4xX+X=250
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\(\dfrac{4\times x}{1\times5}\) + \(\dfrac{4\times x}{5\times9}\) + \(\dfrac{4\times x}{9\times13}\) + \(\dfrac{4\times x}{13\times17}\) = 16
\(x\times\left(\dfrac{4}{1\times5}+\dfrac{4}{5\times9}+\dfrac{4}{9\times13}+\dfrac{4}{13\times17}\right)\) = 16
\(x\) \(\times\) (\(\dfrac{1}{1}\) - \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\) - \(\dfrac{1}{9}\) + \(\dfrac{1}{9}\) - \(\dfrac{1}{13}\) + \(\dfrac{1}{13}\) - \(\dfrac{1}{17}\)) = 16
\(x\) \(\times\) ( \(\dfrac{1}{1}\) - \(\dfrac{1}{17}\)) = 16
\(x\) \(\times\) \(\dfrac{16}{17}\) = 16
\(x\) = 16 : \(\dfrac{16}{17}\)
\(x\) = 17
`4 xx x -x-x=1,07`
`=> 4 xx x - x xx 1 - x xx 1=1,07`
`=> (4-1-1) xx x=1,07`
`=> 2 xx x =1,07`
`=> x=1,07 : 2`
`=>x=0,535`
`4xx x-x-x=107`
`=>x xx (4-1-1)=1,07`
`=> x xx 2=1,07`
`=>x=1,07:2`
`=>x=0,535`
a) => x : 80 = 2
=> x = 160
b) => 200/15 : x = 3
=> x = 40/9
c) => 158 - x = 140
=> x = 18
d) => 231 - (x-6) = 103
=> x - 6 = 128
=> x = 134
\(\frac{3}{8}\times x+\frac{1}{4}\times x=\frac{2}{5}\)
\(\Rightarrow x\times\left(\frac{3}{8}+\frac{1}{4}\right)=\frac{2}{5}\)
\(\Rightarrow x\times\frac{5}{8}=\frac{2}{5}\)
\(\Rightarrow x=\frac{16}{25}\)
~Std well~
#Thạc_Trân
\(4x+3x+2x+x=100\)
\(\Leftrightarrow10x=100\Leftrightarrow x=\frac{100}{10}=10\)
Vậy \(x=10\)
( 4 x X - 0.8 ) : X + 14.5 = 16
( 4 x X - 0.8 ) : X = 16 - 14.5
4 x X - 0.8 = 1.5 x X
4 x X - 1.5 x X = 0.8
( 4 - 1.5 ) x X = 0.8
2.5 x X = 0.8
X = 0.8 : 2.5
X = 0.32
`4xx x+x=250`
`=>x xx (4+1)=250`
`=>x xx 5=250`
`=> x =250:5`
`=>x=50`
4 \(\times\) \(x\) + \(x\) = 250
4 \(\times\) \(x+x\times1\) = 250
\(x\times\) ( 4 + 1) = 250
\(x\times\) 5 = 250
\(x\) = 250 : 5
\(x\) = 50