2.(x-12)+18=164
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a)18 + 2 x y = 50
2 x y = 50 - 18
2 x y = 32
y = 32 : 2
y = 16
b)219 - (y - 19) = 100
(y - 19) = 219 - 100
(y - 19) = 119
y = 119 - 19
y = 100
c)2 x (y - 12) + 18 = 164
2 x (y - 12) = 164 - 18
2 x (y - 12) = 146
( y - 12 ) = 146 : 2
( y - 12 ) = 73
y = 73 - 12
y = 61
\(a,127-\left(y-15\right)=86\)
\(y-15=127-86\)
\(y-15=41\)
\(y=41+15\)
\(y=56\)
\(b,2\times\left(y-12\right)+18=164\)
\(2\times\left(y-12\right)=164-18\)
\(2\times\left(y-12\right)=146\)
\(y-12=146:2\)
\(y-12=73\)
\(y=73+12\)
\(y=85\)
Học tốt
a)
y + 2,3 = 15,7 - 2,4
y + 2,3 = 13,3
y = 13,3 - 2,3
y = 11
Vậy y = 11
b)
127 - (y - 15) = 86
y - 15 = 127 - 86
y - 15 = 41
y = 41 + 15
y = 56
Vậy y = 56
c)
2 x (y - 12) + 18 = 164
2 x ( y - 12 ) = 164 - 18
2 x ( y - 12 ) = 146
y - 12 = 146 : 2
y - 12 = 73
y = 73 + 12
y = 85
Vậy y = 85
a) y + 2,3 = 15,7 - 2,4
y+2,3=13,3
y=11
b) 127 - (y - 15) = 86
y-15=41
y=56
c) 2 .(y - 12) + 18 = 164
2 .(y - 12) =146
y-12=73
y=85
a) y+2,3=15,724
=>y =15,724 - 2,3
=>y = 13,424
b) 127-(y-15)=86
=> y-15 = 127-86
=> y-15 = 41
=> y = 41+15
=> y = 56
c) 2 x (y-12)+18 = 164
=> 2 x (y-12) = 146
=> y-12 = 73
=> y = 73 + 12
=> y = 85
a) \(y+2,3=15,724\)
\(y=15,724-2,3\)
\(y=13,424\)
b) \(127-\left(y-15\right)=86\)
\(y-15=127-86\)
\(y-15=41\)
\(y=41+15\)
\(y=56\)
c) \(2\cdot\left(x-12\right)+18=164\)
\(2\cdot\left(x-12\right)=164-18\)
\(2\cdot\left(x-12\right)=146\)
\(x-12=146:2\)
\(x-12=73\)
\(x=73+12\)
\(x=85\)
3 x 164 x 6 +18 x 347 + 2 x 489 x 9
=(3x6)x164+18x347+(2x9)x489
=18x164+18x347+18x489
=18x(164+347+489)
=18x1000
=18000
Các hỗn só và phân số = nhau là:5/3=1 12/18; 5 9/31=1 29/65; 55/14=5 13/44; 94/65=164/31;2 7/13=66/26
Bài 1.
\(a,\left(2^4\cdot3\cdot5^2\right):\left\{450:\left[450-\left(4\cdot5^3-2^3\cdot5^2\right)\right]\right\}\)
\(=\left(16\cdot3\cdot25\right):\left\{450:\left[450- \left(4\cdot125-8\cdot25\right)\right]\right\}\)
\(=\left(48\cdot25\right):\left\{450:\left[450-\left(500-200\right)\right]\right\}\)
\(=1200:\left[450:\left(450-300\right)\right]\)
\(=1200:\left(450:150\right)\)
\(=1200:3\)
\(=400\)
\(---\)
\(b,3^3\cdot5^2-20\left\{90-\left[164-2\cdot\left(7^8:7^6+7^0\right)\right]\right\}\)
\(=27\cdot25-20\left\{90-\left[164-2\cdot\left(7^2+1\right)\right]\right\}\)
\(=675-20\left\{90-\left[164-2\cdot\left(49+1\right)\right]\right\}\)
\(=675-20\left[90-\left(164-2\cdot50\right)\right]\)
\(=675-20\left[90-\left(164-100\right)\right]\)
\(=675-20\left(90-64\right)\)
\(=675-20\cdot26\)
\(=675-520\)
\(=155\)
\(---\)
\(c,\left[\left(18^7:18^6-17\right)\cdot2022-1986\right]\cdot5\cdot1^{2022}-13^2\cdot2020^0\)
\(=\left[\left(18-17\right)\cdot2022-1986\right]\cdot5\cdot1-169\cdot1\)
\(=\left(1\cdot2022-1986\right)\cdot5-169\)
\(=\left(2022-1986\right)\cdot5-169\)
\(=36\cdot5-169\)
\(=180-169\)
\(=11\)
Bài 2.
\(a) (2^x+1)^2+3\cdot(2^2+1)=2^2\cdot10\\\Rightarrow (2^x+1)^2+3\cdot(4+1)=4\cdot10\\\Rightarrow (2^x+1)^2+3\cdot5=40\\\Rightarrow (2^x+1)^2+15=40\\\Rightarrow (2^x+1)^2=40-15\\\Rightarrow (2^x+1)^2=25\\\Rightarrow (2^x+1)^2= (\pm 5)^2\\\Rightarrow \left[\begin{array}{} 2^x+1=5\\ 2^x+1=-5 \end{array} \right.\\ \Rightarrow \left[\begin{array}{} 2^x=4\\ 2^x=-6 (vô.lí) \end{array} \right. \\ \Rightarrow 2^x=2^2\\\Rightarrow x=2\)
Vậy \(x=2\).
\(---\)
\(b)3\cdot(x-7)+2\cdot(x+5)=41\\\Rightarrow 3\cdot x+3\cdot(-7)+2\cdot x+2\cdot5=41\\\Rightarrow 3x-21+2x+10=41\\\Rightarrow (3x+2x)+(-21+10)=41\\\Rightarrow 5x-11=41\\\Rightarrow 5x=41+11\\\Rightarrow 5x=52\\\Rightarrow x=\dfrac{52}{5}\)
Vậy \(x=\dfrac{52}{5}\).
\(Toru\)
2.(x - 12) + 18 = 164
2 ( x - 12) = 164 - 18
2( x - 12) = 146
x - 12 = 146 :2
x - 12 = 73
x = 73 + 12
x = 85
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