Phân tích đa thức thành nhân tử :
\(3m^2-2m-1\)
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\(\frac{2m^2+3m+1}{2m^2-m-1}=\frac{2m^2+2m+m+1}{2m^2-2m+m-1}\)
\(=\frac{2m\left(m+1\right)+\left(m+1\right)}{2m\left(m-1\right)+\left(m-1\right)}=\frac{\left(m+1\right)\left(2m+1\right)}{\left(m-1\right)\left(2m+1\right)}\)
\(=\frac{m+1}{m-1}\)
Ta có :
a3m+2a2m+am
= am(a2m+2am+1)
= am[(am)2+2am+1]
= am(am+1)2
\(=\left(m-n\right)\left(m+n\right)-2\left(m+n\right)=\left(m+n\right)\left(m-n-2\right)\)
5m^2 - 5mn + 3m - 3n
= 5m . ( m - n ) + 3 . ( m - n )
= ( m - n ) . ( 5m + 3 )
a) 9x² - 25
= (3x)² - 5²
= (3x - 5)(3x + 5)
b) y³ + 6y² + 9y
= y(y² + 6y + 9)
= y(y² + 2.y.3 + 3²)
= y(y + 3)²
c) m² - n² - 2m + 1
= (m² - 2m + 1) - n²
= (m - 1)² - n
= (m - 1 - n)(m - 1 + n)
= (m - n - 1)(m + n - 1)
\(1,\\ a,=4\left(x-2\right)^2+y\left(x-2\right)=\left(4x-8+y\right)\left(x-2\right)\\ b,=3a^2\left(x-y\right)+ab\left(x-y\right)=a\left(3a+b\right)\left(x-y\right)\\ 2,\\ a,=\left(x-y\right)\left[x\left(x-y\right)^2-y-y^2\right]\\ =\left(x-y\right)\left(x^3-2x^2y+xy^2-y-y^2\right)\\ b,=2ax^2\left(x+3\right)+6a\left(x+3\right)\\ =2a\left(x^2+3\right)\left(x+3\right)\\ 3,\\ a,=xy\left(x-y\right)-3\left(x-y\right)=\left(xy-3\right)\left(x-y\right)\\ b,Sửa:3ax^2+3bx^2+ax+bx+5a+5b\\ =3x^2\left(a+b\right)+x\left(a+b\right)+5\left(a+b\right)\\ =\left(3x^2+x+5\right)\left(a+b\right)\\ 4,\\ A=\left(b+3\right)\left(a-b\right)\\ A=\left(1997+3\right)\left(2003-1997\right)=2000\cdot6=12000\\ 5,\\ a,\Leftrightarrow\left(x-2017\right)\left(8x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2017\\x=\dfrac{1}{4}\end{matrix}\right.\\ b,\Leftrightarrow\left(x-1\right)\left(x^2-16\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=4\\x=-4\end{matrix}\right.\)
\(3m^2-2m-1\)
\(=3m^2-3m+m-1\)
\(=3m\left(m-1\right)+\left(m-1\right)\)
\(=\left(m-1\right)\left(3m+1\right)\)
\(3m^2-2m-1\)
\(=3m^2+m-3m-1\)
\(=\left(3m^2+m\right)-\left(3m+1\right)\)
\(=m\left(3m+1\right)-\left(3m+1\right)\)
\(=\left(m-1\right)\left(3m+1\right)\)