tính nhanh nếu có thể
\(\left(\frac{5}{7}-\frac{7}{5}\right)-\left[\frac{1}{2}-\left(-\frac{2}{7}-\frac{1}{10}\right)\right]\)
K
Khách
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27 tháng 6 2017
\(\left(\frac{-1}{2}\right)\)+ \(\left(\frac{-1}{9}\right)\)\(-\frac{7}{18}\)\(-\left(-\frac{3}{5}\right)\)\(-\left(-\frac{2}{7}\right)\)\(+\frac{4}{35}\)+ \(\frac{1}{71}\)
=\(\frac{-9-2-7}{18}\)\(-\frac{-21-10-4}{35}\)+\(\frac{1}{71}\)
=\(\frac{-18}{18}\)\(-\frac{-35}{35}\)+\(\frac{1}{71}\)
=-1 -(-1)+\(\frac{1}{71}\)
=\(\frac{1}{71}\)
BD
27 tháng 6 2017
<=>3-1/4+2/3-5+1/3+6/5-6+7/4-3/2
<=>(3-5-6)+(-1/4+7/4)+(2/3+1/3)+6/5-3/2
<=>-14-3/2+1+6/5-3/2
<=>-13-3+6/5
<=>-16+6/5
<=>-80/5+6/5
<=>-74/5
QN
7 tháng 7 2017
\(A=3-\frac{1}{4}+\frac{2}{3}-5-\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)
\(\Rightarrow\left(3-5-6\right)+\left(-\frac{1}{4}+\frac{7}{4}\right)+\left(\frac{2}{3}+-\frac{1}{3}\right)-\frac{3}{2}+\frac{6}{5}\)
\(\Rightarrow-8+\frac{3}{2}+\frac{1}{3}-\frac{3}{2}+\frac{6}{5}=-8+\frac{1}{3}+\frac{6}{5}=-\frac{97}{15}\)
Chúc bạn may mắn nha !
26 tháng 9 2015
a) A = \(\frac{15}{7}:\left(\frac{1}{15}-\frac{7}{5}\right)-\frac{15}{7}:\left(\frac{17}{15}+\frac{11}{5}\right)=\frac{15}{7}:\frac{-20}{15}-\frac{15}{7}:\frac{50}{15}\)
A = \(\frac{15}{7}.\frac{15}{-20}-\frac{15}{7}.\frac{15}{50}=\frac{15}{7}.\left(\frac{-15}{20}-\frac{15}{50}\right)=\frac{15}{7}.\frac{-105}{100}=-\frac{9}{4}\)
b) B = \(\frac{1}{\left(-\frac{2}{3}\right)^4}.\left(-4\right)^2-1^{2016}-10\frac{1}{3}=\frac{1}{\frac{16}{81}}.16-1-10\frac{1}{3}=\frac{81}{16}.16-1-10\frac{1}{3}\)
B = \(81-1-10-\frac{1}{3}=70-\frac{1}{3}=\frac{209}{3}\)
19 tháng 3 2020
a) \(\frac{-1}{24}-\left[\frac{1}{4}-\left(\frac{1}{2}-\frac{7}{8}\right)\right]\)
= \(\frac{-1}{24}-\left[\frac{6}{24}-\left(\frac{12}{24}-\frac{21}{24}\right)\right]\)
= \(\frac{-1}{24}-\left[\frac{6}{24}-\frac{-9}{24}\right]\)
= \(\frac{-1}{24}-\frac{15}{24}\)
= \(\frac{-16}{24}\) = \(\frac{-2}{3}\)
19 tháng 3 2020
b) \(\left(\frac{5}{7}-\frac{7}{5}\right)-\left[\frac{1}{2}-\left(-\frac{2}{7}-\frac{1}{10}\right)\right]\)
= \(\left(\frac{50}{70}-\frac{98}{70}\right)-\left[\frac{35}{70}-\left(-\frac{20}{70}-\frac{7}{70}\right)\right]\)
= \(\frac{-48}{70}-\left[\frac{35}{70}-\left(-\frac{20}{70}-\frac{7}{70}\right)\right]\)
= \(\frac{-48}{70}-\left[\frac{35}{70}-\frac{-27}{70}\right]\)
= \(\frac{-48}{70}-\frac{62}{70}\)
= \(\frac{-110}{70}=\frac{-11}{7}\)