Tìm x:
225 : (20 - 5x) = 15
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tìm x,biết
5-x-16=40+x
4x-10=15-x
15-x=4x-5
x-15=6+4x
-12+x=5x-20
7x-4=20+3x
5x-7=-21-2x
x+15=20-4x
17-x=7-6x
a)=>5x-4x=-15+20
=>x=5
vậy...
b)=>5x+x=31+5
=>6x=36
=>x=36:6
=>x=6
vậy....
a,5x-20=4x-15
=>5x=4x-15+20
=5x-4x=-15+20
=>x=5
b,5x-5=-x+31
=>5x=-x+31+5
=>5x+x=31+5
=>6x=36
=>x=6
+) 5x - 16 = 40 + x
<=> 5x - x = 16 + 40
<=> 4x = 56
<=> x = 56 : 4
<=> x= 14
+) 3x - 6 = 5x + 2
<=> 3x - 5x = 6 + 2
<=> -2x = 8
<=> x =- 4
+) x + 15 = 20 - 4x
<=> x + 4x = 20 - 15
<=> 5x = 5
<=> x= 1
+) -12 + x = 5x -20
<=> x - 5x = 12 - 20
<=> -4x = -8
<=> x= 2
a: =>x/27+1=-2/3
=>x/27=-5/3
=>x=-45
b: \(\Leftrightarrow x-4=\dfrac{2}{5}:\dfrac{20}{21}=\dfrac{2}{5}\cdot\dfrac{21}{20}=\dfrac{42}{100}=\dfrac{21}{50}\)
=>x=221/50
c: \(\Leftrightarrow x+\dfrac{2}{3}=\dfrac{4}{60}=\dfrac{1}{15}\)
=>x=1/15-2/3=1/15-10/15=-9/15=-3/5
d: \(\Leftrightarrow x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{15}{14}\cdot\dfrac{21}{20}\)
=>\(x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{3}{2}\cdot\dfrac{3}{4}=\dfrac{1}{5}-\dfrac{9}{8}=\dfrac{-37}{40}\)
=>x=-37/24
e: =>-3/7x=84/45
=>x=-196/45
f: =>11/10x=-2/3
=>x=-20/33
\(225:\left(20-5x\right)=15\)
\(\left(20-5x\right)=225:15\)
\(20-5x=15\)
\(5x=20-15\)
\(5x=5\)
\(x=5:5\)
\(x=1\)
\(225:\left(20-5x\right)=15\\ 20-5x=225:15\\ 20-5x=15\\ 5x=20-15\\ 5x=5\\ x=5:5\\ x=1\)