0.98 x 1,04 x (0,75 - 3/4) +145 : 0,01 = ?
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a) Ta có: \(\dfrac{x}{-15}=\dfrac{-60}{x}\)
\(\Leftrightarrow x^2=\left(-15\right)\cdot\left(-60\right)=900\)
hay \(x\in\left\{30;-30\right\}\)
Vậy: \(x\in\left\{30;-30\right\}\)
b) Ta có: \(\left|x\right|+0.573=2\)
\(\Leftrightarrow\left|x\right|=1.427\)
hay \(x\in\left\{1.427;-1.427\right\}\)
Vậy: \(x\in\left\{1.427;-1.427\right\}\)
c) Ta có: \(\left|x+\dfrac{1}{3}\right|-4=-1\)
\(\Leftrightarrow\left|x+\dfrac{1}{3}\right|=3\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=3\\x+\dfrac{1}{3}=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=-\dfrac{10}{3}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{8}{3};-\dfrac{10}{3}\right\}\)
d) Ta có: \(0.01:2.5=\left(0.75x\right):0.75\)
\(\Leftrightarrow\dfrac{0.75\cdot x}{0.75}=\dfrac{0.01}{2.5}\)
\(\Leftrightarrow x=\dfrac{1}{250}\)
Vậy: \(x=\dfrac{1}{250}\)
a: =472x2+472x5+472x2=472x9=4248
b: =28,8+28,8-14,4=43,2
c: =2,4(6,2+3,8)=24
0,01 : 2,5 = ( 0,75 . x ) : ( 0,75)
0,004 = ( 0,75 . x ) : ( 0,75)
( 0,75 . x ) = 0,004 x 0,75
( 0,75 . x ) = 0,003
x = 0,003 : 0,75
x = 0,004
= 0,35x100+0,75x(12-3:\(\dfrac{1}{4}\)) +65
=35+0,75x(12-3x4)+65
=35+65+0,75x0
=100
a)
x - 7,84 = 4,16
x = 4,16 + 7,84
x = 12
b)
(x + 1/4) : 0,01 - (0,75 x 4) = 60
(x + 1/4) : 0,01 - 3 = 60
(x + 1/4) : 0,01 = 63
(x+ 1/4) = 0,63
x = 19/50
a) 0,01 : 25 = ( 0,75 . x ) : 0,75
\(\Rightarrow\frac{1}{2500}=0,75\cdot x:0,75\)
\(\Rightarrow x=\frac{1}{2500}\)
b) \(\left(3,8\right):\left(2x\right)=\frac{1}{4}:\frac{8}{3}\)
\(\Rightarrow3,8:\left(2x\right)=\frac{3}{32}\)
\(\Rightarrow2x=3,8:\frac{3}{32}=\frac{608}{15}\)
\(\Rightarrow x=\frac{608}{15}:2=\frac{304}{15}\)
=0.98x1,04x[0,75-0,75]+145:0,01
=0.98x1,04x 0 +145:0,01
= 0 +145:0,01
= 0 + 14500
= 14500