64 : 2^3
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A. 64 : 16 = 4
B. 210 : 30 = 7
C. 504 : 56 = 9
D. 115 : 23 = 5
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\(\left(\dfrac{1}{64}-\dfrac{1}{3^2}\right)\left(\dfrac{1}{64}-\dfrac{1}{4^2}\right)...\left(\dfrac{1}{64}-\dfrac{1}{64^2}\right)\)
\(=\left(\dfrac{1}{64}-\dfrac{1}{3^2}\right)\left(\dfrac{1}{64}-\dfrac{1}{4^2}\right)...\left(\dfrac{1}{64}-\dfrac{1}{8^2}\right)...\left(\dfrac{1}{64}-\dfrac{1}{64^2}\right)\)
\(=\left(\dfrac{1}{64}-\dfrac{1}{3^2}\right)\left(\dfrac{1}{64}-\dfrac{1}{4^2}\right)...0...\left(\dfrac{1}{64}-\dfrac{1}{64^2}\right)\)
\(=0\)
Vậy...
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a)Vì có nhiều số 52 nên .52x(3+7)=52x10=520
b)Vì có nhiều số 23 nên.23x(2+6+2)=23x10=230
c)Vì số 64 phép cuối ko có số nhân nên ta coi số đó là 1 nên. 64x7+64x2+64x1=64x(7+2+1)=64x10=640
d)Vì phép tính ở giữa có 2 số 48 cộng nên ta coi đó là 1 nên.48x(3+6+1)=48x10=480
nhé
a) 52 x 7 + 52 x 3
= 52 x ( 7 + 3 )
= 52 x 10
= 520
b) 23 x 2 + 6 x 23 + 23 x 2
= 23 x ( 2 + 6 + 2 )
= 23 x 10
= 230
c) 64 x 7 + 64 x 2 + 64
= 64 x 7 + 64 x 2 + 64 x 1
= 64 x ( 7 + 2 + 1 )
= 64 x 10
= 640
d) 48 x 3 + 48 + 48 x 6
= 48 x 3 + 48 x 1 + 48 x 6
= 48 x ( 3 + 1 + 6 )
= 48 x 10
= 480
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\(A=2^0+2^1+2^2+2^3+...+2^{2009}\)
\(=>2A=2^1+2^2+2^3+...+2^{2009}+2^{2010}\)
\(=>2A-A=\left(2^1+2^2+2^3+...+2^{2009}+2^{2010}\right)-\left(2^0+2^1+2^2+2^3+...+2^{2009}\right)\)
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a: \(\dfrac{x^3}{8}=\dfrac{y^3}{64}=\dfrac{z^3}{216}\)
=>\(\left(\dfrac{x}{2}\right)^3=\left(\dfrac{y}{4}\right)^3=\left(\dfrac{z}{6}\right)^3\)
=>\(\dfrac{x}{2}=\dfrac{y}{4}=\dfrac{z}{6}\)
=>\(\dfrac{x}{1}=\dfrac{y}{2}=\dfrac{z}{3}\)
Đặt \(\dfrac{x}{1}=\dfrac{y}{2}=\dfrac{z}{3}=k\)
=>x=k; y=2k; z=3k
\(x^2+y^2+z^2=14\)
=>\(k^2+4k^2+9k^2=14\)
=>\(14k^2=14\)
=>\(k^2=1\)
=>k=1 hoặc k=-1
TH1: k=1
=>\(x=k=1;y=2k=2\cdot1=2;z=3k=3\cdot1=3\)
TH2: k=-1
=>\(x=k=-1;y=2k=2\cdot\left(-1\right)=-2;z=3k=3\cdot\left(-1\right)=-3\)
b: \(\dfrac{x^3}{8}=\dfrac{y^3}{27}=\dfrac{z^3}{64}\)
=>\(\left(\dfrac{x}{2}\right)^3=\left(\dfrac{y}{3}\right)^3=\left(\dfrac{z}{4}\right)^3\)
=>\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}\)
Đặt \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}=k\)
=>x=2k; y=3k; z=4k
\(x^2+2y^2-3z^2=-650\)
=>\(\left(2k\right)^2+2\cdot\left(3k\right)^2-3\cdot\left(4k\right)^2=-650\)
=>\(4k^2+18k^2-3\cdot16k^2=-650\)
=>\(-26\cdot k^2=-650\)
=>\(k^2=25\)
=>\(\left[{}\begin{matrix}k=5\\k=-5\end{matrix}\right.\)
TH1: k=5
=>\(x=2\cdot5=10;y=3\cdot5=15;z=4\cdot5=20\)
TH2: k=-5
=>\(x=2\cdot\left(-5\right)=-10;y=3\cdot\left(-5\right)=-15;z=4\cdot\left(-5\right)=-20\)
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c) 64.7 + 36.7 = 7.(64 + 36) = 7.100 = 700
d) 3.52 - 64 : 23 = 3.25 - 64 : 8 = 75 - 8 = 67
64:2 mũ 3= 8
64 : 2³ = 64 : 8 = 8