16/24-1/6
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NY
1
2 tháng 2 2024
d: \(\dfrac{5}{16}-\dfrac{5}{24}=\dfrac{5\cdot3}{48}-\dfrac{5\cdot2}{48}=\dfrac{5}{48}\)
e: \(-\dfrac{24}{17}-\left(-\dfrac{7}{17}-\dfrac{1}{16}\right)\)
\(=-\dfrac{24}{17}+\dfrac{7}{17}+\dfrac{1}{16}=-1+\dfrac{1}{16}\)
\(=-\dfrac{15}{16}\)
f: \(\dfrac{-11}{6}+\dfrac{2}{5}+\dfrac{-1}{6}\)
\(=\left(-\dfrac{11}{6}-\dfrac{1}{6}\right)+\dfrac{2}{5}\)
\(=-2+\dfrac{2}{5}=\dfrac{-8}{5}\)
29 tháng 10 2018
mình xin nhầm đề là: A = \(1*2*3+2*4*6+4*8*12+8*16*24 \over2*3*4+4*6*8+8*12*16+16*24*32\)
27 tháng 2 2022
\(\dfrac{1}{5}+\dfrac{4}{11}+\dfrac{4}{5}+\dfrac{7}{11}=\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\left(\dfrac{4}{11}+\dfrac{7}{11}\right)=\dfrac{5}{5}+\dfrac{11}{11}=1+1=2\)
\(\dfrac{5}{6}+\dfrac{8}{24}+\dfrac{1}{6}+\dfrac{16}{24}=\dfrac{5}{6}+\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{2}{3}=\left(\dfrac{5}{6}+\dfrac{1}{6}\right)+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)=\dfrac{6}{6}+\dfrac{3}{3}=1+1=2\)
12 tháng 3 2020
1) -39 +14+26+39
= 39-39 + 40
=40
2) -54 +16 +(-6)+54
=54-54 +10
=10
3) 45 +23+(-35)+(-23)
= 45-35 +23 -23
=10+0
=10
4) 45 .17 - 5.9.7
=45.17 -45.7
=45.( 17-7)
=45 .10
=450
5) 24 ( 16-5) -16(24-5)
=24.16 -24.5 -16 .24 +16 .5
= 24.16 -16.24 +5 (16-24)
=0 +5 .(-8)
=-40
Chúc hok tốt!
12 tháng 3 2020
1. ( - 39 ) + 14 + 26 + 39
= [ ( - 39 ) + 39 ] + ( 14 + 26 )
= 0 + 40
= 40
2. ( - 54 ) + 16 + ( - 6 ) + 54
= [ ( - 54 ) + 54 ] + [ 16 + ( - 6 ) ]
= 0 + 10
= 10
3. 45 + 23 + ( - 35 ) + ( - 23 )
= [ 45 + ( - 35 ) ] + [ 23 + ( - 23 ) ]
= 10 + 0
= 10
4. 45 . 17 - 5 . 9 . 7
= 45 . 17 - 45 . 7
= 45 . ( 17 - 7 )
= 45 . 10
= 450
5. 24 . ( 16 - 5 ) - 16 . ( 24 - 5 )
= 24 . 11 - 16. 19
= 264 - 304
= 264 + ( - 304 )
= - ( 304 - 364 )
= - 40
Chúc bạn học tốt !
NT
1
3 tháng 2 2021
Bài 1:
1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)
\(=-12-18\)
=-30
2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)
\(=36-2020+2019-136-27\)
\(=1-100-27\)
\(=-126\)
3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)
\(=144-97-244+197\)
\(=-100+100=0\)
4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)
\(=-24\cdot13+24\cdot3\)
\(=24\cdot\left(-13+3\right)\)
\(=24\cdot\left(-10\right)=-240\)
5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)
\(=54+55+56+57+58-64-65-66-67-68\)
\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)
\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)
=-50
6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)
\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)
\(=-24\cdot5+16\cdot5\)
\(=5\cdot\left(-24+16\right)\)
\(=-5\cdot8=-40\)
7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)
\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)
\(=47\cdot50-23\cdot50\)
\(=50\cdot\left(47-23\right)\)
\(=50\cdot24=1200\)
8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)
\(=-31\cdot\left(47+52+1\right)\)
\(=-31\cdot100=-3100\)
Bài 2:
1) Ta có: \(-17-\left(2x-5\right)=-6\)
\(\Leftrightarrow-17-2x+5+6=0\)
\(\Leftrightarrow-2x-6=0\)
\(\Leftrightarrow-2x=6\)
hay x=-3
Vậy: x=-3
2) Ta có: \(10-2\left(4-3x\right)=-4\)
\(\Leftrightarrow10-8+6x+4=0\)
\(\Leftrightarrow6x+6=0\)
\(\Leftrightarrow6x=-6\)
hay x=-1
Vậy: x=-1
3) Ta có: \(-12+3\left(-x+7\right)=-18\)
\(\Leftrightarrow-12-3x+21+18=0\)
\(\Leftrightarrow-3x+27=0\)
\(\Leftrightarrow-3x=-27\)
hay x=9
Vậy: x=9
4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)
\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)
\(\Leftrightarrow-2x-3=-3\)
\(\Leftrightarrow-2x=0\)
hay x=0
Vậy: x=0
5) Ta có: x(x+3)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-3\right\}\)
6) Ta có: (x-2)(x+4)=0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-4\right\}\)
7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-1;3\right\}\)
DT
25 tháng 1 2022
Bài 1:
1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)
=−12−18=−12−18
=-30
2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27
=36−2020+2019−136−27=36−2020+2019−136−27
=1−100−27=1−100−27
=−126
Tớ chcs cậu học thật giỏi nha !
CM
2
N
3
12 tháng 5 2022
`a, 7/24 - 1/6 = 7/24 - 4/24 = 3/24=1/8`
`b, 21/16 : 7/5 = 21/16 xx 5/7 = 15/16`
LN
0
=2/3-1/6
=4/6-1/6
=3/6
=1/2
\(\dfrac{16}{24}-\dfrac{1}{6}\\ =\dfrac{16:8}{24:8}-\dfrac{1}{6}\\ =\dfrac{2}{3}-\dfrac{1}{6}\\ =\dfrac{2\times2-1}{6}=\dfrac{3}{6}=\dfrac{1}{2}\)