tính bằng cách thuận tiện
a, 12/25 + 3/5 + 13/25
b, 3/2 + 2/3 + 4/3
c,3/5 + 7/5 + 3/4
giúp mình với nha!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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\(1,\dfrac{12}{25}+\dfrac{3}{5}+\dfrac{13}{25}=\left(\dfrac{12}{25}+\dfrac{13}{25}\right)+\dfrac{3}{5}=1+\dfrac{3}{5}=\dfrac{8}{5}\\ 2,\dfrac{3}{2}+\dfrac{2}{3}+\dfrac{4}{3}=\dfrac{3}{2}+\left(\dfrac{2}{3}+\dfrac{4}{3}\right)=\dfrac{3}{2}+2=\dfrac{7}{2}\\ 3,\dfrac{3}{2}+\dfrac{7}{5}+\dfrac{3}{4}=\left(\dfrac{3}{2}+\dfrac{3}{4}\right)+\dfrac{7}{5}=\left(\dfrac{6}{4}+\dfrac{3}{4}\right)+\dfrac{7}{5}=\dfrac{9}{4}+\dfrac{7}{5}=\dfrac{45}{20}+\dfrac{28}{20}=\dfrac{73}{20}\)
a) \(\dfrac{5}{9}+\dfrac{13}{7}+\dfrac{15}{13}+\dfrac{8}{7}+\dfrac{4}{9}+\dfrac{11}{13}\)
\(=\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\left(\dfrac{13}{7}+\dfrac{8}{7}\right)+\left(\dfrac{15}{13}+\dfrac{11}{13}\right)\)
\(=1+3+2\)
\(=6\)
b) \(\dfrac{3}{5}+\dfrac{18}{9}+\dfrac{4}{10}\)
\(=0,6+2+0,4\)
\(=\left(0,6+0,4\right)+2\)
\(=1+2\)
\(=3\)
\(a\dfrac{5}{9}+\dfrac{4}{9}+\dfrac{13}{7}+\dfrac{8}{7}+\dfrac{15}{13}+\dfrac{11}{13}=\dfrac{9}{9}+\dfrac{21}{7}+\dfrac{26}{13}=1+3+2=6\)
\(a,\frac{12}{25}+\frac{3}{5}+\frac{13}{25}\)
\(=\left(\frac{12}{25}+\frac{13}{25}\right)+\frac{3}{5}\)
\(=\frac{25}{25}+\frac{3}{5}\)
\(=1+\frac{3}{5}\)
\(=\frac{8}{5}\)
\(b,\frac{3}{2}+\frac{2}{3}+\frac{4}{3}\)
\(=\frac{3}{2}+\left(\frac{2}{3}+\frac{4}{3}\right)\)
\(=\frac{3}{2}+2\)
\(=\frac{7}{2}\)
\(c,\frac{3}{5}+\frac{7}{5}+\frac{3}{4}\)
\(=\left(\frac{3}{5}+\frac{7}{5}\right)+\frac{3}{4}\)
\(=2+\frac{3}{4}\)
\(=\frac{11}{4}\)
a. 12/25 + 3 / 5+ 13/25 = ( 12/25+13/25)+3/5 = 1 + 3/5= 8/5
b. 3/2 + 2/3 + 4/3 = 3/2+( 2/3+4/3)= 3/2 + 2=7/2
c.3/5+7/5+3/4= (3/5+7/5)+3/4 = 2+ 3/4=11/4
chúc bn hc tốt
a. 12/25+3/5+13/25
=1+3/5
=8/5
b.3/2+2/3+4/3
=3/2+2
=7/2
c.3/5+7/5+3/4
=2+3/4
=11/4
a: \(=\left(15-6-\dfrac{13}{18}\right):\dfrac{298}{27}-\dfrac{17}{8}:\dfrac{51}{40}\)
\(=\dfrac{149}{18}\cdot\dfrac{27}{298}-\dfrac{5}{3}=\dfrac{3}{2}-\dfrac{5}{3}=\dfrac{9-10}{6}=\dfrac{-1}{6}\)
b: \(=\dfrac{-16}{5}\cdot\dfrac{-15}{64}+\dfrac{-22}{15}:\dfrac{11}{2}\)
\(=\dfrac{3}{4}-\dfrac{4}{15}=\dfrac{29}{60}\)
c: \(=\dfrac{-7}{9}\left(\dfrac{4}{11}+\dfrac{7}{11}\right)+5+\dfrac{7}{9}=\dfrac{-7}{9}+\dfrac{7}{9}+5=5\)
d: \(=\dfrac{1}{2}\cdot\dfrac{4}{3}\cdot10\cdot\dfrac{1}{5}\cdot\dfrac{3}{4}=1\)
e: \(=\dfrac{4}{25}+\dfrac{11}{2}\cdot\dfrac{5}{2}+\dfrac{-23}{4}=\dfrac{204}{25}\)
`a: =(7/3-4/3)+11/5=16/5`
`b: =(18/13-5/13)+55/46=1+55/46=101/46`
`c: =27/25-4/9-2/25+5/9=(27/25-2/25)+(5/9-4/9)=1+1/9=10/9`
dễ!nhưng giải mất thời gian lên mình không giải đâu!!!
\(a,\frac{12}{25}+\frac{3}{5}+\frac{13}{25}\)
\(=\left(\frac{12}{25}+\frac{13}{25}\right)+\frac{3}{5}\)
\(=1+\frac{3}{5}\)
\(=\frac{8}{5}\)
\(b,\frac{3}{2}+\frac{2}{3}+\frac{4}{3}\)
\(=\frac{3}{2}+\left(\frac{2}{3}+\frac{4}{3}\right)\)
\(=\frac{2}{3}+2\)
\(=\frac{8}{3}\)
\(c,\frac{3}{5}+\frac{7}{5}+\frac{3}{4}\)
\(=\left(\frac{3}{5}+\frac{7}{5}\right)+\frac{3}{4}\)
\(=2+\frac{3}{4}\)
\(=\frac{11}{4}\)