4. ( 3x -1 )3 - 52 =475
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1: Ta có: |-3x|=x+5
\(\Leftrightarrow\left[{}\begin{matrix}-3x=x+5\left(x\le0\right)\\3x=x+5\left(x>0\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-3x-x=5\\3x-x=5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}-4x=5\\2x=5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-5}{4}\left(nhận\right)\\x=\dfrac{5}{2}\left(nhận\right)\end{matrix}\right.\)
Vậy: \(S=\left\{-\dfrac{5}{4};\dfrac{5}{2}\right\}\)
2: Ta có: \(10-\left|x+1\right|=3x+5\)
\(\Leftrightarrow\left|x+1\right|=10-3x-5\)
\(\Leftrightarrow\left|x+1\right|=-3x+5\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=-3x+5\left(x\ge-1\right)\\-x-1=-3x+5\left(x< -1\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x+3x=5-1\\-x+3x=5+1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x=4\\2x=6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\left(nhận\right)\\x=3\left(loại\right)\end{matrix}\right.\)
Vậy:S={1}
1, bạn xem lại đề
2, 15(x-3) + 8x-21 = 12(x+1) +120
<=> 23x - 66 = 12x + 132
<=> 11x = 198 <=> x = 198/11
3, 10(3x+1) + 5 - 100 = 8(3x-1) - 6x - 4
<=> 30x + 10 - 95 = 18x -12
<=> 12x = 73 <=> x = 73/12
tổng 2 số là:
475 x 2 = 950
số t1 là:
(950 - 52) : 2 = 449
số t2 là
449 + 52 =501
A = \(\dfrac{1}{20}\) + \(\dfrac{2}{35}\) + \(\dfrac{3}{70}\) + \(\dfrac{4}{140}\) + \(\dfrac{5}{266}\) + \(\dfrac{6}{475}\)
A = \(\dfrac{1}{4\times5}\)+ \(\dfrac{2}{5\times7}\)+ \(\dfrac{3}{7\times10}\)+ \(\dfrac{4}{10\times14}\)+\(\dfrac{5}{14\times19}\)+\(\dfrac{6}{19\times25}\)
A = \(\dfrac{1}{4}\)-\(\dfrac{1}{5}\)+\(\dfrac{1}{5}\)-\(\dfrac{1}{7}\)+\(\dfrac{1}{7}\)-\(\dfrac{1}{10}\)+\(\dfrac{1}{10}\)+\(\dfrac{1}{10}\)-\(\dfrac{1}{14}\)+\(\dfrac{1}{14}\)-\(\dfrac{1}{19}\)+\(\dfrac{1}{19}\)-\(\dfrac{1}{25}\)
A = \(\dfrac{1}{4}\)-\(\dfrac{1}{25}\)
A = \(\dfrac{21}{100}\)
Rút gọn hết ta được :
a/ 41x - 17 = -21
=> 41x = -4 => x = 4/41
b/ 34x - 17 = 0
=> 34x = 17
=> x = 17/34 = 1/2
c/ 19x + 56 = 52
=> 19x = -4
=> x = -4/19
d/ 20x2 - 16x - 34 = 10x2 + 3x - 34
=> 10x2 - 19x = 0
=> x(10x - 19) = 0
=> x = 0
hoặc 10x - 19 = 0 => 10x = 19 => x = 19/10
Vậy x = 0 ; x = 19/10
Rút gọn hết ta được :
a/ 41x - 17 = -21
=> 41x = -4 => x = 4/41
b/ 34x - 17 = 0
=> 34x = 17
=> x = 17/34 = 1/2
c/ 19x + 56 = 52
=> 19x = -4
=> x = -4/19
d/ 20x 2 - 16x - 34 = 10x 2 + 3x - 34
=> 10x 2 - 19x = 0
=> x(10x - 19) = 0
=> x = 0 hoặc 10x - 19 = 0
=> 10x = 19
=> x = 19/10
Vậy x = 0 ; x = 19/10
`4*(3x-1)^3 -5^2=475`
`=>4*(3x-1)^3 = 475 +25`
`=>4*(3x-1)^3 = 500`
`=>(3x-1)^3=500:4`
`=>(3x-1)^3= 125`
`=> (3x-1)^3=5^3`
`=>3x-1=5`
`=>3x=5+1`
`=>3x=6`
`=>x=6/3=2`
4.(3x-1)3-52=475
4.(3x-1)3-25=475
4.(3x-1)3=475 +25
4.(3x-1)3=500
(3x-1)3=500:4
(3x-1)3=125
(3x-1)3 =53
3x-1=5
3x=5+1
3x=6
x=6/3
x=2