\(\frac{x}{12}-\frac{5}{6}=\frac{1}{12}\)
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WH
12 tháng 3 2018
\(-\frac{5}{9}-\left(-\frac{5}{12}\right)\)
\(=-\frac{5}{9}+\frac{5}{12}\)
\(=-\frac{5}{36}\)
*Tìm x
\(-\frac{5}{6}-x=\frac{7}{12}+\left(-\frac{1}{3}\right)\)
\(\Rightarrow-\frac{5}{6}-x=\frac{1}{4}\)
\(\Rightarrow x=-\frac{5}{6}-\frac{1}{4}\)
\(\Rightarrow x=-\frac{13}{12}\)
HN
12 tháng 3 2018
\(\frac{-5}{9}-\frac{-5}{12}\)
= \(\frac{-20}{36}-\frac{-15}{36}\)
= \(\frac{-5}{36}\)
Tìm x:
\(\frac{-5}{6}-x=\frac{7}{12}+\frac{-1}{3}\)
\(\frac{-5}{6}-x=\frac{7}{12}+\frac{-4}{12}\)
\(\frac{-5}{6}-x=\frac{1}{4}\)
\(x=\frac{-5}{6}-\frac{1}{4}\)
\(x=\frac{-10}{12}-\frac{3}{12}\)
\(x=\frac{-13}{12}\)
22 tháng 4 2016
Cau A dat thua so chung la ra
Cau B tach mau thanh h cua 2 thua so lien tiep
TT
2
10 tháng 4 2017
Nếu bạn để dài như vậy chắc chẳng ai muốn làm đâu, bạn tách ra từng phần đi
23 tháng 4 2017
\(\frac{x}{12}-\frac{5}{6}=\frac{1}{12}\)
\(\frac{x}{12}-\frac{10}{12}=\frac{1}{12}\)
\(\Rightarrow x-10=1\)
\(x=1+10\)
\(x=11\)
EC
8 tháng 9 2016
Câu 1:
a)\(\frac{3}{4}-0,25-\left[\frac{7}{3}+\left(-\frac{9}{2}\right)\right]-\frac{5}{6}\)
\(=\frac{3}{4}-\frac{1}{4}-\frac{14}{6}+\frac{27}{6}-\frac{5}{6}\)
\(=\frac{1}{2}-\frac{4}{3}\)
\(=-\frac{5}{6}\)
b)\(7+\left(\frac{7}{12}-\frac{1}{2}+3\right)-\left(\frac{1}{12}+5\right)\)
\(=7+\frac{1}{12}+3-\frac{1}{12}-5\)
\(=5\)
EC
8 tháng 9 2016
Câu 2:
\(\frac{3}{4}-\frac{5}{6}\le\frac{x}{12}< 1-\left(\frac{2}{3}-\frac{1}{4}\right)\)
\(-\frac{1}{12}\le\frac{x}{12}< 1-\frac{5}{12}\)
\(-\frac{1}{12}\le\frac{x}{12}< \frac{7}{12}\)
Vậy -1\(\le\)x<7
HH
20 tháng 9 2017
\(\dfrac{3}{7}+\dfrac{1}{2}=\dfrac{-15}{12}x+\dfrac{6}{5}x\)
\(\Leftrightarrow\)\(\dfrac{-15.5+12.6}{60}x=\dfrac{3.2+1.7}{14}\)
\(\Leftrightarrow\)\(\dfrac{-3}{60}x=\dfrac{13}{14}\)
\(\Leftrightarrow\)\(\dfrac{-1}{20}x=\dfrac{13}{14}\)
\(\Leftrightarrow\)x=-\(\dfrac{13}{14}:\dfrac{1}{20}=-\dfrac{13.20}{14}=-\dfrac{130}{7}\)
HH
20 tháng 9 2017
3(12+x)=7(x-4)
\(\Leftrightarrow\)36+3x=7x-28
\(\Leftrightarrow\)7x-3x=36+28
\(\Leftrightarrow\)4x=64
\(\Leftrightarrow\)x=16
29 tháng 6 2022
a: \(=\dfrac{3\left(\dfrac{1}{41}-\dfrac{4}{47}+\dfrac{9}{53}\right)}{4\left(\dfrac{1}{41}-\dfrac{4}{47}+\dfrac{9}{53}\right)}+\dfrac{-\dfrac{1}{4}\cdot\dfrac{-2}{3}-\dfrac{3}{4}:\dfrac{1}{6}}{\dfrac{3}{2}\cdot\left(\dfrac{-2}{3}-\dfrac{3}{4}\cdot\dfrac{-2}{3}\right)}\)
\(=\dfrac{3}{4}+\dfrac{\dfrac{2}{12}-\dfrac{9}{2}}{\dfrac{3}{2}\cdot\dfrac{-1}{6}}=\dfrac{3}{4}+\dfrac{-13}{3}:\dfrac{-3}{12}\)
\(=\dfrac{3}{4}+\dfrac{13}{3}\cdot\dfrac{12}{3}=\dfrac{3}{4}+\dfrac{156}{9}=\dfrac{217}{12}\)
b: \(A=158\left(\dfrac{12\left(1-\dfrac{1}{7}-\dfrac{1}{289}-\dfrac{1}{85}\right)}{4\left(1-\dfrac{1}{7}-\dfrac{1}{289}-\dfrac{1}{85}\right)}:\dfrac{5\left(1+\dfrac{1}{13}+\dfrac{1}{169}+\dfrac{1}{91}\right)}{6\left(1+\dfrac{1}{13}+\dfrac{1}{169}+\dfrac{1}{91}\right)}\right)\cdot\dfrac{50550505}{711711711}\)
\(=158\cdot\left(3\cdot\dfrac{6}{5}\right)\cdot\dfrac{50550505}{711711711}\)
\(\simeq40.39\)
X = 11
k mk nha
\(\frac{x}{12}-\frac{5}{6}=\frac{1}{12}\)
\(\frac{x}{12}=\frac{1}{12}+\frac{5}{6}\)
\(\frac{x}{12}=\frac{1}{12}+\frac{10}{12}=\frac{11}{12}\)
\(x=\frac{11}{12}\times12\)
\(\Rightarrow x=11\)