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ta có
3737 . 43 - 4343 . 37 = ( 3700 + 37) . 43 - (4300+43) . 37
= 3700 . 43 + 37 .43 - 4300 . 37 + 43 . 37
= 43 . 37 . ( 3700 . 43 - 4300 . 37)
= 1591 . (159100 - 159100)
= 1591 . 0
= 0
vậy \(\frac{3737.43-4343.37}{2+4+6+....+100}\)= 0
đap số 0
\(D=\frac{3737.43-4343.37}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{37.101.43-4343.37}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{37.4343-4343.37}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{4343.\left(37-37\right)}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{4343.0}{2+4+6+...+100}\)
\(\Rightarrow D=\frac{0}{2+4+6+...+100}\)
\(\Rightarrow D=0\)
Vậy D = 0
\(D=\frac{37.101.43-43.101.37}{2+4+6+..+100}=\frac{0}{2+4+...+100}=0\)
`(3737.43-4343.37)/(2+4+...+100)`
`= (101.37.43-101.43.37)/(2+4+...+100)`
`=0/(2+4+...+100) = 0`
B=\(\frac{3737.43-4343.37}{2+4+6+..+100}=\frac{101.37.43-101.43.37}{2+4+6+...+100}\)=\(\frac{101\left(37.43-43.37\right)}{2+4+6+...100}=\frac{0}{2+4+6+...+100}\)=0
C=\(\frac{101+100+99+...+2+1}{101-100+99-98+...+3-2+1}=\frac{\left(101+1\right)101:2}{\left(101-100\right)+\left(99-98\right)+...+\left(3-2\right)+1}\)(dưới mẫu có 51 số 1)
=\(\frac{5151}{51}\)=101
a)48.45+55.48=(45+55).48=100.48=4800
b)57.37+57.23+57.40=57.(23+37+40)=57.100=5700
c)25.5.4.17.2=(25.4).(5.17.2)=100.170=17000
d)127.45+55.127-27.100=127.(45+55)-(27.100)=127.100-27.100=(127-27).100=100.100=10000
e)543+165+457+35=(543+457)+(165+35)=1000+200=1200
g)13.58.4+32.6.2+52.10=(52.58)+(52.32)+52.10=52.(58+32+10)=52.100=5200
h)25.5.4.17.2=(25.4).(17.2.5)=100.170=17000
k)(3737.43-4343.37):(2+4+6+...+100)=(37.101.43-43.101.37):(2+4+6+...+100)=0.(2+4+6+...+100)=0
i)1+5+9+...+29+33+37=(1+37)+(5+33)+...=190
a=4800
b=5700
c=17000
d=10000
e=1200
...
phần còn lại bạn tự làm nhé
ngắn gọn
a)
\(118\times45+55\times148-18\times100\)
\(=118\times\left(45+55\right)-18\times100\)
\(=118\times100-18\times100\)
\(=100\times\left(118-18\right)\)
\(=100\times100\)
\(=10000\)
b)
\(127\times45+55\times127-27\times100\)
\(=127\times\left(45+55\right)-27\times100\)
\(=127\times100-27\times100\)
\(=100\times\left(127-27\right)\)
\(=100\times100\)
\(=10000\)
c)
\(86\times63+27\times86+86\times10\)
\(=86\times\left(63+27+10\right)\)
\(=86\times100\)
\(=8600\)
d)
\(57\times37+57\times23+57\times40\)
\(=57\times\left(37+23+40\right)\)
\(=57\times100\)
\(=5700\)
h)
\(\left(3737\times43-4343\times37\right)\div\left(92+4+6+...+100\right)\)
\(=\left(37\times101\times43-43\times101\times37\right)\div\left(2+4+6+...+100\right)\)
\(=0\div\left(2+4+6+...+100\right)\)
\(=0\)
e)
\(543+165+437+35\)
\(=\left(543+437\right)+\left(165+35\right)\)
\(=980+200\)
\(=1180\)
g)
\(13\times58\times4+32\times26\times2+52\times10\)
\(=52\times58+32\times52+52\times10\)
\(=52\times\left(58+32+10\right)\)
\(=52\times100\)
\(=5200\)
i)
Số số hạng là \(\left(37-1\right)\div4+1=10\)
Tổng là \(\left(37+1\right)\times10\div2=190\)