tìm x:
a).x+4/5=3/2
b).x-3/2=11/4
c).25/3-x=5/6
ai nhanh và làm đủ các bước mình sẽ tick 2 cái
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a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)
\(x+\frac{2}{5}=\frac{-7}{20}\)
\(x=\frac{-13}{20}\)
Vậy \(x=\frac{-13}{20}\)
b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)
\(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x=\frac{15}{8}\)
\(x=\frac{-15}{4}\)
Vậy \(x=\frac{-15}{4}\)
Chị gái xinh đẹp à. Câu hỏi của chị khó quá ko ai trả lời. Thôi thì.......k cho mem đi😉
a) \(\left(x-3\right)^2-4=0\)
\(\left(x-7\right)\left(x+1\right)=0\)
\(\orbr{\begin{cases}x=7\\x=-1\end{cases}}\)
b) \(x^2-2x=24\)
\(x^2-2x-24=0\)
\(\left(x-6\right)\left(x+4\right)=0\)
\(\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)
c) \(\left(2x-1\right)^2+\left(x+3\right)^2-5\left(x+7\right)\left(x-7\right)=0\)
\(4x^2+4x+1+x^2+6x+9-5\left(x^2-49\right)=0\)
\(5x^2+10x+10-5x^2+245=0\)
\(10x+255=0\)
\(x=-25.5\)
A) \(\left(x-3\right)^2-4=0\)
\(\left(x-3\right)^2=4\Rightarrow\left(x-3\right)^2=\left(-2\right)^2;2^2\)
th1\(\left(x-3\right)^2=2^2\)
\(\Rightarrow x-3=2\)
\(\Rightarrow x=2+3\)
\(\Rightarrow x=5\)
th2: \(\left(x-3\right)^2=\left(-2\right)^2\)
\(\Rightarrow x-3=-2\)
\(\Rightarrow x=-2+3\)
\(\Rightarrow x=1\)
\(\Leftrightarrow x\in\left\{1;5\right\}\)
a) \(\left(\frac{1}{3}+\frac{1}{5}\right)\times x=\frac{8}{25}\)
\(\frac{8}{15}\times x=\frac{8}{25}\)
\(x=\frac{8}{25}:\frac{8}{15}\)
\(x=\frac{3}{5}\)
Vậy x = 3/5
b) \(\frac{1}{2}:\frac{4}{5}:x=\frac{7}{3}\)
\(\frac{5}{8}:x=\frac{7}{3}\)
\(x=\frac{5}{8}:\frac{7}{3}\)
\(x=\frac{15}{56}\)
Vậy x = 15/36
ủng hộ tớ nha. thank you nhìu
a) (1/3 + 1/5) . x = 8/25
(5/15 + 3/15) . x = 8/25
=> 8/15 . x = 8/25
x = 8/25 : 8/15
x = 3/5
Vậy x = 3/5
a) \(x=\frac{7}{25}+\frac{-1}{5}\)
\(\Rightarrow x=\frac{2}{25}\)
Vậy \(x=\frac{2}{25}\)
b) \(x=\frac{5}{11}+\frac{4}{-9}\)
\(\Rightarrow x=\frac{1}{99}\)
Vậy \(x=\frac{1}{99}\)
c) \(\frac{5}{9}+x=\frac{-1}{3}\)
\(\Rightarrow x=\frac{-1}{3}-\frac{5}{9}\)
\(\Rightarrow x=\frac{-8}{9}\)
Vậy \(x=\frac{-8}{9}\)
d) \(\frac{3}{4}-x=-1\)
\(\Rightarrow x=\frac{3}{4}-\left(-1\right)\)
\(\Rightarrow x=\frac{7}{4}\)
Vậy \(x=\frac{7}{4}\)
e) \(x+4=\frac{1}{5}\)
\(\Rightarrow x=\frac{1}{5}-4\)
\(\Rightarrow x=\frac{-19}{5}\)
Vậy \(x=\frac{-19}{5}\)
f) \(x-\frac{1}{5}=2\)
\(\Rightarrow x=2+\frac{1}{5}\)
\(\Rightarrow x=\frac{11}{5}\)
Vậy \(x=\frac{11}{5}\)
g) \(x+\frac{5}{3}=\frac{1}{81}\)
\(\Rightarrow x=\frac{1}{81}-\frac{5}{3}\)
\(\Rightarrow x=\frac{-134}{81}\)
Vậy \(x=\frac{-134}{81}\)
_Chúc bạn học tốt_
a) \(x+\frac{4}{5}=\frac{3}{2}\)
\(\Rightarrow x=\frac{3}{2}-\frac{4}{5}\)
\(\Rightarrow x=\frac{7}{10}\)
Vậy \(x=\frac{7}{10}.\)
b) \(x-\frac{3}{2}=\frac{11}{4}\)
\(\Rightarrow x=\frac{11}{4}+\frac{3}{2}\)
\(\Rightarrow x=\frac{17}{4}\)
Vậy \(x=\frac{17}{4}.\)
c) \(\frac{25}{3-x}=\frac{5}{6}\)
\(\Rightarrow\left(3-x\right)5=25.6\)
\(\Rightarrow15-5x=150\)
\(\Rightarrow5x=15-150\)
\(\Rightarrow5x=-135\)
\(\Rightarrow x=-135:5\)
\(\Rightarrow x=-27\)
Vậy \(x=-27.\)
ai giúp mình câu c đi