=25\)