a + a x 3/2 + a : 2/7 = 252
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a)\(\frac{5}{9}\times x-1=\frac{8}{9}\)
\(\frac{5}{9}\times x=\frac{8}{9}+1\)
\(\frac{5}{9}\times x=\frac{17}{9}\)
\(x=\frac{17}{9}:\frac{5}{9}\)
\(x=\frac{17}{5}\)
Ta có : (x + 2) + (x + 5) + (x + 8) + ...... + (x + 32) = 198
<=> (x + x + x + ...... + x) + (2 + 5 + 8 + ....... + 32) = 198
<=> 11x + 187 = 198
=> 11x = 198 - 187
=> 11x = 11
=> x = 1
a ) \(x+x\times\frac{1}{3}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(x\times1+x\times\frac{1}{3}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(x\times1+x\times\frac{1}{3}\times\frac{9}{2}+x\times\frac{7}{2}=252\)
\(x\times1+x\times\frac{9}{6}+x\times\frac{7}{2}=252\)
\(x\times\left(1+\frac{9}{6}+\frac{7}{2}\right)=252\)
\(x\times6=252\)
\(x=252\div6\)
\(x=42\)
b ) \(\left(3\times x-0,8\right)\div x+14,5=15\)
\(\left(3\times x-0,8\right)\div x=15-14,5\)
\(\left(3\times x-0,8\right)\div x=0,5\)
\(0,8\div x=3-0,5\)
\(0,8\div x=2,5\)
\(x=0,8\div2,5\)
\(x=0,32\)
y+y x 1/3 : 2/9 + y :2/7 = 252
y x 1 + y x (1/3 x 9/2 ) + y x 7/2 = 252
y x 1/1 + y x 3/2 + y x 7/2 = 252
y x (1/1 + 3/2 + 7/2 ) = 252
y x 6 = 252
y = 252 : 6
y = 42
\(a+a.\frac{3}{2}+a:\frac{2}{7}=252\)
=>\(a+a.\frac{3}{2}+a.\frac{7}{2}=252\)
=>\(a.\left(1+\frac{3}{2}+\frac{7}{2}\right)=252\)
=>\(a.\left(1+5\right)=252\)
=>\(a.6=252\)
=>\(a=42\)
Vậy a =42
=> a + a x 3/2 +a x 7/2 = 252
=> a x (1 + 3/2 + 7/2) = 252
=> a x 6 = 252
=> a = 252 :6
=> a = 42
Vậy a = 42