-12.(x-5)+7.(3-x)=5
tìm x giải hộ nhé :)
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2/3.x + 1/4 = 7/12
2/3.x = 7/12 - 1/4
2/3.x = 1/3
x = 1/3 : 2/3
x = 1/2
Bài làm
\(\frac{2}{3}x+\frac{1}{4}=\frac{7}{12}\)
\(\frac{2}{3}x=\frac{7}{12}-\frac{1}{4}\)
\(\frac{2}{3}x=\frac{7}{12}-\frac{3}{12}\)
\(\frac{2}{3}x=\frac{4}{12}\)
\(\frac{2}{3}x=\frac{1}{3}\)
\(x=\frac{1}{3}:\frac{2}{3}\)
\(x=\frac{1}{3}.\frac{3}{2}\)
\(x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
a) \(x=-\dfrac{3}{5}\times\dfrac{9}{7}=-\dfrac{27}{35}\)
b) \(x\left(0,4-\dfrac{1}{5}\right)=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)
a, \(x=-3,5.\dfrac{9}{7}=-\dfrac{9}{2}\)
b, \(\dfrac{2}{5}x-\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)
\(\text{#ID07 - DNfil}\)
`A = -(x + 1)^2 + 5`
Ta có: `(x + 1)^2 \ge 0` `AA` `x`
`=> -(x + 1)^2 \le 0` `AA` `x`
`=> -(x + 1)^2 + 5 \le 5` `AA` `x`
Vậy, GTLN của A là `5` khi `(x + 1)^2 = 0 => x + 1 = 0 => x = -1`
________
2.
`2x - 0,7 = 1,3`
`=> 2x = 1,3 + 0,7`
`=> 2x = 2`
`=> x = 1`
Vậy, `x = 1`
__
`x - \sqrt{25} = (2/5 - 6/5)`
`=> x - \sqrt{25} = -3/5`
`=> x = -3/5 + \sqrt{25}`
`=> x = -3/5 + 5`
`=> x = 22/5`
Vậy, `x = 22/5`
__
`3/4 + 1/4 \div x = 2/5`
`=> 1/4 \div x = 2/5 - 3/4`
`=> 1/4 \div x = -7/20`
`=> x = 1/4 \div (-7/20)`
`=> x = -5/7`
Vậy, `x = -5/7.`
Ta có ; 1 + (-3) + 5 + (-7) + ...... + x = -600
<=> -2 + -2 + ...... + -2 + x = -600
Mà trc x là thui nói lun x = 1199
Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\frac{x}{5}=\frac{y}{7}=\frac{z}{3}\Leftrightarrow\frac{x^2}{5^2}=\frac{y^2}{7^2}=\frac{z^2}{3^2}=\frac{x^2+y^2-z^2}{25+49-9}=\frac{358}{65}\)
\(\hept{\begin{cases}\frac{x^2}{25}=\frac{358}{65}\\\frac{y^2}{49}=\frac{358}{65}\\\frac{z^2}{9}=\frac{358}{65}\end{cases}}\Rightarrow\hept{\begin{cases}x^2=\frac{1790}{13}\\y^2=\frac{17542}{65}\\z^2=\frac{3222}{65}\end{cases}}\Rightarrow\hept{\begin{cases}x=\sqrt{\frac{1790}{13}}\\y=\sqrt{\frac{17542}{65}}\\z=\sqrt{\frac{3222}{65}}\end{cases}}\)
Vậy ...
\(\frac{12}{7}\times\frac{2}{11}+\frac{12}{11}\times\frac{15}{7}-\frac{12}{7}\times\frac{6}{11}\)
\(=\frac{12}{7}\times\frac{2}{11}+\frac{12}{7}\times\frac{15}{11}-\frac{12}{7}\times\frac{6}{11}\)
\(=\frac{12}{7}\times\left(\frac{2}{11}+\frac{15}{11}-\frac{6}{11}\right)\)
\(=\frac{12}{7}\times1=\frac{12}{7}\)
\(\frac{12}{7}.\frac{2}{11}+\frac{12}{11}.\frac{15}{7}-\frac{12}{7}.\frac{6}{11}\)
= \(\frac{24}{77}\)+\(\frac{180}{77}\)-\(\frac{72}{77}\)
=\(\frac{132}{77}\)
91/19
91/19