Tìm x 20/32 = x+9/24
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d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)
\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)
hay \(x=\dfrac{25}{372}\)
Vậy: \(x=\dfrac{25}{372}\)
e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)
\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)
f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)
\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)
\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)
\(\Leftrightarrow3x=\dfrac{1}{9}\)
hay \(x=\dfrac{1}{27}\)
g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)
\(\Leftrightarrow\dfrac{4}{3}x=2\)
hay \(x=\dfrac{3}{2}\)
Vậy: \(x=\dfrac{3}{2}\)
h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)
Vậy ...
i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)
Vậy ...
`32` phút `8` giây `xx3:4`
`= 96` phút `24` giây `:4`
`=24` phút `6` giây`
`=>C`
a, Ta có: x ∈ B(5) = {0;5;10;15;20;25;...}
Mà x < 20 => x ∈ {0;5;10;15}
b, Ta có: x ⋮ 24; x ⋮ 45 => x ∈ BC{24;45}
24 = 2 3 . 3 ; 45 = 3 2 . 5 => BCNN(24;45) = 2 3 . 3 2 . 5 = 360
=> BC(24;45) = B(360) = {0;360;720;...}
Mà 200 < x < 500 => x = 360
c, Ta có:
452 = px+32 => 420 ⋮ x
321 = qx+21 => 320 ⋮ x
=> x ∈ ƯC(420;320)
420 = 2 2 . 3 . 5 . 7
320 = 2 6 . 5
=> ƯCLN(420;320) = 20 = 2 2 . 5
=> ƯC(420;320) = Ư(20) = {1;2;4;5;10;20}
Vậy x ∈ {1;2;4;5;10;20}
a,= 32.(11+67) +78.68
32.78+78.68
78.(32+68)
78.100
= 7800
b,76.(41-20)+21.24
=76.21+21.24
=21.(76+24)
=21.100
=2100
X/7=10/14 : X la 5
4/9=x/27 : x la 12
15/24=x/32: 15/24= 5/8: vậy X= 20
Ta có:8=23
10=2.5
24=24.5
BCNN(...)=23.5=24.5=40
b)Ta có:
16=24
24=23.3
BCNN(...)=24.3=48
c)Ta có:
60=22.3.5
140=22.5.7
BCNN(...)=22.3.5.7=420
Mấy bài sau bn cứ lm như thế này nhé^^
20/32 = x + 9/24
x = 5/8 - 3/8
x = 1/4
\(\dfrac{20}{32}\)=x+\(\dfrac{9}{24}\)
=>x=\(\dfrac{20}{32}\)-\(\dfrac{9}{24}\)
=>x=\(\dfrac{20.3-9.4}{96}\)
=>x=\(\dfrac{60-36}{96}\)
==>x=\(\dfrac{24}{96}\)
=>x=\(\dfrac{1}{4}\)