15/16 x 8/3 x 3/4
Rút gọn luôn khi tính
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Bài 1.
a. \(3^4.5^4-\left(15^2+1\right)\left(15^2-1\right)=15^4-\left(15^4-1\right)=1\)
b. \(x=11\Rightarrow x+1=12\)
Từ đây, ta có: \(x^4-\left(x+1\right)x^3+\left(x+1\right)x^2-\left(x+1\right)x+111=-x+111=-11+111=100\)
Bài 2.
\(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\)
\(=2^{32}-1\)
ĐK: \(x\ne\pm3\)
Khi đó:
\(C=\dfrac{2\left(x-3\right)}{x^2-9}+\dfrac{1\left(x+3\right)}{x^2-9}-\dfrac{8}{x^2-9}\\ =\dfrac{2x-6}{x^2-9}+\dfrac{x+3}{x^2-9}-\dfrac{8}{x^2-9}\\ =\dfrac{2x-6+x+3-8}{x^2-9}\\ =\dfrac{3x-11}{x^2-9}\)
Thế x = 4 vào C được:
\(C=\dfrac{3.4-11}{4^2-9}=\dfrac{12-11}{16-9}=\dfrac{1}{7}\)
a, \(M=\frac{xy^2+y^2\left(y^2-x\right)+1}{x^2y^4+2y^4+x^2+2}=\frac{y^2\left(x+y^2-x\right)+1}{y^4\left(x^2+2\right)+\left(x^2+2\right)}=\frac{y^4+1}{\left(y^4+1\right)\left(x^2+2\right)}=\frac{1}{x^2+2}\)
Thay x=-3 vào M
=>\(M=\frac{1}{\left(-3\right)^2+2}=\frac{1}{11}\)
b, Vì \(x^2\ge0\Rightarrow x^2+2\ge2\Rightarrow M=\frac{1}{x^2+2}>0\)
1/4 + 15/16 : 3/8 x 2/3 = 1/4 + 15/16 x 8/3 x2/3 = 1/4 + 5/2 x 2/3 = 1/4 + 15/4 = 16/4 = 4
1 + 2/3 + 2/9 + 2/27 = 27/27 + 18/27 + 6/27 + 2/27 = 53/27
\(\frac{3}{9}+\frac{9}{15}+\frac{8}{12}=\frac{1}{3}+\frac{3}{5}+\frac{2}{3}=\left(\frac{1}{3}+\frac{2}{3}\right)+\frac{3}{5}=1+\frac{3}{5}=\frac{8}{5}\)
\(\frac{4}{10}+\frac{12}{32}+\frac{9}{15}=\frac{2}{5}+\frac{3}{8}+\frac{3}{5}=\left(\frac{2}{5}+\frac{3}{5}\right)+\frac{3}{8}=1+\frac{3}{8}=\frac{11}{8}\)
\(\left(\frac{4}{10}-\frac{8}{30}\right)\times\frac{6}{8}=\frac{2}{15}\times\frac{3}{4}=\frac{6}{60}=\frac{1}{10}\)
Bài 1: Tính
\(a.\frac{15}{16}-\frac{7}{16}=\frac{15-7}{16}=\frac{8}{16}=\frac{1}{2}\)
\(b.\frac{7}{4}-\frac{3}{4}=\frac{7-3}{4}=\frac{4}{4}=1\)
\(c.\frac{9}{5}-\frac{3}{5}=\frac{9-3}{5}=\frac{6}{5}\)
\(d.\frac{17}{49}-\frac{12}{49}=\frac{17-12}{49}=\frac{5}{49}\)
Bài 2:Rút gọn rồi tính
\(a.\frac{2}{3}-\frac{3}{9}=\frac{2}{3}-\frac{1}{3}=\frac{2-1}{3}=\frac{1}{3}\)
\(b.\frac{7}{5}-\frac{15}{25}=\frac{7}{5}-\frac{3}{5}=\frac{7-3}{5}=\frac{4}{5}\)
Học tốt. K cho mik nha
\(\dfrac{15}{16}\cdot\dfrac{8}{3}\cdot\dfrac{3}{4}=\dfrac{15\cdot8\cdot3}{8\cdot2\cdot3\cdot4}=\dfrac{15}{2\cdot4}=\dfrac{15}{16}\)
Bạn tick nhé!