Tìm x
71+65*4 bằng ( x+140) :x+260
các anh chị giải giúp em luôn nha
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\(180-\left(x-45\right)\div2=120\)
\(\left(x-45\right)\div2=180-120\)
\(\left(x-45\right)\div2=60\)
\(x-45=60\times2\)
\(x-45=120\)
\(x=120+45\)
\(x=165\)
\(\left(2009-x\right)\div29+32=100\)
\(\left(2009-x\right)\div29=100-32\)
\(\left(2009-x\right)\div29=68\)
\(2009-x=68\times29\)
\(2009-x=1972\)
\(x=2009-1972\)
\(x=37\)
\(\left(x-2\right)\times3-270\div45=120\)
\(\left(x-2\right)\times3-6=120\)
\(\left(x-2\right)\times3=120+6\)
\(\left(x-2\right)\times3 =126\)
\(x-2=126\div3\)
\(x-2=42\)
\(x=42+2\)
\(x=44\)
\(\left(x+0,2\right)+\left(x+0,7\right)+\left(x+1,2\right)+...+\left(x+4,2\right)+\left(x+4,7\right)=65,5\)
\(\left(x+x+x+..+x+x\right)+\left(0,2+0,7+1,2+...+4,2+4,7\right)=65,5\)
\(10x+\frac{\left(0,2+4,7\right)\times10}{2}=65,5\)
\(10x+24,5=65,5\)
\(10x=65,5-24,5\)
\(10x=41\)
\(\Rightarrow x=4,1\)
1,25 x 4 - x = 2,5
5 - x = 2,5
x = 5 - 2,5
x = 2,5
Vậy x = 2,5
`A=(x^2-2)(x^2+x-1)-x(x^3+x^2-3x-2)`
`=x^4+x^3-x^2-2x^2-2x+2-x^4-x^3+3x^2+2x`
`=(x^4-x^4)+(x^3-x^3)+(3x^2-x^2-2x^2)+(2x-2x)+2`
`=2`
1. 15^x=225
<=>15^x=15^2
=>x=2
vậy....
2. x^3=27
<=>x^3=3^3
=>x=3
vậy......
3. 4.2^x-3=125
4.2^x=128
2^x=32
2^x=2^5
=>x=5
vậy.....
\(15^x=225\)
\(\Leftrightarrow15^x=15^2\)
\(\Leftrightarrow x=2\)
\(x^3=27\)
\(\Leftrightarrow x^3=3^3\)
\(\Leftrightarrow x=3\)
\(4.2^x-3=125\)
\(\Leftrightarrow4.2^x=125+3\)
\(\Leftrightarrow4.2^x=128\)
\(\Leftrightarrow2^x=128:4\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
~ Hok tốt ~
x - 7.84 = 64% x (2,8 + 3,7)
<=> x - 7.84 = 0,64 x 6.5
<=> x - 7,84 = 4,16
<=> x = 4,16 + 7,84 = 12
(x + \(\frac{1}{4}\) ) : 0,01 - (0,75x4) = 60
<=> (x + \(\frac{1}{4}\) ) x 100 - 3 =60
<=> 100x + 25 - 3 =60
<=> 100x = 38
<=> x = \(\frac{19}{50}\)
a, x - 7,84 = 64% x ( 2,8 + 3,7 )
x - 7,84 = 64% x 6,5
x - 7,84 = 41,6
x = 41,6 + 7,84
x = 49,44
b, ( x + 1/4 ) : 0,01 - ( 0,75 x 4 ) = 60
( x + 0,25 ) : 0,01 - 3 = 60
( x + 0,25 ) : 0,01 = 60 + 3
( x + 0,25 ) : 0,01 = 63
x + 0,25 = 63 x 0,01
x + 0,25 = 0,63
x = 0,63 - 0,25
x = 0,38
\(71+65\times4=\left(x+140\right):x+260\)
\(71+260=\left(x+140\right):x+260\)
\(71+260-260=\left(x+140\right):x\)
\(71=\left(x+140\right):x\)
\(71x=x+140\)
\(71x-x=140\)
\(70x=140\)
\(x=2\)
\(71+260=\frac{x+140}{x}+260\)
\(\frac{x+140}{x}=71+260-260=71\)
\(x+140=71x\)
\(x-71x=-140\)
\(-70x=-140\)
\(x=\frac{-140}{-70}=2\)
Vậy \(x=2\)