Tìm X biết 9/10-x=1/3
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Từ đề bài=>(x+1)/10+(x+2)/9+(x+3)/8-(-3)=0
<=>......................................(như trên)+3=0
<=>(x+1)/10+1+(x+2)/9+1+(x+3)/8+1=0( vì 1+1+1=3)
<=>(x+1+10)/10+(x+2+9)/9+(x+3+8)/8=0
<=>(x+11)/10+(x+11)/9+(x+11)/8=0
<=>(x+11).(1/10+1/9+1/8)=0
Mà 1/10<1/9<1/8
=>1/10+1/9+1/8 khác 0
<=>x+11=0<=>x=-11
Vậy x=-11
( x+1) + (x+2) +( x+3) +...+( x+9)+(x+10) = 85
\(x+1+x+2+x+3+...+x+9+x+10=85\)
\(10\times x+\left(1+2+3+...+9+10\right)=85\)
\(10\times x+\left[\left(1+10\right)\times10:2\right]=85\)
\(10\times x+55=85\)
\(10\times x=85-55\)
\(10\times x=30\)
\(x=30:10\)
\(x=3\)
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + .......... + ( x + 9 ) + ( x + 10) = 85
x . 10 + ( 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 ) = 85
x . 10 + 55 = 85
x . 10 = 85 - 55
x . 10 = 30
x = 30 : 10
x = 3
Vậy x = 3
Bài 1:
a) \(x.\dfrac{3}{4}=\dfrac{9}{14}\)
\(\Rightarrow x=\dfrac{9}{14}:\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{6}{7}\)
b) \(x:\dfrac{5}{9}=\dfrac{3}{10}\)
\(\Rightarrow x=\dfrac{3}{10}.\dfrac{5}{9}\)
\(\Rightarrow x=\dfrac{1}{6}\)
khoan cach giua 2 so la :2-1=1
co tat ca so so hang hay x la :(10-1):1+1=10
(x+1)+(x+2)+.....................(x+10)=2015
x*10+[(1+10)*10/2]=2015
x*10+55 =2015
x*10 =2015-55
x*10 =1960
x =1960/10
x =196
\(a,\left(x-3\right)\left(x^2+3x+9\right)+x\left(x+2\right)\left(2-x\right)=0\\ \Rightarrow\left(x^3-27\right)+x\left(4-x^2\right)=0\\ \Rightarrow x^3-27+4x-x^3=0\\ \Rightarrow4x-27=0\\ \Rightarrow4x=27\\ \Rightarrow x=\dfrac{27}{4}\)
\(b,\left(x+1\right)^3-\left(x-1\right)^3-6\left(x-1\right)^2=-10\\ \Rightarrow\left(x^3+3x^2+3x+1\right)-\left(x^3-3x^2+3x-1\right)-6\left(x^2-2x+1\right)=-10\\ \Rightarrow x^3+3x^2+3x+1-x^3+3x^2-3x+1-6x^2+12x-6+10=0\)
\(\Rightarrow12x+6=0\\ \Rightarrow12x=-6\\ \Rightarrow x=-\dfrac{1}{2}\)
\(\frac{9}{10}-x=\frac{1}{3}\)
\(x=\frac{9}{10}-\frac{1}{3}\)
\(x=\frac{27}{30}-\frac{10}{30}\)
\(x=\frac{17}{30}\)
Vậy \(x=\frac{17}{30}\)
9/10-x=1/3
x =9/10-1/3
x =17/30