rut gon
\(\dfrac{21^2\cdot14\cdot125}{35^2\cdot125}\)
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Ta có :
\(\frac{21^2.14.125}{35^3.6}=\frac{3^2.7^2.2.7.5^3}{5^3.7^3.2.3}=\frac{2.3^2.5^3.7^3}{2.3.5^3.7^3}=\frac{3}{1}=3\)
Vậy \(\frac{21^2.14.125}{35^3.6}=3\)
\(\frac{21^2.14.125}{35^3.6}\)= \(\frac{21^2.2.7.125}{42875.2.3}\)= \(\frac{21^2.7.125}{125.343.3}\)= \(\frac{21^2.7.125}{125.7.49.3}\)= \(\frac{21^2}{49.3}\)= \(\frac{441}{147}\)
Mình làm rồi nhưng bạn thử tính lại cho chắc nha
Chúc bạn học tốt!
\(A=\frac{4^6.3^4.9^5}{6^{12}}=\frac{\left(2^2\right)^6.3^3.\left(3^2\right)^5}{6^{12}}\)
\(=\frac{2^{12}.3^3.3^{10}}{6^{12}}=3^{13}.3^{12}=3^{25}\)
\(A=\frac{4^6.3^4.9^5}{6^{12}}\)
\(A=\frac{2^6.2^6.3^4.3^5.3^5}{2^{12}.3^{12}}\)
\(A=\frac{3^3.3^5}{1}\)
\(A=3^8\)
\(B=\frac{21^2.14.125}{35^3.6}\)
\(B=\frac{3^2.7^2.2.7.5^3}{5^3.7^3.2.3}\)
\(B=\frac{3.1.1.1.1}{1.1.1.1}\)
\(B=3\)
\(a,=15\left(\dfrac{2121}{4343}+\dfrac{222222}{434343}\right)=15\left(\dfrac{21}{43}+\dfrac{22}{43}\right)=15\cdot1=15\)
Ta có :
Tử số :
( 2005 + 1 ) . 125 + 1000
2005 . 125 + 125 + 1000
2005 . 125 +1125
Mẫu Số :
( 125 + 1 ) . 2005 - 888
125 . 2005 + 2005 - 888
125 . 2005 + 1117
Ta có phân số : \(\dfrac{2005\cdot125+1125}{125\cdot2005+1117}\) = \(\dfrac{1125}{1117}\)
=\(\frac{5^{62}.8^{15}.2^{15}}{8^{19}.5^{63}}\)= \(\frac{2^{15}}{8^4.5}\)= \(\frac{2^{15}}{2^{12}.5}\)= \(\frac{8}{5}\)
\(B=\frac{\left(2^4.3\right)^3.\left(2.5^2\right)^5}{\left(2^6\right)^2.\left(5^3\right)^2.\left(2.3.5\right)^3}\)
\(B=\frac{2^{12}.3^3.2^5.5^{10}}{2^{12}.5^6.2^3.3^3.5^3}\)
\(B=\frac{2^{12}.3^3.2^3.2^2.5^9.5}{2^{12}.5^9.2^3.3^3}\)
\(B=2^2.5=20\)
Vay B = 20
`@` `\text {Ans}`
`\downarrow`
\(\dfrac{21^2\cdot14\cdot125}{35^2\cdot125}\)
`=`\(\dfrac{3^2\cdot7^2\cdot2\cdot7\cdot5^2}{5^2\cdot7^2\cdot5^2}\)
`=`\(\dfrac{3^2\cdot2\cdot7\cdot5^2\cdot7^2}{5^2\cdot5^2\cdot7^2}\)
`=`\(\dfrac{3^2\cdot2\cdot7}{5^2}=\dfrac{126}{25}\)