a.( 83 . 162 . 42 ) : 29
c) (26) 11 : ( 2 10 ) . 2 3
giải giúp mik nhé
nhờ giải rõ
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a. x + \(\dfrac{3}{7}\)= \(\dfrac{2}{5}:\dfrac{18}{25}=>x+\dfrac{3}{7}=\dfrac{2}{5}\)x\(\dfrac{35}{18}=>x+\dfrac{3}{7}=\dfrac{7}{9}\)
=> x = \(\dfrac{7}{9}-\dfrac{3}{7}=\dfrac{49}{63}-\dfrac{27}{63}=\dfrac{22}{63}\)
b. \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{4}{5}-\dfrac{1}{3}\)
=> \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{12}{15}-\dfrac{5}{15}=>x\) x \(\dfrac{5}{9}\)= \(\dfrac{7}{15}\)
=> x = \(\dfrac{7}{15}:\dfrac{5}{9}\)
=> x = \(\dfrac{21}{25}\)
\(a.x+\dfrac{3}{7}=\dfrac{2}{5}:\dfrac{18}{35}\\x+\dfrac{3}{7}=\dfrac{2}{5}\times\dfrac{35}{18} \\ x+\dfrac{3}{7}=\dfrac{7}{9}\\ x=\dfrac{7}{9}-\dfrac{3}{7}\\ x=\dfrac{22}{63}\)
\(b.x\times\dfrac{5}{9}=\dfrac{4}{5}-\dfrac{1}{3}\\x\times\dfrac{5}{9}=\dfrac{7}{15}\\ x=\dfrac{7}{15}:\dfrac{5}{9}\\ x= \dfrac{21}{25}\)
(26 + 53 ) +(42 -26-55-53)
=79 + ( 16 -55 - 53 )
=79 + (-39-53)
=79 -39 - 53
=40 - 53 = -13
B1:
a) \(\frac{1}{15}\)và\(6\)( Mẫu số chung (MSC) : 15)
\(\frac{1}{15}=\frac{1}{15}\)
\(6=\frac{90}{15}\)
Vậy 1/15 và 6 đc quy đồng mẫu số thành hai phân số : 1/15 và 90/15 có MSC là 15
b) tương tự
11/120 và 7/40 ( MSC:120)
\(\frac{11}{120}=\frac{11}{120}\)
\(\frac{7}{40}=\frac{21}{120}\)
viết kết luận tương tự như trên
2/
a) Ta có 10/10 = 1
Và: \(\frac{215}{253};\frac{152}{253}< 1< \frac{26}{15};\frac{26}{11}\)
Nhóm 1) \(\frac{215}{253};\frac{152}{253}\)
Ta có: 215>152 => \(\frac{152}{253}< \frac{215}{253}\)
Nhóm 2) \(\frac{26}{15};\frac{26}{11}\)
Ta có: 15>11 => \(\frac{26}{15}< \frac{26}{11}\)
Vậy: \(\frac{152}{253}< \frac{215}{253}< 1< \frac{26}{15}< \frac{26}{11}\)
Sắp xếp: \(\frac{152}{253};\frac{215}{253};\frac{10}{10};\frac{26}{15};\frac{26}{11}\)
b) Quy đồng hết lên rồi so sánh
a \(\dfrac{6}{15}+\dfrac{11}{15}=\dfrac{17}{15}\)
b \(\dfrac{22}{77}-\dfrac{14}{77}=\dfrac{8}{77}\)
c \(\dfrac{11}{13}\times\dfrac{26}{31}=11\times\dfrac{2}{31}=\dfrac{22}{31}\)
d \(\dfrac{1}{2}\times3\times\dfrac{2}{5}=\dfrac{3}{5}\)
a: \(A=\dfrac{16^5\cdot15^5}{2^{10}\cdot3^5\cdot5^4}=\dfrac{2^{20}\cdot3^5\cdot5^5}{2^{10}\cdot3^5\cdot5^4}=2^{10}\cdot5=5120\)
b: \(B=\dfrac{2^{15}\cdot3+2^{19}\cdot10}{2^{12}\cdot26}=\dfrac{2^{15}\left(3+2^4\cdot10\right)}{2^{13}\cdot13}=2^2\cdot\dfrac{163}{13}=\dfrac{652}{13}\)
\(a,\dfrac{6}{11}+6+\dfrac{5}{7}=\dfrac{42+462+55}{77}=\dfrac{559}{77}\)
\(b,\dfrac{9}{8}\times\dfrac{3}{12}:\dfrac{5}{9}=\dfrac{9}{8}\times\dfrac{3}{12}\times\dfrac{9}{5}=\dfrac{243}{480}=\dfrac{81}{160}\)
\(c,\dfrac{8}{7}:4+2=\dfrac{8}{7}\times\dfrac{1}{4}+2=\dfrac{8}{28}+2=\dfrac{2}{7}+2=\dfrac{16}{7}\)
\(d,\dfrac{3}{5}+4:\dfrac{6}{4}=\dfrac{3}{5}+4\times\dfrac{4}{6}=\dfrac{3}{5}+\dfrac{8}{3}=\dfrac{49}{15}\)
a: 78/42-4/7=13/7-4/7=9/7
100/110-56/88=10/11-7/11=3/11
75/35-11/7+21/49=15/7-11/7+3/7=7/7=1
99/72-15/40-1212/1616=11/8-3/8-3/4=1-3/4=1/4
\(1-x=\frac{29}{12}+\frac{32}{8}\)
\(\Rightarrow1-x=\frac{77}{12}\)
\(\Rightarrow x=1-\frac{77}{12}=\frac{-65}{12}\)
\(\frac{31}{8}.x-\frac{11}{4}=\frac{42}{12}.\frac{10}{8}-\frac{1}{3}\)
\(\Rightarrow\frac{31}{8}.x-\frac{11}{4}=\frac{35}{8}-\frac{1}{3}\)
\(\Rightarrow\frac{31}{8}.x-\frac{11}{4}=\frac{97}{24}\)
\(\Rightarrow\frac{31}{8}.x=\frac{97}{24}+\frac{11}{4}=\frac{163}{24}\)
\(\Rightarrow x=\frac{163}{24}:\frac{31}{8}=\frac{163}{93}\)
a) (512.256.16):512
=512.256.16:512
=(512:512).256.16
=1.256.16
=4096
con c) ra đáp án to lắm, bạn xem lại đề bài đi
a) \(\left(8^3.16^2.4^2\right):2^9=\left(2^9.2^8.2^4\right):2^9=2^{9+8+4}:2^9=2^{21}:2^9=2^{21-9}=2^{12}\)
b) \(\left(2^6\right)^{11}:\left(2^{10}\right).2^3=2^{66}:2^{10}.2^3=2^{66-10+3}=2^{59}\)