\(\frac{3}{8}x+1:\left(-3\right)=\frac{_{-1}}{24}\)
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6 tháng 3 2020
\(1\frac{1}{30}:\left(24\frac{1}{6}-24\frac{1}{5}\right)-\frac{1\frac{1}{2}-\frac{3}{4}}{4x-\frac{1}{2}}=\left(-1\frac{1}{15}\right):\left(8\frac{1}{5}-8\frac{1}{3}\right)\)
\(\Rightarrow\frac{31}{30}:\left(\frac{145}{6}-\frac{121}{5}\right)-\frac{\frac{3}{2}-\frac{3}{4}}{4x-\frac{1}{2}}=\left(\frac{-16}{15}\right):\left(\frac{41}{5}-\frac{25}{3}\right)\)
\(\Rightarrow\frac{31}{30}:\left(\frac{725}{30}-\frac{726}{30}\right)-\frac{\frac{6}{4}-\frac{3}{4}}{4x-\frac{1}{2}}=\left(\frac{-16}{15}\right):\left(\frac{123}{15}-\frac{125}{15}\right)\)
\(\Rightarrow\frac{31}{30}:\frac{-1}{30}-\frac{\frac{3}{4}}{4x-\frac{1}{2}}=\frac{-16}{15}:\frac{-2}{15}\)
\(\Rightarrow\frac{31}{30}.\frac{30}{-1}-\frac{3}{4}:\left(4x-\frac{1}{2}\right)=\frac{-16}{15}.\frac{15}{-2}\)
\(\Rightarrow\left(-31\right)-\frac{3}{4}:\left(4x-\frac{1}{2}\right)=8\)
\(\Rightarrow\frac{3}{4}:\left(4x-\frac{1}{2}\right)=\left(-31\right)-8\)
\(\Rightarrow\frac{3}{4}:\left(4x-\frac{1}{2}\right)=\left(-39\right)\)
\(\Rightarrow4x-\frac{1}{2}=\frac{3}{4}:\left(-39\right)\)
\(\Rightarrow4x-\frac{1}{2}=\frac{3}{4}.\frac{-1}{39}\)
\(\Rightarrow4x-\frac{1}{2}=\frac{-1}{52}\)
\(\Rightarrow4x=\frac{-1}{52}+\frac{1}{2}\)
\(\Rightarrow4x=\frac{-1}{52}+\frac{26}{52}\)
\(\Rightarrow4x=\frac{25}{52}\)
\(\Rightarrow x=\frac{25}{52}:4\)
\(\Rightarrow x=\frac{25}{52}.\frac{1}{4}\)
\(\Rightarrow x=\frac{25}{208}\)
Vậy \(x=\frac{25}{208}\)
Chúc bn học tốt
\(\frac{3}{8}x+\frac{-1}{3}=\frac{-1}{24}\)
\(\frac{3}{8}x=\frac{-1}{24}-\frac{-1}{3}\)
\(\frac{3}{8}x=\frac{3}{8}\)
\(x=1\)
\(\frac{3}{8}\)x+1:\(\frac{-3}{1}\)=\(\frac{-1}{24}\)
\(\frac{3}{8}\)x+1.\(\frac{-1}{3}\)=\(\frac{-1}{24}\)
\(\frac{3}{8}\)x+\(\frac{-1}{3}\)=\(\frac{-1}{24}\)
\(\frac{3}{8}\)x =\(\frac{-1}{24}\)-\(\frac{-1}{3}\)
\(\frac{3}{8}\)x =\(\frac{-1}{24}\)-\(\frac{-8}{24}\)
\(\frac{3}{8}\)x = \(\frac{7}{24}\)
x = \(\frac{7}{24}\):\(\frac{3}{8}\)
x = \(\frac{7}{24}\).\(\frac{8}{3}\)
x = \(\frac{7}{9}\)