A x 0,6 + a : 0.25 = 40.94
A = ...?
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Ta có:
\(A=2^1+2^2+2^3+...+2^{100}\)
\(\Rightarrow2A-A=\left(2^2+2^3+2^4+...+2^{101}\right)-\left(2^1+2^2+2^3+...+2^{100}\right)\)
\(\Rightarrow A.\left(2-1\right)=2^2+2^3+2^4+...+2^{101}-2^1-2^2-2^3+...+2^{100}\)
\(\Rightarrow A=\left(2^2-2^2\right)+\left(2^3-2^3\right)+\left(2^4-2^4\right)+...+\left(2^{100}-2^{100}\right)+\left(2^{101}-2^1\right)\)
\(\Rightarrow A=2^{101}-2\Leftrightarrow A=2^x-2\Leftrightarrow x=101\)
@Phúc Trần Tấn | Em biết làm ý A rồi nhưng không biết làm ý B.!!
Nếu a = 18 , b = 6 và c=3 thì a x b : c = 18 x 6 : 3 = 108 : 3 = 36
nhớ k cho mình nha
a ) 48 - 73 + |15| - ( - 29 )
= -25 + 15 + 29 = 19
b) 134 + 46.( 39 - 78 ) - | 267 |
= 134 + 46.( -39 ) - 267 = -133 -1794 = -1927
c) 36 - 16.( -2 )² + ( - 53 )
= 36 - 16.4 - 53 = -17 - 64 = -81
d) ( 259 - 47 - 5 ) - ( 259 - 5 )
= 259 - 47 - 5 - 259 + 5 = - 5 + 5 + 259 - 259 = 0
e ) 325. 26 - 325 . 125 - 325
= 325 (26 - 125 - 1) = 325. (-100) = -32500
a) Đặt \(A=4x-x^2-5\)
\(-A=x^2-4x+5\)
\(-A=\left(x^2-4x+4\right)+1\)
\(-A=\left(x-2\right)^2+1\)
Mà \(\left(x-2\right)^2\ge0\forall x\)
\(\Rightarrow-A\ge1\)
\(\Leftrightarrow A\le-1< 0\left(đpcm\right)\)
b) Đặt \(B=x^2-2x+5\)
\(B=\left(x^2-2x+1\right)+4\)
\(B=\left(x-1\right)^2+4\)
Mà \(\left(x-1\right)^2\ge0\forall x\)
\(\Rightarrow B\ge4>0\left(đpcm\right)\)
a)4x-x2-5 = -(x2-4x+4)-1= -(x-2)^2 -1 < 0 với mọi x (đpcm)
b) x2 -2x+5= (x2-2x+1)+4=(x-1)^2 +4 >0 với mọi x (đpcm)
\(A\text{×}0,6+A:0,25=40,94\)
\(A\text{×}0,6+A\text{×}4=40,94\)
\(A\text{×}\left(0,6+4\right)=40,94\)
\(A\text{×}4,6=40,94\)
\(A=40,94:4,6\)
\(A=8,9\)