Question

[Phương Thảo Nhi]

Tính

a, B = \(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

Answer 1

[Jemmy Linh]

\(B=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{3.2^2.2^{16.2}}{11.2^{13}.2^{22}-2^{36}}=\frac{3.2^{34}}{11.2^{35}-2^{36}}=\frac{3.2^{34}}{2^{34}\left(11.2-2^2\right)}\)

\(=\frac{3}{11.2-2^2}=\frac{3}{11.2-4}=\frac{3}{22-4}=\frac{3}{18}=\frac{1}{6}\)

Answer 2

[Phương Thảo Nhi]

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