Quy đồng mẫu các phân thức:
1) \(\frac{1}{2a}\); \(\frac{x^2-2ax}{2ax^2}\); \(\frac{2}{x}\)
2) \(\frac{x}{a-2}\); \(\frac{5a-4}{3a^2-6a}\); \(\frac{2}{3a}\)
3) \(\frac{x}{10x-10}\); \(\frac{9x-10}{30x^2-30}\); \(\frac{1}{3x+3}\)
4) \(\frac{1}{1-a}\); \(\frac{1}{a^2+a+1}\); \(\frac{a^3+2}{a^3-1}\)
Ai làm được câu nào cũng đc nk. Mk cần gấp!!!
1)\(\frac{1}{2\text{a}}=\frac{1.\text{x^2}}{2\text{a.x}^2}=\frac{x^2}{2\text{ax}^2};\frac{2}{x}=\frac{2.2\text{a}x}{x.2\text{ax}}=\frac{4\text{ax}}{2\text{ax}^2}\)\(;\frac{x^2-2\text{ã}}{2\text{ax}^2}\)giữ nguyên
2) \(\frac{x}{a-2}=\frac{x.3\text{a}}{3\text{a}\left(a-2\right)}=\frac{3\text{ax}}{3\text{a}^2-6\text{a}};\frac{2}{3\text{a}}=\frac{2.\left(a-2\right)}{3\text{a}\left(a-2\right)}=\frac{2\text{a}-4}{3\text{a}^2-6\text{a}};\frac{5\text{a}-4}{3\text{a}^2-6\text{a}}\)giữ nguyên
3) \(\frac{x}{10\text{x}-10}=\frac{x.3\text{x}}{\left(10\text{x}-10\right).3\text{x}}=\frac{3\text{x}^2}{30\text{x}^2-30};\frac{1}{3\text{x}-3}=\frac{1.10\text{x}}{10\text{x}.\left(3\text{x}-3\right)}=\)\(\frac{10\text{x}}{30\text{x}^2-30\text{x}};\frac{9\text{x}-10}{30\text{x}^2-30\text{x}}\)giữ
4) \(\frac{1}{1-a}==\frac{-1}{a-1}=\frac{-1.\left(a^2+a+1\right)}{\left(a-1\right)\left(a^2+a+1\right)}=\frac{-a^2-a-1}{a^3-1};\frac{1}{a^2+a+1}=\frac{1.\left(a-1\right)}{\left(a-1\right)\left(a^2+a+1\right)}\)
\(=\frac{a-1}{a^3-1};\frac{a^3+2}{a^3-1}\)giữ nguyên