a) 1/2√48+4√27-2√108 b) √(2-√5)mũ 2 - √14+6√5 (Tính, rút gọn)
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a: \(=3\cdot7\sqrt{3}+2\cdot6\sqrt{3}-4\cdot4\sqrt{3}-11\sqrt{3}\)
\(=21\sqrt{3}+12\sqrt{3}-16\sqrt{3}-11\sqrt{3}\)
\(=6\sqrt{3}\)
b: \(=\sqrt{\left(3-\sqrt{5}\right)^2}+\sqrt{\left(\sqrt{5}-1\right)^2}\)
\(=3-\sqrt{5}+\sqrt{5}-1\)
=2
c: \(=\left(4-\sqrt{3}\right)\sqrt{\left(4+\sqrt{3}\right)^2}\)
\(=\left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right)\)
=16-3
=13
a) \(5\sqrt{48}-4\sqrt{27}-2\sqrt{57}+\sqrt{108}\)
\(=20\sqrt{3}-12\sqrt{3}-2\sqrt{57}+6\sqrt{3}\)
\(=\left(20-12+6\right)\sqrt{3}-2\sqrt{57}\)
\(=14\sqrt{3}-2\sqrt{57}\)
b) \(2\sqrt{24}-2\sqrt{54}+3\sqrt{6}-\sqrt{150}\)
\(=4\sqrt{6}-6\sqrt{6}+3\sqrt{6}-5\sqrt{6}\)
\(=\left(4-6+3-5\right)\sqrt{6}\)
\(=-4\sqrt{6}\)
\(a,\)\(\frac{2^5\times3^{12}\times7^8}{2^7\times3^{10}\times7^9}=\frac{3^2\times\left(2^5\times3^{10}\times7^8\right)}{2^2\times7\times\left(2^5\times3^{10}\times7^8\right)}\)\(=\frac{3^2}{2^2\times7}=\frac{9}{28}\)
\(b,\)Tương tự
a: \(=\dfrac{1}{2}\cdot4\sqrt{3}+4\cdot3\sqrt{3}-2\cdot6\sqrt{3}\)
\(=2\sqrt{3}+12\sqrt{3}-12\sqrt{3}=2\sqrt{3}\)
b: \(=\left|2-\sqrt{5}\right|-\sqrt{\left(3+\sqrt{5}\right)^2}\)
\(=\sqrt{5}-2-3-\sqrt{5}\)
=-5