-4/12 + 14/21
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có: \(\left(\dfrac{14}{\sqrt{14}}+\dfrac{\sqrt{12}+\sqrt{30}}{\sqrt{2}+\sqrt{5}}\right)\cdot\sqrt{5-\sqrt{21}}\)
\(=\left(\sqrt{14}+\sqrt{6}\right)\cdot\sqrt{5-\sqrt{21}}\)
\(=\left(\sqrt{7}+\sqrt{3}\right)\left(\sqrt{7}-\sqrt{3}\right)\)
=7-3
=4
a/16
b/15
tui tick cậu rùi c5u tick tui nha
- Nguyễn Hương Giang
11+11=(1+1).(1+1)=4
12+13=(1+2).(1+3)=3.4=12
21+14=(1+2)(1+4)=3.5=15
\(\dfrac{6}{21}-\dfrac{-12}{44}+\dfrac{10}{12}-\dfrac{-1}{4}-\dfrac{18}{33}\)
\(=\dfrac{6}{21}+\dfrac{12}{44}+\dfrac{10}{12}+\dfrac{1}{4}-\dfrac{18}{33}\)
\(=\dfrac{1013}{924}\)
\(\dfrac{6}{21}-\dfrac{-12}{44}+\dfrac{10}{44}-\dfrac{1}{-4}-\dfrac{18}{33}\)
\(=\dfrac{2}{7}+\dfrac{3}{11}+\dfrac{5}{7}+\dfrac{1}{4}-\dfrac{9}{11}\)
\(=\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{3}{11}-\dfrac{9}{11}\right)+\dfrac{1}{4}\)
\(=1+-\dfrac{6}{11}+\dfrac{1}{4}\)
\(=\dfrac{5}{11}+\dfrac{1}{4}\)
\(=\dfrac{31}{44}\)
\(VT=\left(\dfrac{\sqrt{14}.\sqrt{14}}{\sqrt{14}}+\dfrac{\sqrt{6}\left(\sqrt{2}+\sqrt{5}\right)}{\sqrt{2}+\sqrt{5}}\right)\sqrt{5-\sqrt{21}}\\ =\left(\sqrt{14}+\sqrt{6}\right)\sqrt{5-\sqrt{21}}\\ =\sqrt{14}.\sqrt{5-\sqrt{2}1}+\sqrt{6}.\sqrt{5-\sqrt{21}}\\ =\sqrt{70-14\sqrt{21}}+\sqrt{30-6\sqrt{21}}\\ =\sqrt{49-2.7.\sqrt{21}+21}+\sqrt{9-2.3.\sqrt{21}+21}\\ =\sqrt{\left(7-\sqrt{21}\right)^2}+\sqrt{\left(3-\sqrt{21}\right)^2}\\ =\left|7-\sqrt{21}\right|+\left|3-\sqrt{21}\right|\\ =7-\sqrt{21}+\sqrt{21}-3\\ =7-3=4=VP\)
\(-\dfrac{4}{12}+\dfrac{14}{21}\)
\(=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)
`-4/12 + 14/21`
`= -1/3 + 2/3`
`=(-1+2)/3`
`=1/3`
`@ ` \(\text{BNg BaooTrann}\)