1.Tính nhanh : 13 x 2525 - 25 x 1313
2. Tìm X : ( 4 x X - 2 ) x ( 2024 - X ) = X
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Tính nhanh :
a) 252 - 152 = (25 + 15)(25 - 15) = 40 . 10 = 400
b) 872 + 732 - 272 - 132 = (872 - 132) + (732 - 272)
= (87 + 13)(87 - 13) + (73 + 27)(73 - 27)
= 100 . 74 + 100 . 26 = 100 . (74 + 26) = 100 . 100 = 10000
Bài 1:
a)\(\left(x+y\right)^2-\left(x-y\right)^2=\left(x+y+x-y\right)\left(x+y-x+y\right)=2x\cdot2y=2\left(x+y\right)\)
b) \(\left(3x+1\right)^2-\left(x+1\right)^2=\left(3x+1+x+1\right)\left(3x+1-x-1\right)\\ =\left(4x+2\right)\cdot2x=4x\left(2x+1\right)\)
Bài 2:
a) \(25^2-15^2=\left(25-15\right)\left(25+15\right)=10\cdot40=400\)
b) \(87^2+73^2-27^2-13^2=\left(87^2-27^2\right)+\left(73^2-13^2\right)\\ =\left(87-27\right)\left(87+27\right)+\left(73-13\right)\left(73+13\right)\)
\(=60\cdot114+60\cdot86=60\cdot\left(114+86\right)=60\cdot200=12000\)
Bài 2:
a) \(x^3-0,25\cdot x=0\)
\(\Leftrightarrow x^2\left(x-0,25\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x-0,25=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=0,25\end{array}\right.\)
b) \(x^2-10=-25\)
\(\Leftrightarrow x^2=-15\) (vô nghiệm0
c) \(4x^2-4x=-1\)
\(\Leftrightarrow4x^2-4x+1=0\)
\(\Leftrightarrow\left(2x-1\right)^2=0\)
\(\Leftrightarrow2x-1=0\Leftrightarrow x=\frac{1}{2}\)
d) \(8x^3+12x^2+6x+1=0\)
\(\Leftrightarrow\left(2x+1\right)^3=0\)
\(\Leftrightarrow2x+1=0\Leftrightarrow x=-\frac{1}{2}\)
(1-1/2) x (1-1/3) x .... x (1-1/100)
= 1/2 x 2/3 x ... x 99/100
= 1x2x...x99/2x3x..x100
= 1/ 100
a, \(\frac{3}{5}+25-\frac{1}{5}\)
\(=\left(\frac{3}{5}-\frac{1}{5}\right)+25\)
\(=\frac{2}{5}+25\)
\(=25\frac{2}{5}\)
\(=25,4\)
b, \(13.3.32,27+67,63.39\)
\(=39.32,27+67,63.39\)
\(=39\left(32,37+67,63\right)\)
\(=39.100\)
\(=3900\)
c, \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)....\left(1-\frac{1}{100}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}......\frac{99}{100}\)
\(=\frac{1}{100}\)
1:
13*2525-25*1313
=13*25*(101-101)
=0
`@` `\text {Ans}`
`\downarrow`
`1.`
`13 \times 2525 - 25 \times 1313`
`= 13 \times 101 \times 25 - 25 \times 13 \times 101`
`= 13 \times 25 \times ( 101 - 101)`
`= 13 \times 25 \times 0`
`= 0`
`2.`
`(4 \times x - 2) \times (2024 - x) = x`
`4x(2024 - x) - 2(2024 - x) - x = 0`
`4x \times 2024 - 4x \times x - [ 2 \times 2024 + 2 \times (-x) ] = 0`
`8096 - 4x \times x - (4048 - 2x) = 0`
`8096 - 4x \times x - 4048 + 2x = 0`
`4048 - x(4x + 2) = 0`
`x(4x + 2) = 4048`
Bạn xem lại đề ;-; mình nghĩ lp 5 chưa hc mấy dạng ntnay ;-;.