300+10
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A = \(\dfrac{2}{300}\) + \(\dfrac{6}{300}\) + \(\dfrac{10}{300}\)+.....+ \(\dfrac{202}{300}\) + \(\dfrac{206}{300}\)
A = \(\dfrac{1}{300}\)\(\times\) ( 2 + 6 + 10 +.....+ 202 + 206)
A = \(\dfrac{1}{300}\) \(\times\) ( 206 +2) \(\times\) { ( 206 - 2) : 4 + 1} : 2
A = \(\dfrac{1}{300}\) x 208 x 52 : 2
A = \(\dfrac{1352}{75}\)
B = \(\dfrac{24\times36+24\times64}{12\times135-12\times35}\)
B = \(\dfrac{24\times(36+64)}{12\times(135-35)}\)
B = \(\dfrac{24\times100}{12\times100}\)
B = 2
a) 27 × 10 = 270; 72 × 100 = 7200; 14 × 1000 = 14000
86 × 10 = 860; 103 × 10 = 10300; 452 × 1000 = 452000
358 × 10 = 3580; 1977 × 100 = 197700; 300 × 1000 = 300000
b) 80 :10 = 8; 400 : 100 = 4 ;6000 : 1000 = 6
300 : 10 = 30; 4000 : 100 = 40 ; 60000 : 1000 = 60
2000 :10 = 200; 40000 :100 = 400 ;600000 : 1000 = 600
c) 64 × 10 = 640; 32 × 100 = 3200; 95 × 1000 = 95000
640 : 10 = 64; 3200 : 100 = 32; 95000 : 1000 = 95
a) 172 + 10 x 2 = 170 +20 = 192
b) 10 x 2 + 300 = 20 + 300 = 320
c) 69 – 54 : 6 = 69 – 9 = 60
d) 900 + 9 x 10 = 900 +90 = 990
e) 20 x 6 + 70 = 120 + 70 = 190
f) 72 + 300 x 3 = 72 + 900 = 972
Học sinh nhẩm và ghi kết quả như sau:
a) 400 + 300 = 700
700 – 300 = 400
700 – 400 = 300
b) 500 + 40 = 540
540 – 40 = 500
540 – 500 = 40
c) 100 + 20 + 4 = 124
300 + 60 + 7 = 367
800 + 10 + 5 = 815
a) 400 + 300 = 700
700 – 300 = 400
700 – 400 = 300
b) 500 + 40 =540
540 – 40 =500
540 – 500 =40
c) 100 + 20 + 4 =124
300 + 60 + 7 =367
800 + 10 + 5 =815
Ta có: \(\left\{{}\begin{matrix}x-y=10\\\dfrac{300}{y}-\dfrac{300}{x}=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=10+y\\\dfrac{300}{y}-\dfrac{300}{10+y}=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=10+y\\\dfrac{300\left(y+10\right)}{y\left(y+10\right)}-\dfrac{300y}{y\left(y+10\right)}=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=10+y\\300y+3000-300y=y\left(y+10\right)\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=10+y\\y^2+10y-3000=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=10+y\\y^2+10y+25-3025=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=10+y\\\left(y+5\right)^2=3025\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\left[{}\begin{matrix}x=y+10\\x=y+10\end{matrix}\right.\\\left[{}\begin{matrix}y+5=55\\y+5=-55\end{matrix}\right.\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\left[{}\begin{matrix}x=50+10=60\\x=-60+10=-50\end{matrix}\right.\\\left[{}\begin{matrix}y=50\\y=-60\end{matrix}\right.\end{matrix}\right.\)
Vậy: Hệ phương trình có hai cặp nghiệm là (x,y)\(\in\){(-50;-60);(60;50)}
`a)2^{300}=(2^3)^100=8^100`
`3^200=(3^2)^100=9^100`
Vì `9^100>8^100`
`=>2^300<3^200`
`b)3xx24^10`
`=3.(3.8)^10`
`=3^{11}.8^10`
`=3^{11}.2^30`
`2^300=2^{30}.2^{270}`
`=2^{30}.8^{90}`
Vì `3^11<8^90`
`=>3^{11}.2^30<8^{90}.2^30=2^300`
`=>3xx24^{10}<2^300+3^20+4^30`
300+10=310
tk cho mk nhé mk nhanh nhất đó. mk năn nỉ đó.
310 k mk nha
huc ban hoc gioi