(3.x - 16).7 mũ 3 = 2.7
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\((3.x-2^{4} ):7^3 =2.7^{4}\)
\(=>(3.x-16):7^{3} =2.7^{4}\)
\(=>3.x-16=2.7^{4}:7^{3}\)
\(=>3.x-16=2.7^{4-3}\)
\(=>3.x-16=2.7\)
\(=>3.x-16=14\)
\(=>3.x=14+16\)
\(=>3.x=30\)
\(=>x=30:3\)
\(=>x=10\)
\(\left(3x-2^4\right):7^3=\left(2.7\right)^4\)
\(\Rightarrow\left(3x-2^4\right)=2^4.7^4.7^3\)
\(\Rightarrow3x-2^4=2^4.7^7\)
\(\Rightarrow3x=2^4.7^7+2^4\)
\(\Rightarrow3x=2^4.\left(7^7+1\right)=16\left(7^7+1\right)\)
\(\Rightarrow x=\dfrac{16\left(7^7+1\right)}{3}\)
Câu 3 :
A = 7776 . 8 - 2.243. 64
A = 62208 - 31104
A = 31104
Câu 1 :
a) \(12^5=3^5.4^5\)
b) \(20^6=4^6.5^6\)
c) \(54^3=6^3.9^3\)
Câu 2 :
a) \(3.5^{55}=3.\left(5^5\right)^{11}\)
b) \(4.3^{816}=4.\left(3^{17}\right)^{48}\)
c) \(9.8.7^{6412}=9.8.\left(7^{28}\right)^{229}\)
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\(\left(3x-2^4\right).7^3=2.7^4\)
\(\Rightarrow\left(3x-2^4\right)=2.7^4:7^3=14\)
\(\Rightarrow\)\(3x=14+16=30\)
\(\Rightarrow x=30:3=10\)
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\(\left[-\frac{1}{3}\right]^3\cdot x=\frac{1}{81}\)
\(\Leftrightarrow x=\frac{1}{81}:\left[-\frac{1}{3}\right]^3\)
\(\Leftrightarrow x=\frac{1}{81}:\left[-\frac{1}{27}\right]\)
\(\Leftrightarrow x=\frac{1}{81}\cdot(-27)=-\frac{1}{3}\)
\(\left[x-\frac{1}{2}\right]^3=\frac{1}{27}\)
\(\Leftrightarrow\left[x-\frac{1}{2}\right]^3=\left[\frac{1}{3}\right]^3\)
=> Làm nốt
Mấy bài kia cũng làm tương tự
(- \(\dfrac{1}{3}\))3.\(x\) = \(\dfrac{1}{81}\)
\(x=\dfrac{1}{81}\) : (- \(\dfrac{1}{3}\))3
\(x\) = - (\(\dfrac{1}{3}\))4 :(\(\dfrac{1}{3}\))3
\(x=-\dfrac{1}{3}\)
Vậy \(x=-\dfrac{1}{3}\)
\(\left(3\cdot x-16\right)\cdot7^3=2\cdot7\)
\(\Rightarrow3\cdot x-16=\dfrac{2\cdot7}{7^3}\)
\(\Rightarrow3\cdot x-16=\dfrac{2}{7^2}\)
\(\Rightarrow3\cdot x-16=\dfrac{2}{49}\)
\(\Rightarrow3\cdot x=\dfrac{2}{49}+16\)
\(\Rightarrow3\cdot x=\dfrac{786}{49}\)
\(\Rightarrow x=\dfrac{786}{49}:3\)
\(\Rightarrow x=\dfrac{262}{49}\)
\(\left(3x-16\right)\cdot7^3=2\cdot7\)
\(\left(3x-16\right)\cdot343=14\)
\(1029x-5488=14\)
\(1029x=14+5488=5502\)
\(x=\dfrac{5502}{1029}=\dfrac{262}{49}\)