mở ngoặc vuông 6+(1/2)3-1/2 đóng ngoặc vuông: 3/12
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a, \(\dfrac{1}{2}\) - ( - \(\dfrac{1}{3}\) ) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= \(\dfrac{5}{6}\) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= 1 + \(\dfrac{1}{23}\)
= \(\dfrac{24}{23}\)
b, \(\dfrac{11}{24}\) - \(\dfrac{5}{41}\) + \(\dfrac{13}{24}\) + 0,5 - \(\dfrac{36}{41}\)
= (\(\dfrac{11}{24}\) + \(\dfrac{13}{24}\)) - ( \(\dfrac{5}{41}\) + \(\dfrac{36}{41}\)) + 0,5
= 1 - 1 + 0,5
= 0,5
c,\(-\dfrac{1}{12}-\left(\dfrac{1}{6}-\dfrac{1}{4}\right)\)
=\(-\dfrac{1}{12}-\left(-\dfrac{1}{12}\right)\)
=0
d, \(\dfrac{1}{6}-\left[\dfrac{1}{6}-\left(\dfrac{1}{4}+\dfrac{9}{12}\right)\right]\)
= \(\dfrac{1}{6}-\left[\dfrac{1}{6}-1\right]\)
= \(\dfrac{1}{6}-\left(-\dfrac{5}{6}\right)\)
= 1
\(\left[\frac{1}{33}+\frac{31}{333}-\left(\frac{341}{3333}\right)^2\right]\times\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
=\(\left[\frac{1}{33}+\frac{31}{333}-\left(\frac{341}{3333}\right)^2\right]\times\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)
=\(\left[\frac{1}{33}+\frac{31}{333}-\left(\frac{341}{3333}\right)^2\right]\times\left(\frac{0}{6}\right)\)
=\(\left[\frac{1}{33}+\frac{31}{333}-\left(\frac{341}{3333}\right)^2\right]\times0\)
=0
a) \(0,6+\dfrac{2}{3}=\dfrac{6}{10}+\dfrac{2}{3}=\dfrac{3}{5}+\dfrac{2}{3}=\dfrac{9}{15}+\dfrac{10}{15}=\dfrac{19}{15}\)
b) \(-\dfrac{5}{12}+0,75=-\dfrac{5}{12}+\dfrac{75}{100}=-\dfrac{5}{12}+\dfrac{3}{4}=-\dfrac{5}{12}+\dfrac{9}{12}=\dfrac{4}{12}=\dfrac{1}{3}\)
c) \(\dfrac{1}{3}-\left(-0,4\right)=\dfrac{1}{3}+\dfrac{4}{10}=\dfrac{1}{3}+\dfrac{2}{5}=\dfrac{5}{15}+\dfrac{6}{15}=\dfrac{11}{15}\)
d) \(1\dfrac{3}{5}+\dfrac{5}{6}=\dfrac{8}{5}+\dfrac{5}{6}=\dfrac{48}{40}+\dfrac{25}{30}=\dfrac{73}{30}\)
11 3/4-[65/4-41/2]+1-2/3
47/4-[65/4-41/2]+1-2/3
47/4-(-17/4)+1-2/3
16/1+1-2/3
16/1+1/1-2/3
17/1-2/3
51/3-2/3
49/3
tính bằng 2 cách
b. 106 x mở ngoặc 67 + 32 đóng ngoặc
mọi người thông cảm mình ko mở đóng ngoặc được ạ
Cách 1: 106 x (67 + 32) = 106 x 99 = 10494
Cách 2: 106 x (67 + 32) = 106 x 67 + 106 x 32 = 7102 + 3392 = 10494
đây nha
Cách1 \(106\times\left(67+34\right)\)
\(106\times67+106\times34\)
\(=7102+3604\)\(=10706\)
cách 2 \(106\times\left(67+34\right)\)
\(=106\times101=10706\)
78 x (27-16) = 78 x 11 = 858
78 x (27-16) = (78 x 27) - (78x16) = 2106 - 1248 = 858
\([\)6+(\(\dfrac{1}{2}\))3\(]\):\(\dfrac{3}{12}\)=\([\)6+\(\dfrac{1}{8}\)\(]\):\(\dfrac{1}{4}\)=\(\dfrac{49}{8}\):\(\dfrac{1}{4}\)=\(\dfrac{49}{2}\).