Bài1.Tìm x biế́́́́́́t́
a)2/3+1/3(2x-1)=-5
b)25%x+2x=4
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A, \(4^{2x-6}=1\)
\(\Rightarrow4^{2x-6}=4^0\)
\(\Rightarrow2x-6=0\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
B, \(5^{2x-3}-2.5^2=5^2.3\)
\(\Rightarrow5^{2x-3}=5^2.3+2.5^2\)
\(\Rightarrow5^{2x-3}=5^2.\left(3+2\right)\)
\(\Rightarrow5^{2x-3}=5^2.5\)
\(\Rightarrow5^{2x-3}=5^3\)
\(\Rightarrow2x-3=3\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
Bài 1 :
Gọi 3 số tự nhiên cần tìm là n - 1 ; n ; n + 1 ( với n \(\in\) N* )
Theo bài ra , ta có :
[ ( n -1 )n ] + [ ( n + 1 )n ] + [ (n - 1)( n + 1 ) ] = 242
=> ( \(n^2\) - n ) + ( \(n^2\) + n ) + ( \(n^2\) + n - n - 1 ) = 242
=> \(3n^2\) - 1 = 242
=> \(3n^2\) = 243
=> \(n^2\) = 81
=> n = 9 hoặc n = -9
Mà n là số tự nhiên \(\Rightarrow\) n = 9
Vậy 3 số cần tìm là 8 ; 9 ; 10
1) \(\left|2x+5\right|\ge21\Rightarrow2x+5\ge21\)hoặc \(2x+5<-21\)<=> \(x\ge8\) hoặc \(x<-13\)
2)
a) |2x-3|>=0 => A>=0-5=-5 => Min A=-5 <=> x=3/2
b) \(\left|2x-1\right|+\left|3-2x\right|\ge\left|2x-1+3-2x\right|=\left|2\right|=2\Rightarrow B\ge2+5=7\)=> MinB=7 <=>x=1
3)
\(\left|2x-1\right|\ge0\Rightarrow-\left|2x-1\right|\le0\Leftrightarrow A\le0+7=7\Rightarrow MaxA=7\Leftrightarrow x=-\frac{1}{2}\)
b)
th1: nếu x<-3/2 => B=-2x-3+2x+2=-1
th2: nếu \(-\frac{3}{2}\le x\le-1\)=> B=2x+3+2x+2=4x+5
ta có:\(-\frac{3}{2}\le x\le-1\Rightarrow-6\le4x\le-4\Leftrightarrow-1\le4x+5\le1\Rightarrow-1\le B\le1\)
th3: nếu x>-1 => B=2x+3-2x-2=1=>
Max B=1 <=> x>-1 hoặc \(-\frac{3}{2}\le x\le-1\)
2b) Áp dụng bất đẳng thức giá trị tuyệt đối: |a| + |b| \(\ge\) |a + b|. Dấu "=" xảy ra khi tích a.b \(\ge\) 0
Ta có: B = |2x - 1| + |3 - 2x| + 5 \(\ge\) |2x - 1+3 - 2x| + 5 = |2| + 5 = 7
=> Min B = 7 khi
(2x - 1)( 3 - 2x) \(\ge\) 0 => (2x - 1)(2x - 3) \(\le\) 0
Mà 2x - 1 > 2x - 3 nên 2x - 1 \(\ge\) 0 và 2x - 3 \(\le\) 0
=> x \(\ge\) 1/2 và x \(\le\) 3/2
1)
2x.(x-2) - x.(2x+1) = 3
=> 2x2 - 4x - 2x2 - x = 3
=> (2x2 - 2x2 ) - (4x+x) = 3
=> -5x = 3
=> x = \(\dfrac{-3}{5}\)
2) (2x-1).(x-2) - (x+3).(2x-7) = 3
=> 2x2 - 4x - x + 2 - 2x2 + 7x - 6x + 21 = 3
=> (2x2 - 2x2) - (4x + 6x + x - 7x) + 2 + 21 = 3
=> -4x = -20
=> x = -20 : (-4)
=> x = 5
3) (x - 5).(-x + 4) - (x - 1).(x + 3) = -2x2
=> Bạn tách tương tự như mấy câu 2 nhé! Nếu không làm được thì bảo mình
\(a,\dfrac{3}{2}\cdot x-1=\dfrac{1}{2}x-\dfrac{3}{5}\)
\(\Rightarrow\dfrac{3}{2}x-\dfrac{1}{2}x=-\dfrac{3}{5}+1\)
\(\Rightarrow\left(\dfrac{3}{2}-\dfrac{1}{2}\right)x=-\dfrac{3}{5}+\dfrac{5}{5}\)
\(\Rightarrow x=\dfrac{2}{5}\)
\(b,\dfrac{1}{2}x+\dfrac{1}{2}\left(x-2\right)=\dfrac{3}{4}-2x\)
\(\Rightarrow\dfrac{1}{2}x+\dfrac{1}{2}x+2x-1=\dfrac{3}{4}\)
\(\Rightarrow\left(\dfrac{1}{2}+\dfrac{1}{2}+2\right)x=\dfrac{3}{4}+1\)
\(\Rightarrow3x=\dfrac{7}{4}\)
\(\Rightarrow x=\dfrac{7}{4}:3\)
\(\Rightarrow x=\dfrac{7}{12}\)
\(c,\left(x-\dfrac{1}{2}\right)-\dfrac{1}{4}=0\)
\(\Rightarrow x-\dfrac{1}{2}=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{1}{4}+\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{1}{4}+\dfrac{2}{4}\)
\(\Rightarrow x=\dfrac{3}{4}\)
\(d,4^{x-3}+1=17\)
\(\Rightarrow4^{x-3}=17-1\)
\(\Rightarrow4^{x-3}=16\)
\(\Rightarrow4^{x-3}=4^2\)
\(\Rightarrow x-3=2\)
\(\Rightarrow x=2+3\)
\(\Rightarrow x=5\)
#Toru
`3/2 x -1 =1/2x -3/5`
`=> 3/2x -1/2x = -3/5 +1`
`=> 2/2x= -3/5 + 5/5`
`=> x= 2/5`
__
`1/2x +1/2(x-2) = 3/4 -2x`
`=> 1/2x + 1/2x - 2/2 = 3/4 -2x`
`=> 1/2x +1/2x +2x = 3/4 + 1`
`=> 1/2x +1/2x + 4/2x = 3/4 +4/4`
`=> 6/2x = 7/4`
`=> x= 7/4 : 3`
`=>x=7/12`
__
`(x-1/2) -1/4=0`
`=> x-1/2=1/4`
`=> x=1/4 +1/2`
`=> x= 1/4 +2/4`
`=>x=3/4`
__
`4^(x-3) +1=17`
`=> 4^(x-3) =17-1`
`=> 4^(x-3)=16`
`=> 4^(x-3)=4^2`
`=> x-3=2`
`=>x=2+3`
`=>x=5`
a) \(5^4:\left(2x-1\right)^2=25\\ \Leftrightarrow5^4:\left(2x-1\right)^2=5^2\\ \Leftrightarrow5^4:5^2=\left(2x-1\right)^2\\ \Leftrightarrow\left[{}\begin{matrix}\left(2x-1\right)^2=5^2\\\left(2x-1\right)^2=\left(-5\right)^2\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}2x-1=5\\2x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
b) \(17^3.x=17^4\\ \Rightarrow x=17^4:17^3=17\)
c) \(\left(2x+1\right)^3:49=7\\ \Leftrightarrow\left(2x-1\right)^3:7^2=7\\ \Leftrightarrow\left(2x-1\right)^3=7.7^2=7^3\\ \Leftrightarrow2x-1=7\\ \Leftrightarrow x=4\)
a)54 : (2x - 1)2 =25
54 : (2x - 1)2 =52
(2x - 1)2 =54 : 52
(2x - 1)2 = 52
2x - 1 = 5
2x = 5+1
2x = 6
x = 6: 2
x = 3
b)173.x = 174
x = 174 : 173
x = 17
c)(2x + 1)3 : 49 =7
(2x + 1)3 = 7 . 49
(2x + 1)3 = 343
(2x + 1)3 = 73
2x +1 = 7
2x = 7- 1
2x = 6
x = 6:2
x = 3
bài 1
a)\(x^2+5x+6=\left(x+2\right)\left(x+3\right)=0\Leftrightarrow\orbr{\begin{cases}x+3=0\\x+2=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-3\\x=-2\end{cases}}}\)
a) 2/3 + 1/3(2x-1) =-5
1/3(2x-1) = -5 - 2/3
1/3(2x-1) = -17/3
2x-1 = -17/3 : 1/3
2x-1 = -17
2x = -17 + 1
2x = -16
x = -16 : 2
x = -8
b) 25% .x + 2x = 4
x .( 25%+2 ) = 4
x . 9/4 = 4
x = 4 : 9/4
x = 16/9