Tìm x:
x : 23 = 103 X x 101 - x = 5200
x : 76 = 235 23 X x + 77 X x = 2500
cái X lớn là dấu x còn cái nhỏ là nhân
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a) 5.(x-20) = 35
(x-20) = 35:5
x-20 = 7
x = 27
b) (x+125) -301 = 56
x+125 -301 = 56
x - 176 = 56
x = 56 +176
x= 232
c) 215 + (x-21):2 = 235
(x-21):2 = 235 - 215
(x-21):2 = 20
x-21 = 20 .2
x-21 = 40
x = 61
d) (x:23 +45) .67 = 8911
(x:23 +45) = 8911 : 67
x:23+45 = 133
x:23 = 133-45
x:23 = 88
x = 88.23
x = 2024
a) 5.(x - 20) = 35
⇒ x - 20 = 35 : 5
⇒ x - 20 = 7
⇒ x = 7 + 20
⇒ x = 27
b) (x + 125) - 301 = 56
⇒ x + 125 = 56 + 301
⇒ x + 125 = 357
⇒ x = 357 - 125
⇒ x = 232
c) 215 + (x - 21) : 2 = 235
⇒ (x - 21) : 2 = 235 - 215
⇒ (x - 21) : 2 = 20
⇒ x - 21 = 20 x 2
⇒ x - 21 = 40
⇒ x = 21 + 40
⇒ x = 61
d) (x : 23 + 45).67 = 8911
⇒ x : 23 + 45 = 8911 : 67
⇒ x : 23 + 45 = 133
⇒ x : 23 = 133 - 45
⇒ x : 23 = 88
⇒ x = 88 x 23
⇒ x = 2024
x+12=23
x =23-12
x =11
23-x=12
x=23-12
x=11
x-34=76
x =76+34
x =100
x + 12 = 23
x = 23 - 12
x = 11
23 - x = 12
x = 23 - 12
x = 11
x - 34 = 76
x = 76 + 34
x = 110
Kb với mình nhé !
^ Chúc bn học tốt ^
a. 100 - 7 ( x - 5 ) = 58
<=> 7 ( x - 5 ) = 100 - 58
<=> 7 ( x - 5 ) = 42
<=> x - 5 = 42 : 7
<=> x - 5 = 6
<=> x = 6 + 5
<=> x = 11
Tương tự tiếp.
a;100-7(x-5)=58
=>7(x-5)=100-58=42
=>x-5=42:7=6
=>x=6+5=11
b;12(x-1):3=72
=>12(x-1)=72.3=216
=>x-1=216:12=18
=>x=18+1=19
c;12-4(x-1)=4
=>4(x-1)=12-4=8
=>x-1=8:4=2
=>x=2+1=3
d;32-12x=8
=>12x=32-8=24
=>x=24:12=2
nho h do nhe viet moi tay lam day biet ko
=> x + 4 = 0 => x = -4
hoặc 23 - x =0 => x = 23
Vậy x = -4 ; x = 23
=> x+4 = 0 hoặc 23-x = 0
x = 0-4 hoặc x = 23-0
x = 4 hoặc x = 23
\(\frac{74-x}{26}+\frac{75-x}{25}+\frac{76-x}{24}+\frac{77-x}{23}+\frac{78-x}{22}=-5\)
\(\frac{74-x}{26}+1+\frac{75-x}{25}+1+\frac{76-x}{24}+1+\frac{77-x}{23}+1+\frac{78-x}{22}=-5+5\)
\(\frac{74-x}{26}+\frac{26}{26}+\frac{75-x}{25}+\frac{25}{25}+\frac{76-x}{24}+\frac{24}{24}+\frac{77-x}{23}+\frac{23}{23}+\frac{78-x}{22}+\frac{22}{22}=0\)
\(\frac{100-x}{26}+\frac{100-x}{25}+\frac{100-x}{24}+\frac{100-x}{23}+\frac{100-x}{22}=0\)
\(\left(100-x\right)\left(\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{23}+\frac{1}{22}\right)=0\)
=>100-x=0 ( \(\left(\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{23}+\frac{1}{22}\right)\ne0\))
x=100
hahaha
Sửa đề: \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)Ta có: \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)
\(\Leftrightarrow\dfrac{74-x}{26}+1+\dfrac{75-x}{25}+1+\dfrac{76-x}{24}+1+\dfrac{77-x}{23}+1+\dfrac{78-x}{22}+1=0\)
\(\Leftrightarrow\dfrac{100-x}{26}+\dfrac{100-x}{25}+\dfrac{100-x}{24}+\dfrac{100-x}{23}+\dfrac{100-x}{22}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\right)=0\)
mà \(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}>0\)
nên 100-x=0
hay x=100
Vậy: S={100}
Ta có : \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)
\(\Leftrightarrow\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}+5=0\)
\(\Leftrightarrow\dfrac{74-x}{26}+1+\dfrac{75-x}{25}+1+\dfrac{76-x}{24}+1+\dfrac{77-x}{23}+1+\dfrac{78-x}{22}+1=0\)
\(\Leftrightarrow\dfrac{100-x}{26}+\dfrac{100-x}{25}+\dfrac{100-x}{24}+\dfrac{100-x}{23}+\dfrac{100-x}{22}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\right)=0\)
Thấy : \(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\ne0\)
\(\Rightarrow100-x=0\)
\(\Leftrightarrow x=100\)
Vậy ...
a) \(x:23=103\)
\(x=103\times23\)
\(x=2369\)
b) \(x:76=235\)
\(x=235\times76\)
\(x=17860\)
c) \(x\times101-x=5200\)
\(x\times101-x\times1=5200\)
\(x\times\left(101-1\right)=5200\)
\(x\times100=5200\)
\(x=5200:100\)
\(x=52\)
d) Xem lại đề bài í d) nhéee
câu 1 là 515