Tìm x biết 10+2x=45/43
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10 + 2x = 45 : 43
10 + 2x = 45 - 3
10 + 2x = 42
10 + 2x = 16
2x = 16 - 10
2x = 6
x = 6 : 2
x = 3
Vậy x = 3
a, 70 - 5 ( x - 3 ) = 45
⇔ 5 . x - 3 = 70 - 45
⇔ 5 x - 3 = 35
⇔ x - 3 = 35 : 5 ⇔ x - 3 = 7
⇔ x = 10
b, 10 + 2 x = 4 5 : 4 3
⇔ 10 + 2 x = 4 2 ⇔ 10 + 2 x = 16
⇔ 2 x = 4 ⇔ x = 2
c, 60 - 3 x - 2 = 51
⇔ 3 x - 2 = 60 - 51
⇔ 3 x - 2 = 9
⇔ x - 2 = 3 ⇔ x = 5
d, 4 x - 20 = 2 5 : 2 3
⇔ 4 x - 20 = 2 2 ⇔ 4 x - 20 = 4
⇔ 4 x = 24 ⇔ x = 6
a) \(2^x:4=16\\ \Rightarrow2^x=64\\ \Rightarrow2^x=2^6\\ \Rightarrow x=6\)
b) \(4^{x-3}=256\\ \Rightarrow4^{x-3}=4^4\\ \Rightarrow x-3=4\\ \Rightarrow x=7\)
c) \(\left(2x+1\right)^3=343\\ \Rightarrow\left(2x+1\right)^3=7^3\\ \Rightarrow2x+1=7\\ \Rightarrow x=3\)
d) \(10+2x=4^5:4^3\\ \Rightarrow10+2x=16\\ \Rightarrow x=3\)
a,2^x:4=16
2^x=16.4=64
2^x=2^6
=>x=6
b,4^x-3=256
4^x-3=4^4
=>x-3=4
x=4+3=7
c,(2x+1)^3=343
(2x+1)^3=7^3
=>2x+1=7
2x=7-1=6
x=6:2=3
d,10+2x=4^5:4^3
10+2x=4^2=16
2x=16-10=6
x=6:2=3
a, 2x : 4 = 16
⇒ 2x : 22 = 24
⇒ x - 2 = 4
⇒ x = 6
b, 4x-3 = 256
⇒ 4x - 3 = 44
⇒ x - 3 = 4
⇒ x = 7
c, (2x + 1)3 = 343
⇒ (2x + 1)3 = 73
⇒ 2x + 1 = 7
⇒ 2x = 6
⇒ x = 3
d, 10 + 2x = 45 : 43
⇒ 10 + 2x = 16
⇒ 2x = 6
⇒ x = 3
c) \(\left(2x-3\right)-\left(-12\right)=-5-10\)
\(2x-3+12=-15\)
\(2x+9=-15\)
\(2x=-24\)
\(x=-12\)
d) \(17-\left(43-\left|x\right|\right)=45\)
\(17-43+\left|x\right|=45\)
\(-26+\left|x\right|=45\)
\(\left|x\right|=45+26\)
\(\left|x\right|=71\)
\(\Rightarrow\orbr{\begin{cases}x=71\\x=-71\end{cases}}\)
a) 82 - (15 + x) = 72
=> 15 + x = 82 - 72
=> 15 + x = 10
=> x = 10 - 15
=> x = -5
Vậy x = -5
b) 24 - (x - 6) = -3 - 7
=> 24 - (x - 6) = -10
=> x - 6 = 24 + 10
=> x - 6 = 34
=> x = 34 + 6
=> x = 40
Vậy x = 40
a.\(17-\left(43-\left|x\right|\right)=45\)
\(\Leftrightarrow43-\left|x\right|=17-45\)
\(\Leftrightarrow43-\left|x\right|=-28\)
\(\Leftrightarrow\left|x\right|=43+28\)
\(\Leftrightarrow\left|x\right|=71\)
\(\Leftrightarrow x\in\left\{-71;71\right\}\)
b. \(\left(x-2\right)\left(x+15\right)=0\Leftrightarrow x\in\left\{2;-15\right\}\)
c. \(2x^2-3=29\)
\(\Leftrightarrow2x^2=29+3\)
\(\Leftrightarrow2x^2=32\)
\(\Leftrightarrow x^2=32\div2\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow x^2=4^2=\left(-4\right)^2\)
Vậy x = 4 hoặc x = 4
a: =>2x+10=4^2=16
=>2x=6
=>x=3
b: =>2x-138=8*9=72
=>2x=138+72=210
=>x=105
c: =>231-(x-6)=103
=>x-6=128
=>x=134
\(a.10+2x=4^5:4^3\\ \Leftrightarrow10+2x=4^2\\ \Leftrightarrow2x=6\\ \Leftrightarrow x=3\)
\(b.2x-138=2^3.3^2\\ \Leftrightarrow2x-138=72\\ \Leftrightarrow x=210:2\\ \Leftrightarrow x=105\)
\(c.231-\left(x-6\right)=1339:13\\ \Leftrightarrow231-\left(x-6\right)=103\\ \Leftrightarrow x-6=128\\ \Leftrightarrow x=134\)
Chú ý : Nếu bạn chưa học \(\Leftrightarrow\) thì bạn bỏ đi nha !
a: 3x=81
nên x=27
b: \(5\cdot4^x=80\)
\(\Leftrightarrow4^x=16\)
hay x=2
c: \(2^x=4^5:4^3\)
\(\Leftrightarrow2^x=2^4\)
hay x=4