Đặt tính rồi tính.
a) 57 + 28 24 + 67 46 + 39
b) 83 – 19 42 – 38 90 – 76
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Phương pháp giải:
- Đặt tính: Viết phép tính sao cho các chữ số cùng hàng thẳng cột với nhau.
- Tính: Trừ các số lần lượt từ phải sang trái.
Lời giải chi tiết:
\(\begin{array}{*{20}{c}}{a)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{536}\\{\,\,\,\,\,8}\end{array}}\\\hline{\,\,\,544}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{\,\,\,67}\\{829}\end{array}}\\\hline{\,\,\,\,996}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{432}\\{284}\end{array}}\\\hline{\,\,\,\,716}\end{array}\)
\(\begin{array}{*{20}{c}}{b)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{253}\\{\,\,\,\,\,7}\end{array}}\\\hline{\,\,\,\,246}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{561}\\{\,\,\,42}\end{array}}\\\hline{\,\,\,519}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{795}\\{638}\end{array}}\\\hline{\,\,\,\,057}\end{array}\)
-25 + ( 38 +26 - 75 ) - ( 38 + 65 -73 )=-66
tick mik trước nha bạn,mik nhanh nhất
45-58+(-45)+(+58)-3=45-58-45+58-3=(45-45)+(58-58)-3=-3
(-57)-(-12)+3-(-57)=-57+12+3+57=(-57+57)+12+3=15
-(-24)-(-30)+(-24)-30+8=24+30-24-30+8=(24-24)+(30-30)+8=8
-(-12)+(+19)-(+12)+8-19=12+19-12+8-19=(12-12)+(19-19)+8=8
47-(-53)+(-47)-(+53)=47+53-47-53=(47-47)+(53-53)=0
-(+28)+32-(-28)+(-34)=-28+32+28-34=(-28+28)-(34-32)=-2
15-(+72)+(-15)+(+72)=15-72-15+72=(15-15)+(72-72)=0
20-(+46)+(-25)-(-46)=20-46-25+46=(20-25)+(46-46)=-5
28-(-32)+(-28)-32+5=28+32-28-32+5=(28-28)+(32-32)+5=5
-75+(-49)+(+75)+49-12=-75-49+75+49-12=(-75+75)+(49-49)-12=-12
\(...=45-58-45+58-3=-3\)
\(...=-57+12+3+57=15\)
\(...=24+30-24-30+8=8\)
\(...=12+19-12+8-19=8\)
\(...=47+53-47-53=0\)
\(...=-28+32+28-34=-2\)
\(...=15-72-15+72=0\)
\(...=20-46-25+46=-5\)
\(=...28+32-28-32+5=5\)
\(...=-75-49+75+49-12=-12\)
a) 57 + 28 = 85
24 + 67 = 91
46 + 39 = 85
b) 83 - 19 = 64
42 - 38 = 4
90 - 76 = 14
\(\begin{array}{*{20}{c}}{a)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{57}\\{28}\end{array}}\\\hline{\,\,\,\,85}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{24}\\{67}\end{array}}\\\hline{\,\,\,\,91}\end{array}\) \(\begin{array}{*{20}{c}}{ + \begin{array}{*{20}{c}}{46}\\{39}\end{array}}\\\hline{\,\,\,\,85}\end{array}\)
\(\begin{array}{*{20}{c}}{b)\,\,}\\{}\\{}\end{array}\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{83}\\{19}\end{array}}\\\hline{\,\,\,\,64}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{42}\\{38}\end{array}}\\\hline{\,\,\,\,04}\end{array}\) \(\begin{array}{*{20}{c}}{ - \begin{array}{*{20}{c}}{90}\\{76}\end{array}}\\\hline{\,\,\,\,14}\end{array}\)