Giải nhanh giúp mik vs
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a) \(x-\dfrac{1}{5}=\dfrac{-2}{15}\)
\(\Rightarrow x=\dfrac{-2}{15}+\dfrac{1}{5}\)
\(\Rightarrow x=\dfrac{-2}{15}+\dfrac{3}{15}\)
\(\Rightarrow x=\dfrac{1}{15}\)
b) \(8\cdot\left(3^2+1\right)-\dfrac{2}{7}\cdot7\)
\(=8\cdot\left(9+1\right)-\dfrac{2\cdot7}{7}\)
\(=8\cdot10-2\)
\(=80-2\)
\(=78\)
Bài 5:
Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:
\(\dfrac{x}{10}=\dfrac{y}{9}=\dfrac{x-y}{10-9}=4\)
Do đó: x=40; y=36
`@` `\text {Ans}`
`\downarrow`
`j)`
\(x^{17}\div x^{12}=x^{17-12}=x^5\)
`k)`
\(x^8\div x^5=x^{8-5}=x^3\)
`r)`
\(a^5\div a^5=a^{5-5}=a^0=1\)
`l)`
\(x^4\div x=x^{4-1}=x^3\)
`m)`
\(x^7\div x^6=x^{7-6}=x\)
`n)`
\(x^9\div x^9=x^{9-9}=x^0=1\)
`o)`
\(a^{12}\div a^5=a^{12-5}=a^7\)
`p)`
\(a^8\div a^6=a^{8-6}=a^2\)
`q)`
\(a^{10}\div a^7=a^{10-7}=a^3\)
`r(2),`
\(1024\div4=2^{10}\div2^2=2^8\)
`t)`
\(512\div2^3=2^9\div2^3=2^6\)
C5:
nC2H5OH = 8,2 / 46 = 0,2 (mol)
C2H5OH + 3O2-- (t^o)-- > 2CO2 + 3H2O
VCO2 = 0,4 . 22,4 = 8,96 (l)
VO2 = 0,6.22,4=13,44 (l)
9. Has the work been done by him?
10. The boxes were opened and cigarettes were taken out by us
11. She was given a new one
12. He is proved wrong
13. We were promised higher wages
14. This is the third time we have been written to about this by them
15. We were asked to be there at 8 o'clock
16. She is being shown how to do it
\(C=1.2.3+2.3.4+........+48.49.50\)
\(\Rightarrow4C=1.2.3.4+2.3.4.4+........+48.49.50.4\)
\(=1.2.3.4+2.3.4.\left(5-1\right)+.........+48.49.50.\left(51-47\right)\)
\(=1.2.3.4+2.3.4.5-1.2.3.4+........+48.49.50.51-47.48.49.50\)
\(=48.49.50.51\)
\(\Rightarrow C=\frac{48.49.50.51}{4}=1499400\)
Ta có C = 1 x 2 x 3 + 2 x 3 x 4 + ... + 48 x 49 x 50
=> 4C = 1 x 2 x 3 x 4 + 2 x 3 x 4 x 4 + .... + 48 x 49 x 50 x 4
4C = 1 x 2 x 3 x 4 + 2 x 3 x 4 x (5 - 1)+ ... + 48 x 49 x 50 x (51 - 47)
4C = 1 x 2 x 3 x 4 + 2 x 3 x 4 x 5 - 1 x 2 x 3 x 4 + .... + 48 x 49 x 50 x 51 - 47 x 48 x 49 x 50
4C = 48 x 49 x 50 x 51
4C = 5997600
C = 5997600 : 4
C = 1499400
Vậy C = 1499400
\(a,9.\left(\dfrac{1}{3}\right)^2+\left(\dfrac{1}{7}\right)^0-1\\ =9.\dfrac{1}{9}+1-1\\ =\dfrac{9}{9}+1-1\\ =1+1-1\\ =1\\ b,7.\left(5^2-5\right)+\left(-1\right)^2\\ =7.\left(25-5\right)+1\\ =7.20+1\\ =140+1\\ =141\)
a: =9*1/9+1-1=1
b: =7*(25-5)-1=7*20-1=139