1,tính
A=123412341234*5678-567856785678*1234
B=1/285+1/286+...+1/568
1-1/2+1/3-1/4+1/5-1/6+...+1/567+1/568
lam ca cach lam
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=\(\frac{1}{1.2}+\frac{1}{2.3}+..+\frac{1}{7.8}\)
=1-1/8
=7/8
D=1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7+1/7x8
=1-1/2+1/2-1/3+1/3-1/4+.........+1/7-1/8
=1-1/8=1/8
\(\left(\frac{1}{2}+1\right)\cdot\left(\frac{1}{3}+1\right)\cdot...\cdot\left(\frac{1}{999+1}\right)\)
\(=>\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot...\cdot\frac{999}{998}\cdot\frac{1000}{999}\)
\(=>\frac{3\cdot4\cdot5\cdot...\cdot999\cdot1000}{2\cdot3\cdot4\cdot...\cdot997\cdot998}\)
\(=>\frac{1000}{2}=500\)
mik nghĩ là đúng
Bài 1:
a) Ta có:
\(-3\dfrac{1}{5}=-2,8\)
\(\dfrac{37}{10}=3,7\)
Vì \(-3,25< -2,8< 3,7\)
Nên \(-3,25< -3\dfrac{1}{5}< \dfrac{37}{10}\)
b) Ta có:
\(\dfrac{-567}{568}>-1\)
\(\dfrac{-568}{567}< -1\)
\(\Leftrightarrow\dfrac{-567}{568}>-1>\dfrac{-568}{567}\)
\(\Leftrightarrow\dfrac{-567}{568}>\dfrac{-568}{567}\)
c) \(-0,625=-\dfrac{5}{8}\)
Vì \(8>7\)
\(\Leftrightarrow\dfrac{1}{8}< \dfrac{1}{7}\)
\(\Leftrightarrow\dfrac{-5}{8}>\dfrac{-5}{7}\)
\(\Leftrightarrow-0,625>\dfrac{-5}{7}\)
Vậy ...
Giải:
a) \(3,6-\dfrac{-5}{6}.\left(-2,4\right).\dfrac{3}{5}\)
\(=\dfrac{18}{5}-\dfrac{-5}{6}.\left(-\dfrac{12}{5}\right).\dfrac{3}{5}\)
\(=\dfrac{18}{5}-\dfrac{6}{5}\)
\(=\dfrac{12}{5}\)
Vậy ...
b) \(\dfrac{1}{4}-0,5-6\dfrac{1}{2}+\dfrac{5}{8}\)
\(=\dfrac{1}{4}-\dfrac{1}{2}-6\dfrac{1}{2}+\dfrac{5}{8}\)
\(=-\dfrac{49}{8}\)
Vậy ...
c) \(1,1-\left(-1,2\right)-\left|-1,3\right|-2\dfrac{3}{4}\)
\(=1,1+1,2-1,3-2,75\)
\(=-\dfrac{7}{4}=-1,75\)
Vậy ...
A=1234x1001001x5678-5678x1001001x1234
A=0
A=1234x5678-5678x1234
A=0