a,Tính giá trị biểu thức
( 23,79:7,8-6,8:17) x 3,04-2,04
b,Tìm x,biết
(20-x) x 5=40 x 1,5
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1, (30 x 5 - 24 x 4) x 32 : (30 + 20)
= 54 x 32 : 50
= 1728 : 50
= 34,56
2, (12 x 6 + 108) x 15 + 135 : 45
= 180 x 15 + 135 : 45
= 2700 + 135 : 45
= 2700 + 3
= 2703
3, 807 + 49 x (311 - 4807 : 23)
= 807 + 49 x 102
= 807 + 4998
= 5805
4 , ( 4,72 + 3,57 x 4,1 + 8,5 x 2,434) x 100
= 40,046 x 100
= 4004,6
5, (23,79 : 7,8 - 6,8 : 417) x 3,04 - 2,04
= 2,65 x 3,04 - 2,04
= 8,056 - 2,04
= 6,016
a,`7,2-x:6,5=5,7`
`x:6,5=1,5`
`x=9,75`
`232,8-x=2,56xx4,5`
`232,8-x=11,52`
`x=221,28`
`x-93,1=72,81:18`
`x-93,1=4,045`
`x=97,145`
b, `8,6-8,33:3,4=8,6-2,45=6,15`
`9,52:6,8+3,86=1,4+3,86=5,26`
`(25,46-56,42:4)+16,5xx23=(25,46-14,105)+379,5=11,355+379,5=390,855`
a,
M = 10.22 - 67 : 65
M = 10.4 - 62
M = 40 - 36
M = 4
b,
\(x\) - 20 = 5.(-10)
\(x\) - 20 = -50
\(x\) = -50 + 20
\(x\) = - 30
a)
A=\(\left(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}\right)\div\dfrac{2x}{5x-5}\)
\(\Leftrightarrow\left(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}\right)\div\dfrac{2x}{5\left(x-1\right)}\)
ĐKXĐ: \(\left\{{}\begin{matrix}x-1\ne0\\x+1\ne0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0+1\\x=0-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)
MTC: 5(x-1)(x+1)
\([\dfrac{5\left(x+1\right)\left(x+1\right)}{5\left(x-1\right)\left(x+1\right)}-\dfrac{5\left(x-1\right)\left(x-1\right)}{5\left(x-1\right)\left(x+1\right)}]\div\dfrac{2x\left(x+1\right)}{5\left(x-1\right)\left(x+1\right)}\)
\(\Rightarrow[5\left(x+1\right)\left(x+1\right)-5\left(x-1\right)\left(x-1\right)]\div2x\left(x+1\right)\)
\(\Leftrightarrow[5\left(x+1\right)^2-5\left(x-1\right)^2]\div2x^2+2x\)
\(\Leftrightarrow[5\left(x^2+2x+1\right)-5\left(x^2-2x+1\right)]\div2x^2+2x\)
\(\Leftrightarrow(5x^2+10x+5-5x^2+10x-5)\div2x^2+2x\)
\(\Leftrightarrow20x\div\left(2x^2+2x\right)\)
\(\Leftrightarrow10x+10\)
Ta có : a x 7,5 + b x 4,9 + c x 3,2 + a x 2,5 + b x 5,1 + c x 6,8
= (a x 7,5 + a x 2,5) + ( b x 4,9 + b x 5,1 ) + (c x 3,2 + c x 6,8)
= 10a + 10b + 10c
= 10(a + b + c)
= a x ( 7,5 + 2,5 ) x b x ( 4,9 + 5,1 ) x c x ( 3,2 +6,8 )
=a x 10 x b x 10 x c x 10
= ( a x b x c ) x ( 10 x 10 x 10 )
= abc x 1000
= abc000
( 23,79 : 7,8 - 6,8 : 17 ) x 3,04 - 2,04
= ( 3,05 - 0,4 ) x 3,04 - 2,04
= 2,65 x 3,04 - 2,04
= 8,056 - 2,04
= 6,016
( 20 - x ) x 5 = 40 x 1,5 = 60
20 - x = 60 : 5 = 12
x = 20 - 12 = 8