12: (x*3)=1,28+2,72 ; x=........
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=(5,44x6-2x2,72x6)x(5,44x6-2,72)
=[5,44x(6-6)]x(5,44x6-2,72)
=0x(5,44x6-2,72)
=0
Ngoặc sau em ghi không rõ nhưng không quan trọng vì ngoặc trước có kết quả = 0
Ta có:
\(\text{4/3/4+(-0,37)+1/8+(-1,28)+(-2,5)+3/1/12}\)
\(=4:4:3-0,37+1:8-1,28-2,5+3:1:12\)
\(=\frac{1}{3}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{1}{4}\)
\(=\frac{200}{600}-\frac{222}{600}+\frac{75}{600}-\frac{768}{600}-\frac{1500}{600}+\frac{150}{600}\)
\(=\frac{200-222+75-768-1500+150}{600}\)
\(=-\frac{2065}{600}\)
\(=-\frac{413}{120}\)
Bài 1:
0,5\(x\) - \(\dfrac{2}{3}\)\(x\) = \(\dfrac{7}{12}\)
\(\dfrac{1}{2}\)\(x\) - \(\dfrac{2}{3}x\) = \(\dfrac{7}{12}\)
(\(\dfrac{1}{2}-\dfrac{2}{3}\))\(x\) = \(\dfrac{7}{12}\)
- \(\dfrac{1}{6}\)\(x\) = \(\dfrac{7}{12}\)
\(x\) = \(\dfrac{7}{12}\) : (- \(\dfrac{1}{6}\))
\(x\) = - \(\dfrac{7}{2}\)
Vậy \(x\) = - \(\dfrac{7}{2}\)
1,28:0,125+1,28.0,25+1,8.1,75
=1,28.\(\frac{1}{8}\)+1,28.\(\frac{1}{4}\)+1,8.\(\frac{7}{10}\)
=1,28\(\left(\frac{1}{8}+\frac{1}{4}\right)\)+\(\frac{9}{5}\).\(\frac{7}{10}\)
=1,28\(\left(\frac{1}{8}+\frac{2}{8}\right)\)+\(\frac{63}{50}\)
=\(\frac{32}{25}\cdot\frac{3}{8}+\frac{63}{50}\)
\(=\frac{12}{25}\)
\(4\frac{3}{4}+\left(-0,37\right)+\frac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{12}\)
\(=4,75-0,37+0,125-1,28-2,5+\frac{37}{12}\)
\(=0,725+\frac{37}{12}\)
\(=\frac{457}{120}\)
12+8/10=12,8
128/10000=0,0128
1+28/100=1,28
128/1000=0,128
12 8/10 - 12,8
128/10000 - 0,0128
1 28/100 - 1,28
128/1000 - 0,128
12 : (x * 3) = 1,28 + 2,72
12 : (x * 3) = 4
x * 3 = 12 : 4
x * 3 = 3
x = 3 : 3
x = 1
`->` x = 1.