tính nhanh
a . 2,013 x 3,5 + 2,013 x 4,1 + 2,4 x 2,013
b . 20,12 x 2111 - 20,11 x 2012
c . ( 1 + 3 + 5 + .....+ 2017 ) x ( 432432 x 468 - 234234 x 864 )
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a)
x = 0 ; 1 ; 1,001 ; 1,002 ; 1,003 ; 1,004 ; 1, 005 ; 1,006 ; 1,007 ; 1,008 ; 1,009 ; 1,010 ; 1,011
b)
x = 0 ; 1 ; 1,001 ; 1,002 ; 1,003 ; .... ; 2,012
c )
x = 1,3 ; 1,4 ; 1,5 ; 1,6 ; .... ; 3,3
d)
x = 5,02 ; 5,01 ; 5 ; .... ; 3,04
a: \(20,11\cdot7,5+20,11+20,11+20,11\cdot0,5\)
\(=20,11\left(7,5+1+1+0,5\right)\)
\(=20,11\cdot10=201,1\)
b: \(2,5\cdot12,85\cdot4\)
\(=12,85\cdot\left(2,5\cdot4\right)\)
\(=12,85\cdot10=128,5\)
a: 20,11⋅7,5+20,11+20,11+20,11⋅0,520,11⋅7,5+20,11+20,11+20,11⋅0,5
=20,11(7,5+1+1+0,5)=20,11(7,5+1+1+0,5)
=20,11⋅10=201,1=20,11⋅10=201,1
b: 2,5⋅12,85⋅42,5⋅12,85⋅4
=12,85⋅(2,5⋅4)=12,85⋅(2,5⋅4)
=12,85⋅10=128,5
\(a,2017\times\left(8+2\right)=2017\times10=20170\\ b,=\dfrac{3}{7}\times\left(\dfrac{9}{7}-\dfrac{2}{7}\right)=\dfrac{3}{7}\times1=\dfrac{3}{7}\)
Câu 1:
a)\(6\dfrac{5}{8}-4\dfrac{1}{2}=\left(6+\dfrac{5}{8}\right)-\left(4+\dfrac{1}{2}\right)\\ =6+\dfrac{5}{8}-4-\dfrac{1}{2}\\ =\left(6-4\right)+\left(\dfrac{5}{8}-\dfrac{1}{2}\right)\\ =2+\dfrac{1}{8}\\ =2\dfrac{1}{8}\)
b) \(-2.013+1.01=-1.003\)
Câu 2:
\(\dfrac{2}{3}x+\dfrac{1}{2}=\dfrac{1}{10}\\ \dfrac{2}{3}x=\dfrac{1}{10}-\dfrac{1}{2}\\ \dfrac{2}{3}x=-\dfrac{2}{5}\\ x=-\dfrac{2}{5}:\dfrac{2}{3}\\ x=-\dfrac{2}{5}.\dfrac{3}{2}\\ x=-\dfrac{3}{5}\\ x=-0.6\)
Vậy x=-0.6
Câu 1
a) \(-\dfrac{23}{3}=-7\dfrac{2}{3}\)
b)\(123.45=12345\%\)
Mình nghĩ vậy
a)x . 3,5 + x . 12,5 = 396,8
x (3,5+12,5) =396,8
x. 16 =396,8
x = 396,8 :16
x= 24,8
b) 20,11 : 0,1 + 20,11: 10 -20,11 : (2,1 : 21) =2,011
Bài 3:
b: \(x^2+2x+1=\left(x+1\right)^2\)
c: \(x^2-16=\left(x-4\right)\left(x+4\right)\)
d: \(\left(2x-1\right)^2-\left(x+3\right)^2\)
\(=\left(2x-1-x-3\right)\left(2x-1+x+3\right)\)
\(=\left(x-4\right)\left(3x+2\right)\)
a) 2,013x3,5+2,013x4,1+2,4x2,013
=2,013x(3,5+4,1+2,4)
=2,013x10
=20,13