\(\left(1-\frac{1}{21}\right).\left(1-\frac{1}{28}\right).\left(1-\frac{1}{36}\right).........\left(1-\frac{1}{1026}\right)\)
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\(=\frac{-2}{3}\cdot\frac{-5}{6}\cdot\frac{-9}{10}\cdot\cdot\cdot\cdot\frac{-35}{36}\)
\(=\frac{-4}{6}\cdot\frac{-10}{12}\cdot\frac{-18}{20}\cdot\cdot\cdot\cdot\frac{-70}{72}\)
\(=\frac{-1.4}{2.3}\cdot\frac{-2.5}{3.4}\cdot\frac{-3.6}{4.5}\cdot\cdot\cdot\cdot\frac{-7.10}{8.9}\)
\(=\frac{\left(-1\right).\left(-2\right).\left(-3\right)...\left(-7\right)}{2.3.4....8}\cdot\frac{4.5.6....10}{3.4.5....9}\)
\(=\frac{\left(-1\right).2.3...7}{2.3.4....8}\cdot\frac{10}{3}\)
\(=\frac{-1}{8}\cdot\frac{10}{3}=\frac{-5}{12}\)
\(A=\left(1-\frac{1}{21}\right).\left(1-\frac{1}{28}\right).\left(1-\frac{1}{36}\right).....\left(1-\frac{1}{1326}\right)\)
\(A=\frac{20}{21}.\frac{27}{28}.\frac{35}{36}......\frac{1325}{1326}\)
\(A=\frac{5.8}{6.7}.\frac{6.9}{7.8}.\frac{7.10}{8.9}.....\frac{50.53}{51.52}\)
\(A=\frac{5.\left(6.7.....50\right)}{\left(6.7.....50\right).51}.\frac{53.\left(8.9.10.....52\right)}{7.\left(8.9.10.......52\right)}\)
\(A=\frac{5}{51}.\frac{53}{7}=\frac{265}{357}\)
khó z mik ko giai duoc k cho mik ik mik kb cho nha
Đặt \(A=\left(1-\frac{1}{21}\right).\left(1-\frac{1}{28}\right).\left(1-\frac{1}{36}\right).....\left(1-\frac{1}{1026}\right)\)
\(A=\frac{20}{21}.\frac{27}{28}.\frac{35}{36}....\frac{1025}{1026}=\frac{40}{42}.\frac{54}{56}.\frac{70}{72}....\frac{2050}{2052}\)
\(A=\frac{40.54.70.......2050}{42.56.72.....2052}=\frac{5.8.6.9.7.10.....a.\left(a+3\right)}{6.7.7.8.8.9....b.\left(b+1\right)}=\frac{\left(5.6.7...a\right).\left[8.9.10....\left(a+3\right)\right]}{\left(6.7.8.9...b\right).\left[7.8.9....\left(b+1\right)\right]}\)
Tôi chỉ làm đến đây thôi , đề bài sai ở phân số cuối nhé , nếu sửa đề thì thay các số vào a và b nhé