Tìm X , biết X : 0,25 - X : 0,5 = 25,2
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\(x\times\left(0,1+4+2,9+2+1\right)=25,2\)
\(10\times x=25,2\)
\(x=2,52\)
x : 10 + x : 0,25 + x : 2,19 + x : 0,5 = 25,2
x : ( 10 + 0,25 + 2,19 + 0,5) = 25,2
x : 12,94 = 25,2
x = 25,2 x 12,94
x =326,088]
\(x\times\left(0,1+4+2,9+2+1\right)=25,2\)
\(10x=25,2\)
\(x=2,52\)
\(x\times0,1+x\times4+x\times2,9+x\times2+x=25,2\)
\(x\times\left(0,1+4+2,9+2+1\right)=25,2\)
\(x\times10=25,2\)
\(x=25,2:10\)
\(x=2,52\)
tìm x mè giải thích sao :v?
\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11.7+0,8\right)\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)
\(\Leftrightarrow2x-4,36=1\)
\(\Leftrightarrow2x=5,36\)
\(\Leftrightarrow x=2,68\)
b) \(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)
Bài 1:
a)\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot42,9-11,7\cdot0,25+0,25\cdot0,8\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot\left(42,9-11,7+0,8\right)\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot32\)
\(\frac{2\cdot x-4,36}{0,125}=8\)
\(2\cdot x-4,36=8\cdot0,125\)
\(2\cdot x-4,36=1\)
\(2\cdot x=1+4,36\)
\(2\cdot x=5,36\)
\(x=\frac{5,36}{2}=2,68\)
b) \(N=\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...+\frac{1}{2005\cdot2010}\)
\(4N=\frac{4}{1\cdot5}+\frac{4}{5\cdot10}+\frac{4}{10\cdot15}+\frac{4}{15\cdot20}+...+\frac{4}{2005\cdot2010}\)
\(4N=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\)
\(4N=1-\frac{1}{2010}=\frac{2009}{2010}\)
\(N=\frac{2009}{2010}\div4=\frac{2009}{8040}\)
Bài 2:
a) ( x + 5,2 ) : 3,2 = 4,7 ( dư 0,5 )
\(x+5,2=4,7\cdot3,2+0,5\)
\(x+5,2=15,54\)
\(x=15,54-5,2=10,34\)
b)\(A=\frac{4047991-2010\cdot2009}{4050000-2011\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4050000-2009-2010\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4047991-2010\cdot2009}=1\)
Bài 3:
a) \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)
\(x\cdot\left(104,5-14,1+9,6\right)=25\)
\(x\cdot100=25\)
\(x=\frac{25}{100}=\frac{1}{4}=0,25\)
b) \(T=\frac{2009\cdot2010+2000}{2011\cdot2010-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+4020-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+2000}=1\)
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4/x=-y/6=0,5
4/x=-y/6=1/2
Ta có: 4/x=1/2.Suy ra:4.2=x
8=x
-y/6=1/2. Suy ra:-y.2=6
-y=3
y=-3
vậy x=8 , y=-3
4/x = -y/6 = 0,5
4/x = -y/6 = 1/2
y/-6 = 1/2
y. 2 = -6. 1
y. 2 = -6
y = -6 : 2
y = -3
4/x = -1/3
4. 3 = x. -1
12 = x. -1
12 : -1 - x
-12 = x
Vậy x = -12, y =-3
Chưa chắc đã đúng đâu, mk nghĩ vậy thôi
X : 0,25 - X : 0,5 = 25,2
X x 4 - X x 2 = 25,2
X x ( 4 - 2 ) =25,2
X x 2 = 25,2
X = 25,2 : 2
X 12,6
X : 0,25 - x : 0,5 = 25,2
x x 4 - X x 2 = 25,2
X x ( 4 - 2 ) = 25,2
X x 2 = 25,2
X = 25,2 : 2
X = 12,6