Tính thuận tiện:
a)1 1/2 x 1 1/3 x 1 1/4 ; b)1 1/2 : 1 1/3 : 1 1/4
Mong mn giúp đỡ ak
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a)\(\dfrac{2}{3}.\dfrac{4}{5}+\dfrac{1}{3}.\dfrac{4}{5}=\left(\dfrac{2}{3}+\dfrac{1}{3}\right).\dfrac{4}{5}=1.\dfrac{4}{5}=\dfrac{4}{5}\)
b)\(\dfrac{2}{3}.\dfrac{4}{5}-\dfrac{1}{3}.\dfrac{4}{5}=\left(\dfrac{2}{3}-\dfrac{1}{3}\right).\dfrac{4}{5}=\dfrac{1}{3}.\dfrac{4}{5}=\dfrac{4}{15}\)
a) \(\dfrac{2}{3}\times\dfrac{4}{5}+\dfrac{1}{3}\times\dfrac{4}{5}=\dfrac{4}{5}\times\left(\dfrac{2}{3}+\dfrac{1}{3}\right)=\dfrac{4}{5}\times1=\dfrac{4}{5}\)
b) \(\dfrac{2}{3}\times\dfrac{4}{5}-\dfrac{1}{3}\times\dfrac{4}{5}=\dfrac{4}{5}\times\left(\dfrac{2}{3}-\dfrac{1}{3}\right)=\dfrac{4}{5}\times\dfrac{1}{3}=\dfrac{4}{15}\)
c) \(\dfrac{1}{2}:\dfrac{3}{4}+\dfrac{1}{6}:\dfrac{3}{4}=\dfrac{1}{2}\times\dfrac{4}{3}+\dfrac{1}{6}\times\dfrac{4}{3}=\dfrac{4}{3}\times\left(\dfrac{1}{2}+\dfrac{1}{6}\right)=\dfrac{4}{3}\times\dfrac{2}{3}=\dfrac{8}{9}\)
d) \(\dfrac{1}{2}:\dfrac{3}{4}-\dfrac{1}{6}:\dfrac{3}{4}=\dfrac{1}{2}\times\dfrac{4}{3}-\dfrac{1}{6}\times\dfrac{4}{3}=\dfrac{4}{3}\left(\dfrac{1}{2}-\dfrac{1}{6}\right)=\dfrac{4}{3}\times\dfrac{1}{3}=\dfrac{4}{9}\)
= 1/2 x ( 3/4 + 1/4 )
= 1/2 x 1
= 1/2
Nếu như thấy thuận tiện thì cho mình 1 nhé. Thanks
a)\(\left(1+\frac{1}{2}\right)\left(1+\frac{1}{3}\right)\left(1+\frac{1}{4}\right)=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}=\frac{3.4.5}{2.3.4}=\frac{5}{2}\)
b)\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}=\frac{1.2.3}{2.3.4}=\frac{1}{4}\)
\(A=\frac{1}{2}×\frac{3}{4}+\frac{1}{4}×\frac{1}{2}\)
\(A=\frac{1}{2}×\left(\frac{3}{4}+\frac{1}{4}\right)\)
\(A=\frac{1}{2}×\left(\frac{3+1}{4}\right)\)
\(A=\frac{1}{2}×1\)
\(A=\frac{1}{2}\)
\(B=\frac{1212}{2121}×\frac{151515}{161616}\)
\(B=\frac{1212:101}{2121:101}×\frac{151515:10101}{161616:10101}\)
\(B=\frac{12}{21}×\frac{15}{16}\)
\(B=\frac{12×15}{21×16}\)
\(B=\frac{3×4×3×5}{3×7×4×4}\)
\(B=\frac{15}{28}\)
\(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot\dfrac{4}{5}\\ =\dfrac{1}{5}\)
(1-1/2)×(1-1/3)×(1-1/4)×(1-1/5)×1-1/6=1/2×2/3×3/4×4/5×5/6=1/6
\(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)\times\left(1-\frac{1}{5}\right)=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times\frac{4}{5}=\frac{1}{5}\)
a/\(1\dfrac{1}{2}\times1\dfrac{1}{3}\times1\dfrac{1}{4}\)
\(=\dfrac{3}{2}\times\dfrac{4}{3}\times\dfrac{5}{4}\)
\(=\dfrac{5}{2}\)
b/\(1\dfrac{1}{2}:1\dfrac{1}{3}:1\dfrac{1}{4}\)
\(=\dfrac{3}{2}:\dfrac{4}{3}:\dfrac{5}{4}\)
\(=\dfrac{3}{2}\times\dfrac{3}{4}\times\dfrac{4}{5}\)
\(=\dfrac{9}{10}\)
#kễnh
a) \(=\dfrac{1\cdot2+1}{2}\cdot\dfrac{1\cdot3+1}{3}\cdot\dfrac{1\cdot4+1}{4}\)
\(=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot\dfrac{5}{4}\)
\(=\dfrac{5}{2}\)
b) \(=\dfrac{3}{2}:\dfrac{4}{3}:\dfrac{5}{4}\)
\(=\dfrac{3}{2}\cdot\dfrac{3}{4}\cdot\dfrac{4}{5}\)
\(=\dfrac{9}{10}\)