|x-5|+19=20
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Không cần cảm ơn chị nhé chị đang học lớp 5 hi hi
x = 1/10
19/20 - x = 17/20
x = 19/20 - 17/20
x = 2/20
x = 1/10
19/20-x=8/5-3/4
19/20 -x = 17/20
x = 19/20 - 17/20
x = 2/20
x = 1/10
x+2/5=1/2
x = 1/2 - 2/5
x = 1/10
x+3/7=2/5+3/10
x + 3/7 = 7/10
x = 7/10 - 3/7
x = 19/70
19/20-x=8/5-3/4
19/20 - x = 17/20
x = 19/20 - 17/20
x = 1/10
\(\dfrac{x+1}{1}+\dfrac{2x+3}{3}+\dfrac{3x+5}{5}+...+\dfrac{10x+19}{19}=12+\dfrac{4}{3}+\dfrac{6}{5}+...+\dfrac{20}{19}\)
\(x+1+\dfrac{2x}{3}+1+\dfrac{3x}{5}+1+...+\dfrac{10x}{19}+1-12-\dfrac{4}{3}-\dfrac{6}{5}-...-\dfrac{20}{19}=0\)
\(x+\dfrac{2x}{3}-\dfrac{4}{3}+\dfrac{3x}{5}-\dfrac{6}{5}+...+\dfrac{10x}{19}-\dfrac{20}{19}+10-12=0\)
\(x-2+\dfrac{2x-4}{3}+\dfrac{3x-6}{5}+...+\dfrac{10x-20}{19}=0\)
\(x-2+\dfrac{2\left(x-2\right)}{3}+\dfrac{3\left(x-2\right)}{5}+...+\dfrac{10\left(x-2\right)}{19}=0\)
\(\left(x-2\right)\left(\dfrac{2}{3}+\dfrac{3}{5}+...+\dfrac{10}{19}\right)=0\)
Ta thấy \(\left(\dfrac{2}{3}+\dfrac{3}{5}+...+\dfrac{10}{19}\right)>0\)
\(\Rightarrow x-2=0\Rightarrow x=2\)
|x - 5| + 19 = 20
|x -5 | = 20 - 19
| x - 5| = 1
\(\left[{}\begin{matrix}x-5=1\\x-5=-1\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=6\\x=4\end{matrix}\right.\)
\(x\in\) { 4; 6}
\(|x-5|=1\)
\(\left\{{}\begin{matrix}x-5=1\\x-5=-1\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x=6\\x=4\end{matrix}\right.\)